Recent content by utkarsh009

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    Solve Gauss' Law Homework: Charge of Insulating Sphere & Conductor Shell

    This Q is actually the charge on the outer surface (d) . For inner surface (c), it will be negative of the charge on solid sphere. Add both of these to get the net charge. That will be the answer to (b)
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    Calculating Wave Speeds of Steel Guitar Strings

    v=√(T/¢) T= tension in wire ¢= mass per unit length
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    Solve Gauss' Law Homework: Charge of Insulating Sphere & Conductor Shell

    Go ahead and use it. See if you can get the answer. (∫E.dS=q/ε(o)) or you could simply use the formula you mentioned it in relevant equations. I'm not supposed to spoonfeed you. Check the answer in your textbook.
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    Solve Gauss' Law Homework: Charge of Insulating Sphere & Conductor Shell

    Assume that the solid sphere and induced charges are not present at all (since the have no effect). Only a spherical conductor is present with charge on its outer surface.
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    Solve Gauss' Law Homework: Charge of Insulating Sphere & Conductor Shell

    Your answer to b part is wrong. There will be induced charge on the inner surface of the shell so that the field due to solid sphere and induced charge is 0 everywhere outside it. So the field at 50 cm is only due to the charge on outer surface. Use it to calculate net charge on shell.
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    Show that Euler-Mascheroni sequence is decreasing &monotonic

    What if you integrate it from n to n+1? Also can you think of the area of rectangle formed with height 1/(n+1) and width (n+1)-n? Just compare them on the graph of f(x)=1/x
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    Lagrange's mean value theorem problem

    Yah... Was just thinking the same and was about to post it... :P
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    Lagrange's mean value theorem problem

    But your h(x) had solved the problem. What was the error??
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    Lagrange's mean value theorem problem

    Thanks mate! Solved it... But how did you think of that function h(x)??
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    Lagrange's mean value theorem problem

    Homework Statement Homework Equations Lagrange's mean value theorem The Attempt at a Solution Applying LMVT, There exists c belonging to (0,1) which satisfies f'(c) = f(1)-f(0)/1 = -f(0) But this gets me nowhere close to the options... :(
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    Integrating a Definite Integral with Trigonometric Functions

    Oh yah... Thanks ... I solved it... But have a look at this file... I couldn't get an answer for this...
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    Integrating a Definite Integral with Trigonometric Functions

    Oh yes... By mistake i typed the integration symbol after it. Cosec a should be inside the integral. So, how should i proceed??
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    Integrating a Definite Integral with Trigonometric Functions

    Homework Statement ∫dt/(t^2 +2tcos a + 1) (Limits of the integral are from 0 to 1) (0<a<π) Homework EquationsThe Attempt at a Solution Put t=sin a dt=cosa da ∫dt/(t^2 +2tcos a + 1) = ∫cos a da/(sin^2 a + sin 2a + 1) [ limits of integration changed to 0 to π/2] = ((cosec a)/2) ∫sin 2a da/(sin^2...
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    Does the colour of light change with a change in medium

    Thanks! www.physicsforums.com/showthread.php?t=459065 this thread also helped me. Thanks for giving the link.
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    Lens maker's equation used correctly?

    @Danny :the equation which you are using seems to be derived from thin lens equation where you neglect thickness as it's too small compared to Radii of curvature.
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