Minimum Separation of Two Frictionless Pucks

AI Thread Summary
To determine the minimum separation of two frictionless pucks with given masses and charges, one must consider the electrostatic repulsion due to their charges and their initial kinetic energies. The initial velocities of the pucks create kinetic energy, while the charges create potential energy that affects their motion. The relationship between kinetic energy and potential energy will help in calculating the minimum distance as they approach each other. The equation E = delta V/r may be relevant in analyzing the forces at play. Understanding these energy forms and their interactions is crucial for solving the problem effectively.
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two frictionless pucks are placed on a level surface, as shown, at an initial distance of 20.0 m. the mass of puck 1 is 0.80 kg and it has a charge of +3.0 X 10^-4 C., while puck 2 is 0.40 kg with a charge of +3.0 X 10^-4 C. the initial velocity of puck 1 is 12.0 m/s (E) and the initial velocity of puck 2 is 8.0 m/s (W). find the minimum separation of the two pucks (the minimum distance between the pucks>

1: I'm totally lost
would i use
E= delta V/r
?
 
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