Homework Statement
Homework Equations
The Attempt at a Solution
I let µ be 9, as that's the approximate permittivity of air/ free space.
I assumed that as a hat had a subscript y, it ran parallel to the y axis, and worked from there, getting the cross product of the unit...
I think I worked this out, would appreciate if someone could confirm my answer.
500pC = 500x10^-12 C
Potential at a point = Kₑ (q/r)
applied these and got:
Va = 9x10^-12
Vb = 3x10^-10
Potential difference between a and b = |Va - Vb|
=> 2.91x10^-10
Homework Statement
Homework Equations
V=IR ?
The Attempt at a Solution
My main problem with this question is that impedance seems to apply only when inductors and capacitors are involved, but this circuit includes only resistors, so it seems to me like I could just treat it as resistance...
r1 and r2 are distances from the origin, right? But what is V? also, is E the electric field, which is F/q? If so, I would need q, the charge at each point, wouldn't I? but you said I didn't.
Homework Statement
Given a point charge of 500pC at the origin, find the potential difference between points a and b at distances 5m and 15m respectively along the x-axis.
Homework Equations
Coulomb's law, I think?
The Attempt at a Solution
The reason I thought coulombs law was relevant...