Recent content by SwaGGeReR

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    Partial Derivatives of Power Functions

    Got it. Thanks!
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    Partial Derivatives of Power Functions

    Thanks slider. I originally thought that ln(abx)=xln(ab), but apparently that's not true. Yet ln(ax)=xln(a). Why is this so?
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    Partial Derivatives of Power Functions

    To differentiate y=ax I would use logarithmic differentiation. 1) Take the ln of both sides: ln(y)=ln(ax) 2) Using properties of logs, this equals: ln(y)=x*ln(a) 3) Differentiating each side: y'/y=ln(a) 4) Solving for y': y'=y*ln(a) 5) Substituting for y: y'=ax*ln(a) The...
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    Partial Derivatives of Power Functions

    For a function such as w=5xy/z How would you find the partial derivative of w with respect to y or z? I've tried using basic logarithmic differentiation, but can't arrive at the correct answer. For reference, the correct answer is wy=5*(xy/z/z)*ln(x)
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    Probability Syntax: Types 1, 2 & 3 Defects

    A certain system can experience three different types of defects. Let A[i] (i=1,2,3) denote the event that the system has a defect of type i. Suppose that P(A[1]) =.12 P(A[2])=.07 P(A[3])=.05 P(A[1] union A[2])=.13 P(A[1] union A[3])=.14 P(A[2] union A[3])=.10 P(A[1] intersects A[2]...
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    How can I plot a 3D vertical plane in Mathematica?

    I'm trying to plot something like x+y=2 in 3D. The image should look like this: Been trying to do it in Mathematica using Plot3D, but the it treats the input as a function of z. Another example: Plot3D[x=4,{x,0,10},{y,0,10},AxesLabel{x,y,z}] plots z=4, not x=4. A similar thread, with no...
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