Difference between Fermions and Bosons in Feynman diagrams

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What distinguishes Fermions form Bosons in Feynman diagrams?
 
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Fermions are usually drawn with solid lines and bosons are usually drawn with dashed or wavy lines.
 
I was hoping for a more physical answer.
 
Could you rephrase the question? It isn't clear what you're asking since you specified 'in a Feynman Diagram'. I assume you know the difference in spins.
 
The fermions are physical type particles and the bosons are effect type particles.

An electron would be a fermion and a photon would be a boson.

Is this the "more physical answer" you were looking for?
 
This thread is years old.
 
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Thread 'Lesser Green's function'
The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...

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