Recent content by zandbera

Okay yeah for (b) I did what I thought, I used E = 9.60 x 10^3, then multiplied by +e, divided by mass of proton to get a, then used delta x = Vi t + 1/2 a t^2 with Vi = 0, and i got 5.68 mm, the correct answer. So then for (c), the horizontal component is just the initial horizontal velocity...

(b) From the equation and my given data, is qE = 9.60 x 10^3 N/C or is it just E = 9.60 x 10^3? If it's E = 9.60 x 10^3, I would just multiply by (+e) to get qE and then divide by the mass of a proton, right?

Yeah that's where the problem was. If I use # of electrons = 1.8 x 10^28, then take 1% of that, then multiply that by 1.602 x 10^-19 to convert to Coulombs, square that value, multiply by k, divide by r^2 (r = .85 m) and i get 1.03 x 10^25Thanks!

Homework Statement A proton moves at 4.50 x 108 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.60 x 103 N/C. Ignoring any gravitational effects, find (a) the time interval required for the proton to move 5.00 cm horizontally, (b) its vertical...

Yeah okay I was thinking about that and that makes sense. And yeah I misunderstood the question. I thought they meant each person was an arms length away so the total distance between them was 2 arms lengths so i used 2(0.75) and 2(1.0) With that info, I got 6.10 x 10^61. Which is way too high

Homework Statement Nobel laureate Richard Feynman once said that if 2 persons stood at arm's length from each other and each person had 1% more electrons than protons, the force of repulsion between them would be enough to lift a "weight" equal to that of the entire Earth. Carry out an...

so then because 2(4/6)^n is convergent, the original series is convergent, correct?

Homework Statement I have to determine whether the given series is convergent or divergent using the comparison tests: \sum from n = 1 to infinity of (n + 4n / (n + 6n) Homework Equations If bn is convergent and an \leq bn then an is also convergent liimit of an/bn as n goes to...

thank you i got it now. one question though: how do you know to multiply the ratios? as far as i understand, it gives you the efficiency for Qc2 / Qh1 so that would be like the energy input from the first engine to the energy output of the second engine so it would be the efficiency for the...

assuming that Qc1 = Qh2, e1 = 1 - Qc1/Qh1 e2 = 1 - Qc2/Qc1 Qc1/Qh1 = e1 - 1 Qc2/Qc1 = e2 - 1 multiplying them, i get e1e2 - e1 - e2, which is -1 times the answer I am trying to show. why is this?

Homework Statement Suppose you build a two-engine device with the exhaust energy output from one heat engine supplying the input energy for a second heat engine. We say that the two engines are running in series. Let e1 and e2 represent the efficiencies of the two engines. (a) The overall...

Ohhhhh okay I think I get it now. Thanks

Which is equal to the ratio of the final and initial pressures?

well for an adiabatic expansion i know that PiVi^y = PfVf^y where y = cp/cv, but i don't know the final and initial volumes so how does that help?

haha hey, yeah i found another site that had a bit of an explanation to it, but it didn't have c) or d) to it. thanks