How Fast Can Water Flow from a Kitchen Faucet on the Third Floor?

AI Thread Summary
The discussion focuses on calculating the maximum velocity of water flowing from a kitchen faucet located on the third floor, given a gauge pressure of 170 KPa at street level. The relevant Bernoulli equation is applied, but there is confusion regarding the definition of P2, with some participants suggesting it should be atmospheric pressure. The correct interpretation of P1 as gauge pressure and the need to adjust P2 accordingly is emphasized. The expected answer for the maximum velocity is 6.8 m/s, but the initial approach to the equation was incorrect. Clarification on the pressure terms is crucial for solving the problem accurately.
lch20yy
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Homework Statement



water in main pipe at the street level is at a gauge pressure of 170 KPa and is moving with neglibible speed. A pipe connected to the main pipe is used to deliver the water to kitchen located on the third floor of a building, at a 15-m height from the street level. what is the maximum possible velocity with which the water can emerge from an open kitchen faucet?

Homework Equations



p1+1/2 rho G v^2+rho G H = p2 + 1/2 rho G v^2 + rho G H

The Attempt at a Solution



i have the equation p1=p2+1/2(rho)GV^2+(rho)G H
since p1 speed is negligible and height is 0. I am not sure abount what p2 is. is it the atmosphere pressure?
the answer is 6.8m/s, but i can't get the answer. pls help
 
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lch20yy said:
p1+1/2 rho G v^2+rho G H = p2 + 1/2 rho G v^2 + rho G H
A spare couple of Gs in there.
I am not sure abount what p2 is. is it the atmosphere pressure?
P1 is given as gauge pressure, which means it's the additional pressure beyond atmospheric. So what do you think you should use for P2?
 
ok i got this ... i got the equation wrong
 

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