Recent content by Tjvelcro

Sorry for the late reply... Oh ok that makes sense there are many factors that could be effecting the potential for the datarate to reach that high. I will probably explain that in my work. Any idea about 802.11b which uses CCK (Complementary code keying) what M value to use? Thanks...

Hi all, I need some help finding the thoeretical data rates for 802.11 a, b, g, n standards. I think I should use the following equation... C = 2Blog2M C = data rate in bps, B = channel bandwidth in hz, M = # of voltage levels or # signal elements For instance I look up the channel...

No, I am not sure what that equation is... tried to look in my book but cannot find it.

Homework Statement What is the expected power of the first three frequency components of a square wave with an amplitude of 0.2V? Homework Equations None that I know of :( The Attempt at a Solution I'm not sure where to start with this since it seems to give me so little...

Homework Statement A frequency band from 76 MHz to 86 MHz is available for wireless transmission. Design a frequency division multiplexing system with 2 MHz wide channels and 2 MHz guard bands (assume that guard bands aren’t necessary at the lower and upper ends of the band). Indicate...

Homework Statement Hi all! I seem to be having trouble doing integration by parts. I seem to have a pretty clear picture of the steps I need to do but something seems to always trick me. Usually I would ask my prof but she is away for a week. I use the formula: uv - ∫vdu = given...

So for the second problem Differentiate g(x)= x^2(ln(2x)) I used product rule. g'(x) = 2x(ln(2x)) + (x^2)(2/2x) g'(x) = 2x(ln(2x)) + (x) This is where I made my mistake, I get confused with y'lnx=1/x and y'[lng(x)] = g'(x)/g(x) Thanks Tjvelcro

Homework Statement 1. Differentiate g(x)= ln(x(x^2 - 1)^1/2 2. Differentiate g(x)= x^2(ln(2x)) Homework Equations Law of logs and product rule The Attempt at a Solution 1. I simplified to g'(x) = 1/x + (1/2)(1/(X^2 - 1)(2x) then g'(x) = 1/x + 2x/(2(x^2 - 1)) Answer however...

So f(4)=3 as given in the question... f'(4)=1/4 since 1/4 is the slope of the tangent line at point (4,3)? Thanks for the help! Test this Thursday!

a. so I use y – y1 = m(x – x1) sub in (5, -3) for the point and 4 for the slope? Solve for y. So y-(-3)=4(x-5) y=4x-23 b. I would use m=(y2-y1)/(x2-x1) to find the slope as you suggest. m=(3-2)/(4-0) m=1/4 Now I need to find f(4) and f'(4) I need to find the equation first as I did...

Homework Statement a. Find the equation of the tangent line to the graph of y=g(x) at x = 5 if g(5) = -3 and g'(5) = 4 b. If the tangent line to y = f(x) at (4,3) passes through the point (0,2), find f(4) and f'(4) Homework Equations y=mx =b f(a+h)-f(a) h y – y1 = m(x – x1) The...

Homework Statement Which is 2s complement of 0x3D9E a) BD9F b) BDA0 c) C262 d) 3D9E Homework Equations I believe I subract each digit from F The Attempt at a Solution FFFF -3D9E ______ C261 Someone in my class said the answer was c) but do I still add one? I...

Nevermind, I was not using my calculator correctly. Brackets are very helpful :p

Homework Statement A long pair of wires conducts 20.2 (amps) od dc current to, and from, an instrument. The wires are 23mm apart, what is the magnetic field 9.7cm from their midpoint in their plane? Homework Equations B=(µo/2pi)*(I/d) The Attempt at a Solution µo = 4pix10^-7...

Current = charge / time I = q / t Solve for the unknown q q=I*t Then I can use Q=CV right? Plug in Q and V and solve for C. C= Q / V This seems to make sense...