Intiutive approach to Green's function for SE

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Griffiths develops an intelgral equation for Scrödinger equation in his QM book. As doing so, he requires Green's function for Helmholtz equation

<br /> (k^2 + \nabla^2) G( \mathbf r) = \delta^3(\mathbf r)<br />

A rigourious series of steps, including Fourier transforms and residue integrals follow immidiately. As it turns out, the Green's function is independent of direction of \mathbf r, i.e. G(\mathbf r) = G(r). Does anyone know a trick deducing this condition without actually finding the Green's function. The importance to prove is that, it turns out that there's a relatively simple solution if we assume G(\mathbf r) = G(r))
 
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This simpler form of the GF is caused by a space-invariance of the potential.
 
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