Viscosity of Fluid Mixtures: Calculating Pa.s

  • Thread starter Thread starter flash
  • Start date Start date
  • Tags Tags
    Viscosity
AI Thread Summary
To calculate the viscosity of a fluid mixture, a weighted average can be used if the fluids are well mixed. For example, combining a fluid with a viscosity of 1 Pa.s and water with a viscosity of 0.89 × 10^-3 Pa.s in a 1:9 ratio can yield a new viscosity through this method. This approach is generally acceptable for Newtonian fluids, as there are no significant deviations expected in their behavior. While some users express uncertainty about the accuracy of this method, it is considered reasonably reliable for practical applications. Understanding the principles of viscosity in mixtures is essential for experiments involving different fluid concentrations.
flash
Messages
66
Reaction score
0
Hi,
I have a question about the viscosity of fluids: If I know the viscosity of one fluid, say 1 Pa.s, and I add a portion of water (say for example 1 part water to 9 parts fluid), viscosity 0.89 × 10^-3 Pa.s, what is the viscosity of the new mixture? I have done an experiment for school where we mixed corn syrup with water in different concentrations (90%, 80%, etc) and need to work out the viscosity of each mixture.
Thanks!
 
Physics news on Phys.org
Is there any reason you wouldn't be able to do a weighted average? I'd imagine that, if the two fluids are well mixed, you could just use that method.
 
Thanks for the reply. I think I know what you mean. Are you sure that's an ok way to do it?
 
For Newtonian fluids I think it's fine; to be honest, I've never come across a situation where I've had to do that, but I can't think of a reason off the top of my head that it wouldn't be at least reasonably accurate.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top