The discussion focuses on calculating the ratio of wave speeds (VA / VB) for two steel guitar strings with different diameters and tensions. String A has a diameter of 0.50 mm and is under 410.0 N of tension, while String B has a diameter of 1.0 mm and is under 820.0 N of tension. The relevant formula for wave speed in a string is V = √(T/μ), where T is tension and μ is mass per unit length. The participants emphasize the need to relate wave speed to tension and mass per unit length to solve the problem effectively.
PREREQUISITESPhysics students, music instrument makers, and anyone interested in the mechanics of sound in strings will benefit from this discussion.
Amongst your standard equations, you should have one that relates wave speed in a string/wire to tension and mass per unit length.Ignis Radiis said:Homework Statement
Two steel guitar strings have the same length. String A has a diameter of 0.50 mm and is under 410.0 N of tension. String B has a diameter of 1.0 mm and is under a tension of 820.0 N. Find the ration of the wave speeds, VA / VB
in these two strings.
Homework Equations
V= ƒ λ
FT = FG
The Attempt at a Solution
I'm lost on where to start...
v=√(T/¢)Ignis Radiis said:Homework Statement
Two steel guitar strings have the same length. String A has a diameter of 0.50 mm and is under 410.0 N of tension. String B has a diameter of 1.0 mm and is under a tension of 820.0 N. Find the ration of the wave speeds, VA / VB
in these two strings.
Homework Equations
V= ƒ λ
FT = FG
The Attempt at a Solution
I'm lost on where to start...