Recent content by r-swald

1.6x10^-19? I used that number and it worked. I was also using the wrong number for n, it was given as the total number of charged particles within the block and then divided by the volume was the n I was looking for. I'd also converted cm to m incorrectly, but it all worked out in the end :)...

I don't get it. Ok so I'm trying to find the drift speed of the electrons, I use this by dividing current (.167) by ne • A. You used cross-sectional area in your derivation so I'd use that, but I'm not sure what the factor of e is so I tried the packing density I found by dividing the "n" you...

Ok, so Vd = I / nA is there a difference between n and ne? I'm still not sure how to find the area to plug into this equation

Right, negative distance isn't possible, they'd only cancel if the charges were opposite. Thank you!

I've found I to be .167 using the potential and resistance. I also found the volume by multiplying the cross-sectional area by the length (?) and then dividing the # of conducting electrons into that to find packing density (n). To find drift speed, I would also need the area of the block as...

Ah, okay I mixed up change in and sum of. I tried this again and I must be thinking screwy b'c the final KE I figured to be 0 since V final would be approaching 0, and the final PE I figured to be 0 since r final would approach infinity. I also ended up with 0 initial PE b'c the top and bottom...

Below is the work I've attempted. I used 2 PE b'c there were 2 point charges, and only one KE b'c only the proton is moving. The final equation in case it's hard to see is V(esc) = sqrt (4kQq / mr). I'm not sure if I did it right. Did I set up this equation right? and I am also not sure what...

Thanks for the replies, pretty sure I got it. I was just missing the V = -Ed (had it in an odd location on formula sheet) and the constant E-field. 👍

I first attempted to use kinematics, but to find acceleration I would need to find the force either by finding the e-field first and multiplying it with q, or just kQq / r^2. However, I was not given second charge or surface charge density. Is there another way I could go about making the...

Oh yeah, it was a sign problem. Thank you!

Yeah so the second one I'm still getting wrong, it's probably something just as silly 🤔 F2 = F13 - F23 = (9E9*61.42E-6*6.6E-6 / .03^2) - (9E9*1.42E-6*2.04E-6 / .02^2) I'm getting 28.54 for this and still saying I'm 10% off.

Awesome! got it. I didn't even think about that, now I Just have to figure out what I did wrong with the other one

I attempted this a few times but keep getting the same wrong answer... Converted the values: q1 = 6.6E-6 q2 = 1.42E-6 q3 = -2.04E-6 d1 = .03m d2 = .02m Calculation for force on 1 F1 = - F12 + F13 = - (9E9*6.6E-6*1.42E-6 / .03^2) + (9E9*6.6E-6*2.04E-6 / .02^2) (I used negative for F12 to...