RC time constant lab, Current vs time

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Homework Help Overview

The discussion revolves around a lab experiment involving a simple RC circuit where participants are tasked with analyzing a current vs. time graph of a capacitor charging and discharging. The goal is to determine the RC time constant and calculate the capacitance from the experimental data, comparing it to a provided value.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between current and time in the context of the circuit, with one suggesting the use of the equation I = q/t to find charge. Others question the applicability of this approach given the non-constant nature of current.

Discussion Status

The discussion is ongoing, with participants exploring different equations that relate current to charge and time. Some guidance has been offered regarding the need for an exponential relationship in the context of charging and discharging capacitors, but no consensus has been reached on the best approach to calculate capacitance from the graph data.

Contextual Notes

Participants are working with specific known values for resistance and capacitance provided by the professor, and there is a focus on using experimental data to derive capacitance, which may involve assumptions about the behavior of the circuit.

Tjvelcro
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Homework Statement



In my lab we where given a simple circuit and told to get some data of a capacitor charging and discharging. Thus I now have a graph of current vs time, we used semi-log paper for this so the graph would be a straight line.

We are given the value of the resistor and capacitor from the professor.

We are now asked to find the RC time constant of both charge the discharge, then find the C of our capacitor from our data and compare it with the given value from our professor.

Knowns:
R=(0.94x10^6)ohms
C=(62x10^-6) farads
I=(11x10^-6) amps
Our lab asked us to turn up the voltage until we got 11uA therefore I can use ohms law to find my voltage using V=IR
V=(11x10^-6)*(0.94x10^6) = 10.34V

Homework Equations



V=IR
Q=CV
T=RC

The Attempt at a Solution



I know one value of C simply because my professor gave it to me.
Given C = (62x10^-6) farads

Now I must use the data I recorded to calculate C. This is where I'm stuck, I have a current vs time graph but cannot see how to get a C value with it and can't find the RC time constant of my data.

Tjvelcro
 
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What equation relates current to time, for your circuit? It is necessary to know that, in order to proceed.
 
Current = charge / time
I = q / t
Solve for the unknown q

q=I*t
Then I can use Q=CV right?
Plug in Q and V and solve for C.

C= Q / V

This seems to make sense...
 
Last edited:
Tjvelcro said:
Current = charge / time
I = q / t

This would work if I were constant, but it isn't constant.

The actual the relation is
I = dQ/dt

At any rate, you should have an equation something like
I = I0e-t/t0
in your textbook or class notes. That is the one you would need to use.
 

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