Converting cm4 to m4: What's the Equation?

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To convert cm^4 to m^4, each centimeter must be converted to meters, which involves dividing by 100, since 100 cm equals 1 m. Therefore, to convert 92644 cm^4 to m^4, you would calculate (92644 cm^4) / (100^4) to find the equivalent in m^4. The conversion for area (cm^2 to m^2) follows a similar principle, where 100 cm equals 1 m, leading to 10,000 cm^2 equating to 1 m^2. Understanding the difference between linear and quartic measurements is crucial for accurate conversions. The final result will yield the correct measurement in cubic meters.
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I need to know how to convert cm4 to m4

I have 92644cm4 and want it in m4

Thanks.
 
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Do you know how to convert cm to m?

cm2 to m2?
 
yes but my teacher says when its m^4 its different than if its just m?
 
It is.

You have to convert each cm into m...
 
stainton1 said:
yes but my teacher says when its m^4 its different than if its just m?

That's why I asked not only about converting cm to m, but also about converting cm2 to m2...
 
100 cm = 1 m
so (100 cm)2 = 10,000 cm2 = (1 m)2 = 1 m2

And so on until you figure out how many cm4 are in 1 m4 (1 "quartic" meter).
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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