Calculating toxicant concentration

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SUMMARY

The forum discussion centers on calculating toxicant concentration for a toxicity bioassay using nitrate (NO3-) as the test toxicant. The participants clarify the correct calculation for determining the lethal concentration (LC50) based on the notation "NO3-N". The consensus is that to achieve a concentration of 10 mg NO3-N/L, one must use 60.71 mg of sodium nitrate (NaNO3), as this reflects the nitrogen content rather than the nitrate itself. This understanding is crucial for accurate toxicity testing in aquatic species.

PREREQUISITES
  • Understanding of toxicology and bioassays
  • Knowledge of nitrate chemistry, specifically sodium nitrate (NaNO3)
  • Familiarity with concentration calculations in environmental science
  • Basic principles of lethal concentration (LC50) determination
NEXT STEPS
  • Research the methodology for conducting toxicity bioassays
  • Learn about the implications of nitrate nitrogen (NO3-N) in aquatic ecosystems
  • Explore the calculation of lethal concentrations (LC50) for various toxicants
  • Investigate the effects of sodium nitrate (NaNO3) on different aquatic species
USEFUL FOR

Environmental scientists, toxicologists, laboratory technicians, and researchers involved in aquatic toxicity testing will benefit from this discussion.

PedroAndrade
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Hi!

In my lab we're preparing a toxicity bioassay using nitrate (NO3-) as the test toxicant. The tests we're doing are range-finding tests, to help determine the lethal concentration (LC50) for that species with nitrate.

We are following the lead of another work (http://www.sciencedirect.com/science?_ob=ArticleURL&_udi=B6V74-4F02KWG-B&_user=10&_rdoc=1&_fmt=&_orig=search&_sort=d&view=c&_acct=C000050221&_version=1&_urlVersion=0&_userid=10&md5=172b82c36ff657803f003c89ddaca62d") which used sodium nitrate (NaNO3) as the source of nitrate. In that article, the test concentrations used for a similar species range from 5 to 160 mg NO3-N/L. This is where my understanding of chemistry is lacking. I'll try to illustrate my doubts with an example:

If I want to find the LC50 for a solution of 10 mg nitrate/L, what do I calculate exactly?
a) 10 mg of NaNO3
b) 13,71 mg of NaNO3 - corresponding to 10 mg of NO3-
c) 60,71 mg of NaNO3 - corresponding to 10 mg of N

My feeling is that b) is correct, but the notation NO3-N is throwing me off. Can anyone help out with this?
 
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I thought it was b) too, lucky thing I asked a friend who's an environmental microbiologist.

It's c). "NO3-N/l" should be read as 'Nitrate nitrogen per liter". So it's just the amount of nitrogen.
 
Thank you very much alxm! You stopped my day from becoming the new season of 24.:smile:
 

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