Magnetic Field involving solenoids

AI Thread Summary
In the discussion about the magnetic field involving two solenoids, it is established that the inner solenoid has a magnetic field of zero when it is mounted inside the outer solenoid. The key point is that both solenoids carry the same number of turns per unit length, and the magnetic field inside a solenoid is given by the formula B = μ_o * i * n. Participants conclude that if the currents in the two solenoids are equal and opposite, the magnetic fields will cancel each other out, resulting in a zero magnetic field in the inner solenoid. Therefore, the correct answer is that the current in the inner solenoid is the same as the current in the outer solenoid.
McAfee
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Homework Statement



Two long ideal solenoids (with radii 20 mm and 30 mm respectively) carry the same number of turnes of wire per unit length. The smaller solenoid is mounted inside the larger, along a common axis. It is observed that the magnetic field within the inner solenoid is zero. The current in the inner solenoid must be:

A. two-thirds the current in the outer solenoid
B. one-third the current in the outer solenoid
C. twice the current in the outer solenoid
D. half the current in the outer solenoid
E. the same as the current in the outer solenoid

This one is hard. If you could please provide an explanation with the answer so I could better understand this.
THanks in advance.

Homework Equations



n/a

The Attempt at a Solution



Right now I'm ruling out answer A.
 
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Hi McAfee! :smile:
McAfee said:
Two long ideal solenoids (with radii 20 mm and 30 mm respectively) carry the same number of turnes of wire per unit length. The smaller solenoid is mounted inside the larger, along a common axis. It is observed that the magnetic field within the inner solenoid is zero.

Call the currents I and J.

Hint: what is the formula for the magnetic field inside a current-carrying solenoid?

And can we just add the fields?
 
tiny-tim said:
Hi McAfee! :smile:Call the currents I and J.

Hint: what is the formula for the magnetic field inside a current-carrying solenoid?

And can we just add the fields?

The formula is B = μ_o*i*n

n is the number of turns
and yes
 
yup! :smile:

so what's the total equation, and is it A B C D or E ? :wink:
 
20mm = .02
30mm = .03

assuming that I can ignore n because it will be the same for both.
Would it be E because the radii doesn't play a role in the equation?
 
sorry, i missed your post :redface:
McAfee said:
assuming that I can ignore n because it will be the same for both.
Would it be E because the radii doesn't play a role in the equation?

yes the radii don't matter,

so if (case E) the currents are equal (and opposite), then the magnetic field inside the inner solenoid will be zero :smile:
 
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