Derivative of tan(2x) at pi/6 without a calculator

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Homework Statement



If f(x)= tan(2x), then f'(pi/6) =

Homework Equations



deriv. of tan(pi/3)

The Attempt at a Solution



How can I solve this? I am not supposed to use a calculator?? tan(pi/3) ...am I supposed to memorize this?
 
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What is f'(x) ?
Hint: use the chain rule.
 
tan(pi/3) ' = sec^2(pi/3) is it??
 
And now how can you simplify that using the definition of sec?
 
SAT2400 said:

Homework Statement



If f(x)= tan(2x), then f'(pi/6) =

Homework Equations



deriv. of tan(pi/3)
The derivative of tan(pi/3) is zero. tan(pi/3) is a constant, and the derivative of any constant is zero.
SAT2400 said:

The Attempt at a Solution



How can I solve this? I am not supposed to use a calculator?? tan(pi/3) ...am I supposed to memorize this?
Yes. There are a few angles whose trig functions you should have memorized - 0, pi/6, pi/4, pi/3, pi/2, as well as their supplements and combinations with pi/2, pi, and so on. You should also have memorized all of the six trig functions in terms of the sine or cosine.
 
jav said:
And now how can you simplify that using the definition of sec?

Can you write sec x in terms of sine and/or cosine? You should have memorized the values of sin(pi/3) and cos(pi/3)
 
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