How can I plot a 3D vertical plane in Mathematica?

[SwaGGeReR]

I'm trying to plot something like x+y=2 in 3D. The image should look like this:

Been trying to do it in Mathematica using Plot3D, but the it treats the input as a function of z.

Another example: Plot3D[x=4,{x,0,10},{y,0,10},AxesLabel{x,y,z}] plots z=4, not x=4.

A similar thread, with no conclusive answer: https://www.physicsforums.com/showthread.php?t=101840

 

[chiro]

I'm trying to plot something like x+y=2 in 3D. The image should look like this:

Been trying to do it in Mathematica using Plot3D, but the it treats the input as a function of z.

Another example: Plot3D[x=4,{x,0,10},{y,0,10},AxesLabel{x,y,z}] plots z=4, not x=4.

A similar thread, with no conclusive answer: https://www.physicsforums.com/showthread.php?t=101840

Hey SwaGGeReR and welcome to the forums.

Have you looked at the documentation?

Also what do the arguments mean for the function? What does {x,0,10} refer to? Are they just bounds for the variables?

The other thing is what is the default coordinate system for Mathematica? Is it RHS? LHS? Does the z-axis point up? (In many math programs it does and in many maths courses they treat z as pointed up and not in or out of the page).

 

[LCKurtz]

I'm not familiar with Mathematica but maybe it is like Maple. Can you plot surfaces as parametric plots? If so, you could use the parameterization:

x = x
y = 2 - x
z = z
$\vec R(x,z) =\langle x, 2-x,z\rangle$ and plot it using whatever syntax Mathematica requires.