How long to fire a small rocket. Impulse problem.

AI Thread Summary
Small rockets are utilized for minor speed adjustments in satellites, with one example having a thrust of 59N. To determine how long the rocket should be fired to change a 74,000kg spacecraft's velocity by 54cm/s, the impulse-momentum relationship is applied. The relevant formula derived is delta t = m(Vf - Vi) / F, where delta t represents the time duration of the thrust. The discussion highlights the challenge of not having the initial velocity (Vi) to complete the calculation. Ultimately, the focus is on understanding the change in velocity needed for the calculation.
fanie1031
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1. Small rockets are sued to make small adjustments in the speed of satellites. One such rocket has a thrust of 59N. If it is fired to change the velocity of a(n) 74000kg spacecraft by 54cm/s, howl ong should it be fired? Answer in units of s.


2.
F=deltaP, delta t;
F=mVf-mVi (impulse equals change in momentum);
F=m(delta v,delta t)

So my derivation (if that's a word) is

(m*delta v)/ delta t= net force = mVf-mVi. From there I get the formula in my attempt to solve the problem.


3. I made delta t=mV/F= 74000kg(.054m/s)/ 59N... I think my problem lies in that I don't have the initial velocity... but I'm not sure how to get it.
 
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Oh in 2. It should be F= m(delta v/delta t)
 
fanie1031 said:
1. Small rockets are sued to make small adjustments in the speed of satellites. One such rocket has a thrust of 59N. If it is fired to change the velocity of a(n) 74000kg spacecraft by 54cm/s, howl ong should it be fired? Answer in units of s.


They want the change in velocity to be 54cm/s

and since Ft=mv-mu=m(v-u)

What should v-u be equal to?
 
Dang, I don't know what you mean by u in Ft=mv-mu=m(v-u). The change in velocity is definitely something I missed. THank you for pointing it out.
 
Oh I got it. Thank you. Delta t= m(Vf-Vi)/F.
 
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