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Oribe Yasuna
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Homework Statement
A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by
E vector =
The charges making up the dipole are q1 = +6 nC and q2 = -6 nC and the dipole separation is s = 4 mm (see figure below). What is the potential difference along a path starting at location P1 =
Homework Equations
delta V = - integral of i -> f (E vector * delta L vector)
The Attempt at a Solution
delta V = 2qs/4πε0 ( 1/P2^3 - 1/P1^3 ) * 0.04
delta V = 9e+9 * 2(6e-9)(0.004) * ( 1/(0.06)^3 - 1/(0.02)^3 ) * 0.04
delta V = -2.08e+3
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