Recent content by rob1985

I think that is beyond my capability

P = ((Vs * Vr) /X)* sinδ Q = Vr/X * (Vs*cosδ - Vr) These would be the equations your referring to I hope. How I work that into the question I've got, I don't know

So the only equation I can think that will help is Q =(Va-Vb)/X Q = (11KV- 3.2MVA)/4.6

That is what the lesson information gives when tackling a similar question, ill be honest I am not sure of the equations, that is something I have not covered during the lessons

Homework Statement Hi guys, I was just wondering if anybody could help me with the below question Homework EquationsThe Attempt at a Solution Radial Total load = 3.2 /_-36.87deg + 2.3 /_ 53.13deg =(2.56 - j1.92) +(1.38 +j1.84) = (3.94 -j0.08)...

to be honest I am really not sure, I suspect it is zero as there is no load so the magnetic field of the rotor is the same as the stator. am I on the right tracks

hi all, Just a quick question, what would the load angle be of a synchronous motor when running at no load. would it be 0 degrees or 45 degrees

So how do I estimate what the losses are, is there a formula I can use

Hi I was wondering if someone could tell me the equation for finding out what the windage and friction losses are based on the information below. I've drawn the graph and I can work out the I/0, R0 and X0A four-pole, star-connected, squirrel-cage induction motor operates froma variable voltage...

Hi justadaftspark, how did you work out the friction and windage losses. the lessons don't show me the equation.

So for a) what does it mean when it says draw the laplace form of the input portion of the circuit as represented in figure 4C. I've had no look in finding anything to do with this in my lesson notes.

Does anybody have any updates regarding this post, I am not even sure where to begin. The lessons from uni do not give any suggestion on what the question is after.

So part b) find I by nodal analysis So I have the following V1/Z1 - V20/Z1 - V20/Z4 + V3/Z5 - V20/Z5 + V2/Z3 - V20/Z3 + V3/Z3 = 0 (V1 - V20)/Z1 + -V20/Z4 + (-V20-V3)/Z5 - V2 - (V20 - V3)/Z3 = 0 (V1 - V20)/Z1 - V20/Z4 + (V3 - V20)/Z5 + (V2 - V20 + V3/Z3 = 0 -V20 ( 1/Z1 + 1/Z4 + 1/Z5 + 1/Z3)...

Thanks gneill, I've sorted my maths out now. i1 = 16.811946 + j -22.879203 i2 = 25.963628 + j -40.154424 i3 = 18.059026 + j -22.095398 So i = (i1 - i2) (16.811946 + j -22.879203) - (25.963628 + j -40.154424) = -9.151682 + j17.275221 This is by mesh analysis, now for nodal analysis lol

Right so once I've got rid of the exponential sign the results come out as followed. i1 = 4.566713472 + j -6.224865387 i2 = 7.067532754 + j -10.92749295 i3 = 4.92009011 + j -6.007402841 So i1 - i2 to find i = (4.566713472 + j -6.224865387) - (7.067532754 + j -10.92749295) So i = 2.500819282 +...