How Do You Calculate Final Temperatures in an Adiabatically Isolated Cylinder?

AI Thread Summary
In an adiabatically isolated cylinder divided by a partition, two moles of monatomic ideal gas are initially at different temperatures: 523 K on the left and 287 K on the right. When the partition moves quasi-statically, the pressures equalize, leading to a change in temperature on both sides. The relationship between pressure and volume during an adiabatic process is crucial for calculating the final temperatures. The relevant equation for work done in this scenario is W = (3/2)nRT, but additional variables are needed for a complete solution. Understanding these principles is essential for determining the final temperatures on both sides of the partition.
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Homework Statement


The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partition. Both sides contain one mole of a monatomic ideal gas (), with the initial temperature being 523 K on the left and 287 K on the right. The partition is then allowed to move slowly (i.e. quasi-statically) to the right, until the pressures on each side of the partition are the same. Find the final temperatures on the (a) left and (b) right sides.

http://edugen.wiley.com/edugen/courses/crs1507/art/qb/qu/c15/ch15p_92.gif


Homework Equations


I think that for this kind of problem i need to use W=3/2nRT, however I am not given any of the other variables so i am lost.


The Attempt at a Solution

 
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adiabatic condition

How do pressure and volume relate during an adiabatic process? Look it up!
 

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