Recent content by sudera

Oh, this makes a lot of sense, I get it now. Thanks a lot for elaborating on the analogy!

If it's independent of the distance, then why is the electric field not constant? @Orodruin said it was, in fact, constant and zero, but the electric field in the link I shared and in the picture of the original post isn't zero in the "triangle".

Well, I came across this when learning about diodes, so a slab would be more accurate. However, my textbook solves for the electric field using the equation ##\dfrac{dE}{dx} = \dfrac{\lambda}{\epsilon_0}##, and so does this site in section 4.3.3...

I think I understand what you meant now. But the question here is the electric field IN or ALONG the line of charge, not perpendicular to it.

What about the electric field "triangle" in the picture then? Perhaps I am interpreting it wrong.

But in case of an infinite surface, the electric field is constant perpendicular to the surface, whereas here it is declining. So I don't really understand what you mean.

This is not really homework, but I'm having trouble understanding it intuitively. I came across this when learning about the space charge layer of a diode. The solution I know simply uses the 1D form of Gauss's law: ##\vec{\nabla} \cdot \vec{E}## = ##\dfrac{\rho}{\epsilon_0}## becomes...

Hi, I use ##v_2(t)## only to denote the voltage over the inductor, not the entire circuit.

Would this system look something like this? ##v_1(t) = L_1 \dfrac{di_1}{dt} - M\dfrac{di_2}{dt}## ##v_2(t) = M \dfrac{di_1}{dt} - L_2\dfrac{di_2}{dt}## Can I use ##i_1(t)=at## and ##i_2(t)=0## or is this not allowed because the current becomes different from the original current supply because...

Since the induced emf of the second circuit is a constant, the current will also be constant, and thus will not create a changing magnetic flux through the first circuit and will not change the current in the first circuit, so the power in the first circuit is unaffected while the power in the...

This is more like a theoretical question of my own than actual homework. Say there is a circuit with a current source and an inductor. There is a current ##i(t)=at## going through the inductor. We now place a new circuit with an inductor and a resistor next to it. The current ##i(t)## causes a...

Oh, I see. Thank you so much for your elaborate help and your patience! I really appreciate you walking me through the problem step by step.

The equations give ##f = 300 N## and ##T = 400 N##. The maximum static frictional force is ##\mu_s n = \mu_s m g = 392.4 N## so it rolls without slipping. I'm just wondering now what I'd have to do if the maximum was less than 300 N. The acceleration of the contact point of the yo-yo on the...

##\tau_c = -T r + f R = \dfrac{a_c}{R-r}## ##m a = T - f = m \alpha r## I don't know if I should include the belt's acceleration (in the form of ## + m a_C## on the left-hand side) as a force. Does an accelerating surface count as a force? I feel like it should, but on the other hand, if you...

##\tau_C = I_C \alpha##, where ##I = 200 kg \cdot m^2## is the moment of inertia around the center and ##\tau_C## the torque on the center. ##\alpha = \dfrac{a_C}{R-r}## so the magnitude of the torque needed is ##200 \dfrac{a_C}{R-r}##. I'm not sure what this implies for the frictional force...