Recent content by ScrubsFan

Oh sweet! Thanks.

91. Write balanced equations to show the formation of each of the following compounds. Name the reactants in each case, and show clearly the removal of the water molecule. a) butyl propanoate b) propyl methanoate Answers: a) butyl propanoate- C[SIZE="1"]7H[SIZE="1"]14O[SIZE="1"]2 =...

Alright I fixed part b), is it right now? MgF[SIZE="1"]2 <---> Mg2+ (aq) + 2F- (aq) Ksp = [Mg2+][F-]2 [Mg2+] = 2.7 x 10[SIZE="1"]-3 [F-] = 2 x 2.7 x 10[SIZE="1"]-3 Ksp = (2.7 x 10[SIZE="1"]-3)(5.4 x 10[SIZE="1"]-3) = 1.5 x 10[SIZE="1"]-5

70. The solubility product of calcium hydroxide, Ca(OH)2, is 7.9 x 10[SIZE="1"]-6 at 25°C. Will a precipitate form when 100mL of 0.10 mol/L of CaCl2 solution and 50.0mL of 0.070 mol/L of NaOH solution are combined? Solution 1. Determine the formula for the possible precipitate that might...

69. Calculate the Ksp for each of the salts whose solubility is listed below. a) CaSO[SIZE="1"]4 = 3.3 x 10-3 mol/L b) MgF[SIZE="1"]2 = 2.7 x 10-3 mol/L Answers: a) Solution 1. Write the dissociation reaction and the Ksp expression for the equilibrium reaction. Thus...

Consider the following reaction A(g) <---> 2B(g) + C(g) When 1.00 mol of A is placed in a 4.00L container at temperature t, the concentration of C at equilibrium is 0.050 mol/L. What is the equilibrium constant for the reaction at temperature t? Here is my answer: The balanced...

Yes I have seen and read about activation energy, and the only thing I could think of for this problem is that the activation of the forward reaction is given as 135 kJ/mol. 135 kJ/mol + 14.2 kJ/mol = 149.2 kJ/mol So the activation energy for the reverse reaction would be 149.2 kJ/mol?

53. For the reaction CO + NO[SIZE="1"]2 ---> CO[SIZE="1"]2 + NO The activation energy for the forward reaction is 135 KJ/mol of CO reacted. a) Determine the heat of reaction. DH = Hf products - Hf reactants = (197.9 + 240.5) - (213.6 + 210.6) = 14.2 kJ/mol b) From the data...

Write balanced equations to show the formation of each of the following compounds. Name the reactants in each case, and show clearly the removal of the water molecule. a) butyl propanoate b) propyl methanoate Im not exactly sure how to answer this question... below are pics of the...

Name the following substances. a) [Cu(Cl[SIZE="1"]4]2- - tetrachloridecopper(II) ion b) Ag(NH[SIZE="1"]3)2+ - diamminesilver ion c) Cu(NH[SIZE="1"]3)[SIZE="1"]4SO[SIZE="1"]4 - tetraamminecoppersulfate (or tetraamminecopper(II) sulfate) d)...

I already drew them and they did not line up properly when I posted my reponse, so I attached the pictures; and yes you can still click on them and they will show up, even though it says pending approval.

No, what I wrote was correct in that it is reacting, although I meant to put HCl not Cl[SIZE="1"]2. Below is what is shows in my textbook. 2-butene + HCl(g) ---> 2-chlorobutene I tried making them in the window but looked weird, view the pics and it shows the structure of each, but I...

When 2-butene reacts with hydrogen chloride gas, only one product is detected, whereas when 1-butene reacts similarly, two products are usually found. Explain this. I know that when 2-butene reacts with hydrogen chloride that the bond breaks and the Cl[SIZE="1"]2 adds on one atom to each...

Awsome, thank you for your comments.

The digestion of some foods, such as red meat, releases the urate ion C[SIZE="1"]5H[SIZE="1"]3N[SIZE="1"]4O[SIZE="1"]3- into the bloodstream. An excess of urate in the blood can result in the formation of sodium urate crystals in joints and tissues. This leads to a painful form of arthritis...