Hi all, i often help out in the chemistry section, was wondering if you could help me with a question:
A vessel of thermal capacity 500 J/oC contains 0.5 kg of water at 50oC.
0.2 kg of water at 20oC is added and perfectly mixed with the hotter water.
In this process, heat is lost by the...
Hi there,
\mathrm{K_c} = \frac{\mathrm{[HBr]^2}}{\mathrm{[H_2] \cdot [Br_2]}}
Where i = initial and f = final
[H2init--][Br2init]--[2HBr2init]
[0.340--][0.220 ]--[2---x---]
[H2Fin--]Br2Fin ]--[2HBr2fin]
[0.1396 ][0.0196]--[2---x--]
/_\ = 0.2004
So 2HBr = 2 x /_\ = 2 x 0.2004...
Question one:
“How many grams of Mg(OH)2 (2 is a subscript) will be needed to neutralize
25ml of stomach acid if stomach acid is 0.10 M HCl?”
Display reaction equation (balanced) (Step 1)
Mg(OH)2+2HCl-->MgCl2+2H2O
1 to 2 ratio:
25ml of 0.10 M (INITIAL CONCENTRATION BEFORE...
CH4+ 202 --> 2H2O + CO2
CH4 = 100g
2O2 = 100g
Mr of substances (one mole weighs):
CH4 = 16.043g
O2 = 31.999 so 2O2 = 63.998
H2O = 18.015 so 2H2O = 63.030
CO2 = 44.010.
Now calculate number of moles:
Number of moles = Mr / w (w = mass of substance)
CH4 = 100 /...
Yes it is possible and does happen, just browse yahoo and look up "superacids", you can easily have a negative pH of -1. And there are NO limits for a pH value.
Wolfson.
Do you know the pH scale?
The pH of potassium cyanide will 7,
No 7 is netrul, 7+ = basic, 7- = acidic.
The pH of potassium cyanide will be = 11 (0.1 N aqueous solution). Use 11.
pH of sodium methanoate = 8-9.5
Methylammonium chloride = 8 (0.1N)
Would appreciate anyhelp to solving any of these questions ty.
1 A diffraction grating of pitch 3 .27mm is illuminated at normal incidence with
light comprised of various wavelengths. If components of wavelength
495nm, 625nm and 990nm are present find:-
a) the angular positions of the...
Hello i have been able to do 7 out of 8 question on my linear motion questions, but this last question number 8, is proving difficult. I don't know whether the tutor has made a mistake (as the answers are typed at the bottom) so if you could be of help i would be very glad ty.
I am using s =...