Cos^2(x) Integral: Get Help Solving

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Homework Help Overview

The discussion revolves around the integral of cos²(x), specifically the expression ∫cos²(x) dx. Participants are exploring the use of trigonometric identities to simplify the integral and are attempting to integrate the resulting expression.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the identity cos²(x) = (1 + cos(2x))/2 but expresses confusion about its utility. Other participants suggest breaking the integral into simpler parts and discuss the potential for substitution methods. Questions about the integration of cos(2x) and the correctness of the resulting expressions are raised.

Discussion Status

Participants are actively engaging with the problem, offering insights and suggestions for approaches. There is a recognition of the need for substitution in the integration process, and some participants express uncertainty about the correctness of their results, indicating a productive exploration of the topic.

Contextual Notes

There is mention of a potential oversight regarding the inclusion of a constant of integration, which reflects the common challenges faced in integral calculus. The discussion also highlights the importance of verifying results against expected answers.

iRaid
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Homework Statement


\int cos^{2}x dx

I know that

cos^{2}x = \frac{1+cos2x}{2}

but I don't see how that helps me.
Can someone help walk me through it..

Homework Equations


The Attempt at a Solution

 
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Well, that leaves you with:
\int \frac{1}{2}+\frac{1}{2}cos(2x)dx

Which you can break up into two integrals:
\int \frac{1}{2}dx + \int \frac{1}{2}cos(2x)dx

The first one should be no problem. Isn't there some sort of substitution you can make for the second one?
 
Can you integrate cos(2x)? Use a u substitution.
 
u=2x du=(1/2)dx
(1/2)∫cosudu
=(1/4)sin2x

So then..
x/2 + (1/4)sin2x
but that's not the answer..
 
Last edited:
iRaid said:
u=2x du=(1/2)dx
(1/2)∫cosudu
=(1/4)sin2x

So then..
x/2 + (1/4)sin2x
but that's not the answer..

I think it is the correct answer. You should probably put a +C on it. Is that the problem?
 
Dick said:
I think it is the correct answer. You should probably put a +C on it. Is that the problem?

Oh nevermind was looking at the wrong answer. Thanks for the help.
 

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