Finding the air cavity resonance of a propane tank for a drum.

AI Thread Summary
The discussion focuses on building a drum from a propane tank and the importance of determining its resonant frequency to optimize tuning. The creator plans to incorporate approximately seven distinct notes, referred to as "tongues," and is seeking formulas to relate tongue dimensions to the tank's resonant frequency. Suggestions include using a microphone and speaker setup to identify the resonant frequency through feedback oscillation or by dropping a marble into the tank to capture the echo. There is also a recognition that the air cavity's resonance may differ from the mechanical resonance of the steel shell, and achieving a design where these frequencies coincide could enhance the drumming effect. Overall, the goal is to create a functional and musically versatile instrument for a drummer.
great_sushi
Messages
30
Reaction score
0
I am going to build a drum out of a propane tank. I think it will be handy to find the resonant frequency of the tank and choose the tuning accordingly so not to pick frequencies that are extremely damped.

I have a cavity resonance formula found on hyper physics
cav.gif


I am not going to build a drum with only one note, there will be approximately 7. 7 notes in most scales. http://muzmaker.ru/uploads/posts/2009-04/1240604374_717ff323216270166.jpg
If you look at the image you'll see the notes, I am going to refer to them as tongues.

Once I find the resonant frequency I can decide on the tuning. Another problem is choosing the dimensions of the tongues at the top. I've been trying to find another formula so that I can determine the size of the tongues, so a larger tongue results in a slower oscillation producing a lower note and vice versa. But I will need to relate the tongue dimensions to the resonant frequency of the tank.

Im curious to know how to calculate the resonant frequency of something steel with particular dimensions.

Once I have that relation I can move forward. Also, fine tuning will be done by either bending the tongue downward/upward permanently as to result in a lower/higher frequency respectively.

Thankyou, If all goes well, my drummer sister will have another present for christmas.
 
Physics news on Phys.org
Do you have an oscilloscope on which to measure frequency, if you were to use a microphone? (You might also need an amplifier.) If you held a microphone at the mouth of the cavity, and dropped a marble inside, you'd record a decaying echo which would be the frequency of resonance. I don't quite understand how something like this could simultaneously have 7 unrelated resonant frequencies, but maybe that is possible. I don't claim to understand much about the mysteries of music.
 
I don't have a microphone but I could introduce a speaker into the cavity and do a frequency sweep. Noting the frequencies that 'stand out'. I imagine that there will be one natural frequency and perhaps 'n' integer values of the wavelength.
Say having one wave with (i think its nodes where you hear maximum intensity) nodes at both ends, (only two). Then one whole wavelength with 3 nodes, then 4 nodes, then 5.
I might not be explaining it very well and I may be wrong.

It would be great if someone could explain it properly
 
On further reflection, I guess the air cavity could have a resonant frequency that is independent of the mechanical resonance of the steel shell. I expect drumming effect would be most impressive when the design sees these two frequencies coincide.

You certainly could try sweeping the speaker frequency and listening for a peak, but when I tried this using a column of glass tube as a class demo, the peak was as good as imperceptible.

An idea that could hold promise involves introducing both a microphone and a speaker into the cavity, the speaker delivering an amplified version of what the mic picks up. As the gain is turned up, feedback should see the system begin to oscillate and show feedback squeal. I expect that frequency of oscillation would be the resonant frequency of the cavity. You might be able to press into service the mic and earpiece from a discarded cell phone for this. This isn't going to reveal multiple resonant frequencies, though.
 
Last edited:
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
Back
Top