Considering a short parabolic impulse as direct current?

AI Thread Summary
A short parabolic impulse of one polarity cannot be treated as direct current in a circuit due to the nature of reflections, which require changes in signal value over time. Ordinary formulas for reflections are not applicable to DC analysis. Instead, the discussion emphasizes the importance of considering the impulse response of the circuit. This can be achieved through direct measurement or by analyzing the frequency response and applying a Fourier Transform. Understanding these concepts is crucial for accurately analyzing voltage waves in such scenarios.
freddyfish
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Is it possible to consider a short (20ns) impuls of only one polarity as a short segment of direct current in a simple circuit where the reflections are to be analyzed? If not, how should I treat this kind of voltage waves?

The voltage is obviously not constant, but I wonder if it is possible to use ordinary formulas for reflections etc.

Thanks
 
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You can't discuss reflections in terms of DC. The essential point about a reflection is that there is a change, in time, in value of the signal - i.e. it's there because of non-DC components of the signal.
You need to be thinking in terms of the Impulse Response of your circuit, which you can obtain either directly or by measuring the frequency response (including phase information) and then a Fourier Transform.
 
Thank you very much! Very good answer. :)
 

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