Recent content by physics newb

No, I haven't. That's why I'm here. What do I do?

How should you graph the function y = (5/x^2) -3 so that it looks linear? Can you explain your reasoning?

A barge with mass 1.50 X 10^5 kg is proceeding downriver at 6.2 m/s in heavy fog when it collides with a barge heading directly across the river (see the poorly drawn image, in link)http://img.photobucket.com/albums/v638/ravenatic20/untitled4.jpg ... The second barge has mass 2.78 X 10^5 kg and...

A 300 g ball with a speed v of 6.0 m/s strikes a wall at an angle of 30 degrees, and then rebounds with the same speed and angle. It is in contact with the wall for 10 ms. (a) What is the impulse on the ball from the wall? (b) What is the average force on the wall from the wall? What...

The car's momentum is 1600*1.2 kg-km/hr? That being 1920. What would the units be? Now my momentum is 80*Vu kg-km/hr where Vu is your velocity? Where do I go from here?

Suppose that your mass is 80 kg. How fast would you have to run to have the same translational momentum as a 1600 kg car moving at 1.2 km/h? I happen to know the answer is 24 km/hr. But, how do I get to this answer? What are the steps? Could someone solve it out and show me how they got it...

I know, but I need to solve this problem. What do I do?

http://img.photobucket.com/albums/v638/ravenatic20/cablecars.jpg Like my MS Paint skills? haha The image shows a section of an alpine cable-car system. The maximum permissible mass of each car with occupants is 2800 kg. The cars, riding on a support cable, are pulled by a second cable...

Luggage is transported from one location to another in an airport by a conveyor belt. At a certain location, the belt moves down an incline that makes an angle of 2.5 degrees with the horizontal. Assume that with such a slight angle there is no slipping of the luggage. Determine the magnitude...

OK, but I still don't know the initial velocity. If I did your equation, would it look like this? x=u(1.00)+1/2(9.8m/s^2)1.00^2 ?

Time is not my luxury here. What is the next thing I do?

What does the u stand for in your eqation? How can I get a (acceleration) solved?

Is the firefighter's actual weight the force of gravity that acts on him, 712 N? I happen to know the answer is 494 N up, and 494 N down. Now, how do I get to this answer?

v^2 = v_0^2 + 2 a \Delta x Would this be it?

Anyone have ideas to get me started. I'm not sure what to do next.