Calculator inverse tangent problem

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Homework Statement


Suppose that a wind is blowing from the direction N45ºW at a speed of 50 km/h. A pilot is steering a plane in the direction N60ºE at an airspeed of 250 km/h. Find the true course (direction) and ground speed (magnitude) of the plane.

Homework Equations



The Attempt at a Solution



The resultant vector will be in an upward direction in the second quadrant, right? I determined that the resultant vector
v = <25(√2) - 125(√3), 25(√2) + 125>

I am trying to find the angle that the plane is flying.
tan θ = [25(√2) + 125]/[25(√2) - 125(√3)]
Using inverse tangent and my calculator, I got an angle around -41.5 degrees.
If the resultant vector is in the second quadrant, this is wrong. I remember that the calculator sometimes will not work for inverse tangent, but I can't remember when, or what to do to fix it.

Please help.
 
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Use your trig identities. What is \tan(\theta+180^\circ)?
 
The same thing...I was thinking I had to add something. I couldn't remember what though. Thanks
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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