Problem with use of 'velocity' of charged particle in lorentz force eq

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The discussion centers on the application of the Lorentz force equation for a charged particle moving in a uniform magnetic field. It highlights the discrepancy in force calculations when observing the particle from different reference frames, specifically when the observer moves with a velocity V' parallel to the particle's velocity V. The key point raised is whether the magnetic field is considered fixed relative to both frames, which affects the resulting electric field due to the Lorentz transformation. The introduction of an electric field complicates the analysis, as it alters the net force acting on the particle. Clarifying these assumptions is essential for accurately determining the forces involved in different reference frames.
pratikaman
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if we assume a charge particle enters in a uniform magnetic field with velocity V w.r.t inertial frame as shown fig. then according to the situation shown there will be force acting on particle due to magnetic field (neglecting B field induced due to charged particle itself). But now if we observe this situation from a frame of reference which is moving with velocity V' in direction of particle's velocity with respect to inertial frame then velocity of particle observed in that frame will be V-V'. then force on particle due to magnetic field will be less (As calculated by lorentz force equation) than as calculated in inetial frame.

what will be the right solution for this case?
 

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Are you implying/specifying/assuming that the magnetic field is fixed in relation to both reference frames?
 
There will now be an E field, becuse a Lorentz transformation of B produces an E field.
 
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