Potential difference between two points problem

AI Thread Summary
To find the potential difference between two points due to a point charge of 500pC, the relevant formula for electric potential is V = Kₑ(q/r), where Kₑ is Coulomb's constant. The potential at points a (5m) and b (15m) can be calculated using this formula, leading to the potential values Va and Vb. The potential difference is then determined by the equation |Va - Vb|. A participant initially struggled with the calculations but later realized an error in using the correct value for Kₑ. The discussion emphasizes the importance of understanding electrostatic potential and correctly applying the relevant formulas.
wheybags
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Homework Statement



Given a point charge of 500pC at the origin, find the potential difference between points a and b at distances 5m and 15m respectively along the x-axis.

Homework Equations



Coulomb's law, I think?

The Attempt at a Solution



The reason I thought coulombs law was relevant was because it was mentioned in the first part of the equation. I tried to apply Coulomb's law, but got nowhere, as I don't have a charge for a and b, and also, I think that would ignore the charge at the origin, so it was probably the wrong way to go about it. To be honest, it just doesn't seem to me like there is enough information given to do anything with it, really.
All help gratefully received.
 
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Have you learned anything called as electrostatic potential??
If not, read some book and grab an idea of it. It will help you to understand the problem!
 
Yes, please do look in your physics textbook, in the section or chapter on electric potential.

You are looking for the potential (or voltage) of a point charge -- there should be a formula for this.
 
I looked, but couldn't find anything really. Wouldn't I need to know the charge at a and b to do anything?
 
wheybags said:
I looked, but couldn't find anything really. Wouldn't I need to know the charge at a and b to do anything?

It's a point charge, so no.

Change in electric potential is defined as [V(\mathbf{r_2})-V(\mathbf{r_1})] = -\int_{\mathbf{r_1}}^{\mathbf{r_2}} \!\!\! \mathbf{E} \cdot d\mathbf{r}

What is the electric field for a point charge?
 
r1 and r2 are distances from the origin, right? But what is V? also, is E the electric field, which is F/q? If so, I would need q, the charge at each point, wouldn't I? but you said I didn't.
 
I think I worked this out, would appreciate if someone could confirm my answer.

500pC = 500x10^-12 C
Potential at a point = Kₑ (q/r)
applied these and got:
Va = 9x10^-12
Vb = 3x10^-10
Potential difference between a and b = |Va - Vb|
=> 2.91x10^-10
 
You're formula and procedure are correct, but your calculations of Va and Vb are wrong. Are you using Ke = 9.0x10^9?
 
Oh god, I'm an idiot. I was using Ke = 9...
 
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