Kal_Electri
- 1
- 0
The inductor is initially an air cored one.When the Iron core is introduced,the resistance is found to increase considerably.Please explain.
Losses.yungman said:Why is the resistance which is the real part increase?
DC? DC hasn't been mentioned.yungman said:Like how? When you measure at DC, it is only the resistance of the wire and is constant no matter what. How is the induction of core change the DC resistance?
jim hardy said:DC resistance doesn't change.
But if you measure AC impedance and phase angle and do a polar to rectangular calc you get a real component that is different from what a DC ohm-meter would report.
That's because the core losses are energy losses which can only show up as resistance.
And they're only present when excitation is AC.
NascentOxygen said:DC? DC hasn't been mentioned.
NascentOxygen said:DC? DC hasn't been mentioned.
The theory of eddy current losses in transformer laminations is given in http://www.elect.mrt.ac.lk/EE201_em_theory.pdfyungman said:But R is the DC value only! Or are you implying the skin effect cause the R to go up and this has nothing to do with the inductance. It is pure resistance that increase with frequency! That actually makes sense! I think I answer my own question!
jim hardy said:Yungman - check my thinking
Iron losses in the core come out as heat so must cause an in-phase component of current. Else there'd be no net electrical energy transfer into core. P=VICos(Theta) and theta can't be 90 degrees if there's any watts heating the core.
So they will appear to be another resistance in parallel
which will show up as series in theveniin equivalent
and the DC ohms will differ from the ohms in real component of complex Z.
am i on track?
old jim
jim hardy said:Yungman - check my thinking
Iron losses in the core come out as heat so must cause an in-phase component of current. Else there'd be no net electrical energy transfer into core. P=VICos(Theta) and theta can't be 90 degrees if there's any watts heating the core.
So they will appear to be another resistance in parallel
which will show up as series in theveniin equivalent
and the DC ohms will differ from the ohms in real component of complex Z.
am i on track?
old jim
Averagesupernova said:I would agree that in order for heat to be generated the current would have to be in phase with the voltage. Would we look at this as a parallel resistance or a series one?