Recent content by paulie

I think, I'm just missing another 6' in the computation of volume in the liquid. That "6ft square" means (6)^2 and not 6ft^2. (I assumed that 6ft^2 is the area). I got around 9990 lbs at the end. Although still not sure how can I use the atmospheric pressure on the problem...

It was not stated, there's no figure too provided by the book. :( The answer is provided around 10000

Homework Statement A pyramid weighing 4000 lb has a base 6ft square and an altitude of 4ft. The base covers an opening in the floor of a tank in which there is water 4 ft deep. Underneath the floor of the tank and on the water surface there is air at atmospheric pressure. What vertical force is...

Homework Statement Given that we have q1 = -4nC on the y-axis at y=0.60m. q2 on the y-axis at y= -1.20m. What must be the sign and magnitude of q2 be for the net electric field at the origin to be: a. Zero b. 50 N/C Homework Equations E=KQ/R2 The Attempt at a Solution I used: ET = E1 + E2...

Homework Statement Two positive point charges, A and B are 6m apart. The electric field intensity at point C, midway between the two charges is 5 N/C directed towards B and the potential at the same point is 45V. Find the magnitude of A and the magnitude of B. Homework Equations E = kQ/r2 The...

Homework Statement A furnace is constructed with 0.5 m of fire brick, 0.15 m of insulating brick and 0.25 m of ordinary building brick. The inside surface-temperature is 1530K and the outside surface temperature is 525K. The thermal conductivities of the fire, insulating and building bricks are...

Homework Statement Given a copper calorimeter that has a mass of 446 grams containing 95 grams of ice at 0.0°C. If 35 grams of steam at 100.0°C and 1.00 atm pressure is added to the can, what is the final temperature of the can and its contents? At the final temperature, how many kilograms are...

That was what I was thinking but it bothered me that it was the only answer that didn't exactly gave the exact value from the answer sheet. Thanks for the help guys.

@rl.bhat I tried using volume and linear but I arrived with a bigger value. @mjc123 Tried to make both linear and I arrived with Δt = - 58.7521 C° which is pretty good, finding the final temperature I got 11.2473 °C although the given correct answer is 11.2766 °C. I'll try to recompute later...

Homework Statement Find the common temperature at which the inner diameter of the ring is 0.05% larger than the diameter of the sphere. Given: Lead sphere d = 5cm To = 70°C ∝ = 29x10-6/C° Steel ring d = 4.9975cm (the sphere is 0.05% larger than the inner diameter of the ring, hence this value)...

Thanks for you help! :)

Did you get 2.9994 ft for the length? My solution paper gives that value, it seems I typed it incorrectly. Tried checking using linear expansion/contraction and it gives the same value, never knew I can use this to check.

Homework Statement A rectangular windshield is to be assembled by installing a glass plate on a 3 ft by 1 ft frame at 60°C. The glass plate is cut at 68°F in such a way that its length is three times its width. The linear expansivity of glass is 5 x 10-6 /C°. (a) What area of the glass plate at...