PAllen
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A.T. said:Thanks. Do you have some links on Fermi-normal coordinates in uniformly accelerated frames and Minkowski space-time? The wiki says it is just a generalization of Rindler for curved space-times, so I assumed that for accelerated frames in flat space time they yield the same results.
For a beautiful derivation that Rindler coordinates are radar coordinates, our very own George Jones recently produced:
https://www.physicsforums.com/showpost.php?p=4278480&postcount=5
From the wikipedia article, the metric for Rindler coordinates is:
ds^2 = - g^2 x^2 dt^2 + dx^2 ...
I don't know of a good online reference for Fermi-Normal coordinates of a uniformly accelerated observer in SR. However, section 6.6 of MTW derives this (without calling it that). This section is all flat spacetime. The metric becomes:
ds^2 = -(1+ g x)^2 dt^2 + dx^2 ...
Note how this form approaches Minkowski metric for x=0. For Rindler coordinates x=0 represents the horizon. Also note that if you just transform Rindler to have its x=1 line become new x=0, you still don't get Fermi Normal; you get:
ds^2 = -(g+gx)^2 dt^2 + dx^2 ...
What you need is x' = x - 1/g to get from Rindler to Fermi-Normal.
[Edit: On further thought, it appears that Fermi-Normal coordinates as above, for a uniformly accelerating observer would still have the same simultaneity surfaces as Rindler and Radar - just labeled differently. Thus, it seems, you need change in acceleration - e.g. the classic twin with slightly rounded turnaround - to expose the difference between Radar simultaneity and Born Rigid simultaneity (which is what Fermi-Normal uses).]
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