Blackbody Heat Shields/Metal Sheets

  • Thread starter Thread starter sweetdreams12
  • Start date Start date
  • Tags Tags
    Blackbody Heat
AI Thread Summary
A blackbody heat shield effectively minimizes radiant heat loss by utilizing parallel metal sheets with an emissivity of 1.0. Each sheet absorbs and re-emits radiation, creating a barrier that reduces the overall heat transfer. To achieve less than 20% heat loss compared to an unshielded scenario, calculations must consider the temperature equilibrium of the sheets and the environment's temperature, typically around 0°C. The Stefan-Boltzmann law, P_emitted = σAT^4, is crucial for determining the emitted power and understanding the thermal dynamics involved. Proper analysis will reveal the necessary number of sheets to meet the desired heat loss reduction.
sweetdreams12
Messages
8
Reaction score
0
A “blackbody heat shield” is used to reduce radiant heat loss in situations where standard low conductivity insulation (i.e. normal insulation) cannot be used. The shield is constructed using a set of parallel metal sheets, each with emissivity 1.0.

Explain how/why this “heat shield” works and determine how many sheets of metal are
required to reduce the heat loss to less than 20% of the unshielded value. (Hint: think
about the radiation absorbed by each sheet and how this energy will be re-radiated.)

Diagram:
gbZNa.jpg


I really need help with this xD I don't even know where to begin.
 
Science news on Phys.org
Here are some ideas:
- assume that the whole problem is 1-dimensional
- begin with 1 heat shield: Where does it receive/emit radiation?
- assuming that the environment has a temperature of ~0, calculate the temperature of that heat shield in equilibrium
 
ummmm I still don't get it xD

do I use the equation:

Q = mC deltaT?
 
No, that looks like regular conduction.
##P_{emitted}=\sigma A T^4## (Stefan-Boltzmann)
 
Thread 'Thermo Hydrodynamic Effect'
Vídeo: The footage was filmed in real time. The rotor takes advantage of the thermal agitation of the water. The agitation is uniform, so the resultant is zero. When the aluminum cylinders containing frozen water are immersed in the water, about 30% of their surface is in contact with the water, and the rest is thermally insulated by styrofoam. This creates an imbalance in the agitation: the cold side of the water "shrinks," so that the hot side pushes the cylinders toward the cold...
Back
Top