Understand the two doubly degenerate mode of D4h symmetry

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The discussion focuses on the properties of the PtCl4 complex, specifically its charge and the multiplicity of platinum within the context of D4h symmetry. The charge of PtCl4 is confirmed to be -2, as it is commonly recognized as the [PtCl4]2- ion. The multiplicity of platinum in this ion is identified as 1, indicating a closed-shell singlet ground state. Additionally, there is an inquiry about the vibrational characteristics of the two doubly degenerate Eu modes associated with the complex, highlighting a need for further understanding of their vibrational behavior.
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Hello all,
This is not a homework problem. Just to understand the two doubly degenerate mode of D4h symmetry i wanted to make sample calculation. Pt in the middle of a square formed by 4 Cl atoms. PtCl4 has square planar structure (AB4) molecule.
1. What is the whole charge of PtCl4 ? Is this -2 ?
2. Multiplicity of Pt ? Multiplicity = [2S+1] where S is spin state of Pt.
thanks.
 
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That would naturally depend on which oxidation state of platinum you're interested in. But since the [PtCl4]2- ion is well-known, I'm assuming that's the one you want. It has a closed-shell singlet ground-state.
 


Hello,
So multiplicity is 1? please give the number!
Because nobody knows about the vibrational picture of the partners of the two degenerate Eu modes. I need to find how it vibrates.
 
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