What's wrong with this local realistic counter-example to Bell's theorem?

  • #51
JenniT said:
Taking just the first part of your post:

I am confused.

In the PDF, the P1-P8 are the probabilities that attach to the outcomes that are in the two Bell-table columns to their left.
But those cannot possibly be observable outcomes because they specify + or - for three different angles, whereas on each trial there are only two experimenters who can each get a result at only one angle. Do you understand that on the Sakurai's Bell inequality page, notation like + - + in the "Alice" column is intended to mean that on a given trial, the source sent a particle to Alice whose hidden variables predetermined (even before she chose what angle to set her polarizer to) that if she chose angle "a" on that trial she was guaranteed to get +, if she chose angle "b" on that trial she was guaranteed to get -, and if she chose angle "c" on that trial she was guaranteed to get +? And do you understand that there is no way we can actually know what predetermined results were associated with Alice's particle on each trial, that + - + represents a hidden set of predetermined results, with P1-P8 representing the hidden probabilities that the source sends out each possible set of predetermined results? Please tell me, yes or no, if you understand and agree that this is the meaning of P1-P8 on the Sakurai's Bell inequality page.

If you do understand and agree with this, then are P1-P8 on your table intended to have exactly the same meaning? If not, what do they mean? For example, suppose on one trial Alice chooses angle a and got result +, while Bob chose angle c and got +. How are we supposed to know whether this trial corresponded to the "outcome" [Alice: +--, Bob: -++] or if it corresponded to the "outcome" [Alice:++-, Bob: -++]? Both of these have a + in the "a" slot for Alice, and a + in the "c" slot for Bob. Is the "outcome" of each trial supposed to be something determined by experiment, or is it supposed to be a "hidden" fact which we imagine could be known by an omniscient observer even if it's not known by us, as on the Sakurai's Bell inequality page?
JenniT said:
In equation (1), directly below the table, I directly derive Pab by summing over P3 and P4 (as you suggest).
Then why did you say that you "absolutely reject" the claim that P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7? Which one of these do you reject? I won't be able to understand why you reject it unless you give me a straight answer to what P1-P8 are supposed to be the probabilities of, certainly all three of these equations must be true if P1-P8 have the meaning on the wiki page which I discussed above, do you disagree?
JenniT said:
Re games: I do not expect any classical game (eg, cards, balls) to deliver the correct results that are to be associated with EPRB.
Do you include the type of computer-simulation game I mentioned as a "classical game"? If so, I'd say that shows you don't understand what "local realism" means, since the laws of a local realist universe should be possible to simulate (at least approximately, to any desired degree of accuracy) on a collection of computers where each computer is calculating what should happen in each local region of spacetime, with each computer only having access to the output of other computers which simulated local regions in the past light cone of that one. If you don't see why this should be true and want to discuss it, read over the definition of local realism I gave in [post=3154224]post #20 to Avodyne[/post] and tell me if you don't understand it or don't see how it would imply the idea that a local realist universe should be possible to simulate on a network of local computers each figuring out what happens in a small unit of space in each small increment of time (like a cellular automaton)
JenniT said:
I thought (was I wrong) that the so-called silly equation was mentioned somewhere in relation to this thread? I thought someone related it to BI?
I was referring to this equation: P3 + P4 = P3 + P4 + (POSITIVE NUMBER). I'm sure no one seriously suggested a sum of two probabilities could fail to be equal to itself.
JenniT said:
Is the above-quoted sum, (1) in the PDF, wrong?
It gives the correct answer but without an explanation of what the symbols P3 and P4 are supposed to mean, it is physically meaningless.
 
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  • #52
JenniT said:
YOU say "logically this would imply that

P(a+, b+) = P3 + P4 and

P(a+, c+) = P2 + P4 and

P(c+, b+) = P3 + P7...
"

From the PDF; and in its terminology (which is consistent with yours):

Pab++ = P3 + P4. See PDF eqn (1).

Pac++ = P2 + P4; from direct observation in the PDF!

Pcb++ = P3 + P7; from direct observation in the PDF!

As DrC often says: Where's the beef?

Your logical implication agrees with the PDF.
The PDF does not give any formulas for Pac++ and Pcb++, so I don't know what you mean by "from direct observation". And if that's the case, why did you say in post #42 (after you had posted the PDF) the following?
NB: I ABSOLUTELY REJECT:

P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7.
I was just taking you at your word that you "absolutely reject" that. In any case, if you do agree with these equations, then would you not also agree that since P2, P3, P4, and P7 are all non-negative, it must be true according to your formulas that P3 + P4 ≤ P2 + P4 + P3 + P7, and thus Pab++ ≤ (Pac++) + (Pcb++) for all possible values of a,b,c?
 
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  • #53
JesseM said:
But the sums are physically meaningless if you don't explain basic definitional questions like what you mean the probabilities P1-P8 to be the probabilities of. You obviously don't mean them to be probabilities of different predetermined states according to the chart on the wiki page, because then you wouldn't say:

If you accepted the standard meaning of P1-P8 you would have to accept this; for example, P3 and P4 are the probabilities of the only two predetermined states where Alice is predetermined to get + if she chooses angle "a" and Bob is predetermined to get + if he chooses angle "b".

Not if you use the standard definition of P1-P8. I have no idea what you mean the probabilities P1-P8 to be the probabilities of, and thus no idea why you think the previous line would "imply" this silly equation.

Forget about particle experiments for a second and consider this simple analogy. Suppose we have a machine that periodically prints out pairs of scratch lotto cards, and sends one card to Alice and one to Bob. Each card contains three squares labeled "a", "b", and "c", which are covered by a silvery substance you have to scratch to see what's underneath, and anytime a square is scratched it will reveal either a + or - underneath. Suppose Alice and Bob choose randomly which square to scratch each time they receive a card, and after many trials we observer that on every trial where they choose to scratch the same square, they get opposite results (+- or -+). Wouldn't the natural local realist conclusion be that each time the machine prints a pair of cards and sends them, then before Alice and Bob choose which box to scratch there is already either a + or - under each square, with the machine always making sure to make each member of the pair the opposite of the other, so for example the hidden symbols on Alice's card are a+,b-,c+ then the hidden symbols under Bob's must be a-,b+,c-? In this case, over many trials the source will print each type of card with some well-defined frequency, so we can define the following probabilities:

P1 = Probability that source sent card (a+,b+,c+) to Alice and card (a-,b-,c-) to Bob
P2 = Probability that source sent card (a+,b+,c-) to Alice and card (a-,b-,c+) to Bob
P3 = Probability that source sent card (a+,b-,c+) to Alice and card (a-,b+,c-) to Bob
P4 = Probability that source sent card (a+,b-,c-) to Alice and card (a-,b+,c+) to Bob
P5 = Probability that source sent card (a-,b+,c+) to Alice and card (a+,b-,c-) to Bob
P6 = Probability that source sent card (a-,b+,c-) to Alice and card (a+,b-,c+) to Bob
P7 = Probability that source sent card (a-,b-,c+) to Alice and card (a+,b+,c-) to Bob
P8 = Probability that source sent card (a-,b-,c-) to Alice and card (a+,b+,c+) to Bob

Can you see that in this example, it must be true that if Alice scratches square a and Bob scratches square b, P(a+,b+) must be P3 + P4? Likewise if Alice scratches square a and Bob scratches square c, P(a+, c+) = P2 + P4, and if Alice scratches square c and Bob scratches square b, P(c+, b+) = P3 + P7. But in no way does this "imply" your strange equation saying that P3 + P4 = P3 + P4 + (POSITIVE NUMBER), here P3 + P4 = P3 + P4 and nothing more. Do you agree that all this is true of this specific example involving scratch lotto cards, ignoring for the moment your weird ideas about particle experiments and angles? Please give a clear yes/no answer here.

If you agree with this, then understand that the probabilities in the Sakurai's Bell inequality page are meant to be exactly analogous, they simply represent predetermined results (determined by the hidden variables associated with the particle, which might be arbitrarily complex) for each of the three allowed orientations of the polarizers or Stern-Gerlach devices. So if you mean the probabilities to represent something different, and this difference leads you to odd conclusions like the "implication" P3 + P4 = P3 + P4 + (POSITIVE NUMBER), you need to explain what you mean the probabilities P1-P8 to represent physically, if they are not intended to have the same meaning as on the Sakurai Bell inequality page. If you don't explain what the physical meaning of P1-P8 are supposed to be, then the "reasoning" behind your statements is going to be totally incomprehensible to anyone but yourself, it's as if you're speaking your own private language that no one else understands. But I suspect that the problem may be deeper, that even you don't really have any clear notion of what P1-P8 are supposed to represent, and that you've just invented some rather arbitrary mathematical rules for yourself without bothering to think about what the physical meaning of the symbols is actually supposed to be.

Why did it have you confused? The rules were fairly simple, you play the role of the source, then you can load any information onto the two flash drives on each trial (representing the hidden variables associated with the two particles created by the source on a given trial), then the two flash drives are sent to Alice and Bob. They then have a choice of whether to press A, B, or C (representing three orientations of simulated polarizers or SG devices), and their computers will simulate the "laws of physics" (these laws can be anything you want them to be, you programmed the rules in advance), taking into account both the variables associated with the particle on the flash drive and the simulated orientation selected by the experimenter, to produce either + or - as output. To "win" this game, you just have to produce statistics analogous to those in QM, meaning that on every trial where Alice and Bob chose the same button to press they always got opposite results, but on trials where they chose different buttons, the frequency they both got + is the same as in QM (and can thus violate the Bell inequality). Is there any aspect of this game you find unclear? If not, do you think that the PDF shows a strategy that would allow you to "win" at this game?


Jesse,

1: You appear to have been mislead by an incorrectly placed full stop; possibly from a cut-and-paste. I've fixed this. But am unsure what you think my qualifying clause attached to. And why it is not mentioned in your critique?

May I take it that you do not require me to deliver one of your terms being equal to the sum of two others?

Am concerned there's a subtlety here that I do not want to gloss or miss. Do you require any manipulation of the 3 terms?

2. Re games: Excuse my being guarded here until we are clear about the PDF. Flash-drives etc are classical devices; I doubt they could encode entanglement. It might be that you just want to encode the PDF? Is it the God's-eye distribution that some look for?

PS: Could I have one question per post for a while, please.

Here's mine: Do you require any manipulation of the 3 terms that you keep citing, please?
 
  • #54
JesseM said:
A: The PDF does not give any formulas for Pac++ and Pcb++, so I don't know what you mean by "from direct observation".

I meant "by looking at the table".

JesseM said:
B: And if that's the case, why did you say in post #42 (after you had posted the PDF) the following?

Please see the qualifying sentence immediately beneath

JesseM said:
C. I was just taking you at your word that you "absolutely reject" that. In any case, if you do agree with these equations, then would you not also agree that since P2, P3, P4, and P7 are all non-negative, it must be true according to your formulas that P3 + P4 ≤ P2 + P4 + P3 + P7, and thus Pab++ ≤ (Pac++) + (Pcb++) for all possible values of a,b,c?
Help please. Could you explain the physical significance of this SUM?

Is it the case that the inequality holds (or is relevant) for some logical or physical reason?

I think explanation here might make it clearer to me where I have confused you. Or where I have erred.

Thanks.
 
  • #55
JenniT said:
Jesse,

1: You appear to have been mislead by an incorrectly placed full stop; possibly from a cut-and-paste. I've fixed this. But am unsure what you think my qualifying clause attached to. And why it is not mentioned in your critique?
I thought "if it implies" was just a rhetorical phrase, like "I reject Obama's healthcare plan if it implies people are mandated to buy insurance", where the person saying this knows that Obama's plan does include such a mandate. Are you saying you are genuinely unsure as to whether the equations P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7 hold, or whether P3 + P4 = P3 + P4 + (POSITIVE NUMBER) would be an implication of this? I don't know what possible argument would "imply" that the second would be a consequence of the first, seems like a total non sequitur to me. And in any case, if you aren't even sure how to calculate P(a+, b+) and P(a+, c+) and P(c+, b+) then you obviously can't claim that you have a well-defined "model"!
JenniT said:
May I take it that you do not require me to deliver one of your terms being equal to the sum of two others?
If by this you mean P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7, then this is an automatic consequence of the definitions of P1-P8 on the Bell inequality page, if you don't think all three of these equations hold then you need to explain what your physical definitions of P1-P8 are (as I keep asking over and over) and how you calculate P(a+, b+) and P(a+, c+) and P(c+, b+).
JenniT said:
Am concerned there's a subtlety here that I do not want to gloss or miss. Do you require any manipulation of the 3 terms?
Don't know what you mean by "manipulation".
JenniT said:
2. Re games: Excuse my being guarded here until we are clear about the PDF. Flash-drives etc are classical devices; I doubt they could encode entanglement.
A "local realist" model of QM would be a classical model in the sense that Maxwell's laws are classical, it would explain everything without recourse to superpositions or spooky-action-at-a-distance. Again it seems doubtful to me that you really understand the meaning of "local realism" if you don't see that local realist models should be possible to simulate to arbitrary accuracy on classical computers.
JenniT said:
It might be that you just want to encode the PDF? Is it the God's-eye distribution that some look for?
If you want to pick your strategy in the game by "encoding the PDF" be my guest. For example, on each trial you could load the flash drives with a set of predetermined results like a+,b-,c+, with the probabilities of different predetermined results on each trial being determined by P1-P8 in your PDF. Then each computer's algorithm for generating a "result" on each trial would just be to take the button pressed by the user (Alice or Bob), then look at the corresponding slot on the predetermined results on the flash drive, and give the symbol in that slot as output (for example, if Alice chooses button "b" and her flash drive contains the predetermined results a+,b-,c+, then the output would be -). But this strategy would not be a "win" for you, because the statistics over many trials would not match those of QM.
JenniT said:
PS: Could I have one question per post for a while, please.

Here's mine: Do you require any manipulation of the 3 terms that you keep citing, please?
Again I don't know what you mean by "manipulation", perhaps you could give an example? Anyway, my main question right now would just be how you would propose to calculate P(a+, b+) and P(a+, c+) and P(c+, b+), whether you would use the formulas P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7, with P2,P3,P4,P7 all defined as in the PDF, or whether you would use some different formulas.
 
  • #56
JenniT said:
I meant "by looking at the table".
Your table does not give any formulas for calculating Pac++ and Pcb++.
JenniT said:
In any case, if you do agree with these equations, then would you not also agree that since P2, P3, P4, and P7 are all non-negative, it must be true according to your formulas that P3 + P4 ≤ P2 + P4 + P3 + P7, and thus Pab++ ≤ (Pac++) + (Pcb++) for all possible values of a,b,c?
JesseM said:
Help please. Could you explain the physical significance of this SUM?

Is it the case that the inequality holds (or is relevant) for some logical or physical reason?
It would hold in a local realist theory where each particle pair has hidden variables that predetermine what result it would give to any of the possible polarizer angles, with P1-P8 giving the probabilities of different sets of predetermined results as shown in the wiki page's table. But Pab++ ≤ (Pac++) + (Pcb++) does not hold in the theory of quantum mechanics for certain values of a,b,c. Therefore the theory of QM cannot be explained by a local realist theory.
 
  • #57
JesseM said:
I thought "if it implies" was just a rhetorical phrase, like "I reject Obama's healthcare plan if it implies people are mandated to buy insurance", where the person saying this knows that Obama's plan does include such a mandate. Are you saying you are genuinely unsure as to whether the equations P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7 hold, or whether P3 + P4 = P3 + P4 + (POSITIVE NUMBER) would be an implication of this? I don't know what possible argument would "imply" that the second would be a consequence of the first, seems like a total non sequitur to me. And in any case, if you aren't even sure how to calculate P(a+, b+) and P(a+, c+) and P(c+, b+) then you obviously can't claim that you have a well-defined "model"!

OK; so we're clear on what I meant.

We appear to agree re non sequiturs.

I am sure of my calculations and reject the non sequitur.

Did I not answer this? https://www.physicsforums.com/showpost.php?p=3158191&postcount=50

The model is well-defined ... at least in so far as it agrees with your logical implication.

JesseM said:
If by this you mean P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7, then this is an automatic consequence of the definitions of P1-P8 on the Bell inequality page, if you don't think all three of these equations hold then you need to explain what your physical definitions of P1-P8 are (as I keep asking over and over) and how you calculate P(a+, b+) and P(a+, c+) and P(c+, b+).

Jesse, I'm sure that I calculate them the same way you do, using P1-P8 per the PDF.

If you refer to the calculation of each of P1-P8; they are derived from local realistic considerations. Just before this post of yours I was about to post this:

Thinking hard about our differences, does this help: Are you confusing my model with naive realism? With EPR elements of physical reality, interpreted in the naive tradition?

I AM NOT in the naive tradition in any way. My HVs are perturbed by the measurement interaction. To my mind, via spin axes following gyroscopic-like trajectories. The tricky word in EPR eprs is "corresponding".​

JesseM said:
Don't know what you mean by "manipulation".

OK. I meant equating the 3 of them in some way.

JesseM said:
A "local realist" model of QM would be a classical model in the sense that Maxwell's laws are classical, it would explain everything without recourse to superpositions or spooky-action-at-a-distance. Again it seems doubtful to me that you really understand the meaning of "local realism" if you don't see that local realist models should be possible to simulate to arbitrary accuracy on classical computers.

Oh! Oh! Is your requirement realistic?

I'm pretty sure that entanglement cannot be simulated on classical computers: spherical symmetry etc.

I am confident that my LR ideas cannot be simulated. You seem to be limiting LR to naive realism, in some of these phrases. My LR, primitive or cumbersome as it may seem, delivers the PDF. Your question below relates to that. LET US NOT get carried away by discussing LR now. If the PDF fails, my LR fails.

JesseM said:
If you want to pick your strategy in the game by "encoding the PDF" be my guest. For example, on each trial you could load the flash drives with a set of predetermined results like a+,b-,c+, with the probabilities of different predetermined results on each trial being determined by P1-P8 in your PDF. Then each computer's algorithm for generating a "result" on each trial would just be to take the button pressed by the user (Alice or Bob), then look at the corresponding slot on the predetermined results on the flash drive, and give the symbol in that slot as output (for example, if Alice chooses button "b" and her flash drive contains the predetermined results a+,b-,c+, then the output would be -). But this strategy would not be a "win" for you, because the statistics over many trials would not match those of QM.

My model would require us to go beyond the encoding of gyroscopes, no two gyroscopes the correlated, except pair-wise; observers freely setting measurement orientations at random, ... Let's not digress; just yet.

JesseM said:
Again I don't know what you mean by "manipulation", perhaps you could give an example? Anyway, my main question right now would just be how you would propose to calculate P(a+, b+) and P(a+, c+) and P(c+, b+), whether you would use the formulas P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7, with P2,P3,P4,P7 all defined as in the PDF, or whether you would use some different formulas.

Manipulation addressed above.

I think I answered the next one: No difference between you and me here. Have you run a few lines using the PDF example below the table?

You do see that each result there is in total agreement with QM?

My question: Has anyone, presumably from the so-called Bell community, delivered the values for P1-P8 that the table requires? I'd be keen to see where they differ from mine.
 
  • #58
JenniT said:
Jesse, I'm sure that I calculate them the same way you do, using P1-P8 per the PDF.
"Using P1-P8" is still vague, do you use all of the equations P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7, yes or no? If you do then your probabilities will obey the inequality Pab++ ≤ (Pac++) + (Pcb++)! The whole point of the proof is that QM violates this inequality, therefore it cannot be compatible with local realism! If you use the equations P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7 then your model disagrees with QM, do you not understand this?
 
  • #59
JesseM said:
Your table does not give any formulas for calculating Pac++ and Pcb++.

Could you just use your formula; or the evident formula that I used in the worked example.

Why not do Pac++ and Pcb++?

Here's my answer: Sac/2, Scb/2. The QM results, I believe?
JesseM said:
It would hold in a local realist theory where each particle pair has hidden variables that predetermine what result it would give to any of the possible polarizer angles, with P1-P8 giving the probabilities of different sets of predetermined results as shown in the wiki page's table. But Pab++ ≤ (Pac++) + (Pcb++) does not hold in the theory of quantum mechanics for certain values of a,b,c. Therefore the theory of QM cannot be explained by a local realist theory.

By predetermined; do you allow the HV to respond to each SGM that it encounters?

I'm wondering if this is the key difference between us. Explaining your focus on card-games? Card games cannot deliver the PDF table!

My calculation would yield: Pab++ = Sab/2 ≤ 1/2.

Which MUST hold in QM.

For I have Pac+– and Pbc+– added to the RHS of what you offer above.

My one question: Is it not the case that they too deliver: a = +; b = +; and so must be included in any rational study?

Thanks, as always,

JenniT
 
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  • #60
JesseM said:
"Using P1-P8" is still vague, do you use all of the equations P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7, yes or no? If so then your probabilities will obey the inequality Pab++ ≤ (Pac++) + (Pcb++)! The whole point of the proof is that QM violates this inequality, therefore it cannot be compatible with local realism! If you use the equations P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7 then your model disagrees with QM, do you not understand this?
We are cross-posting.

I use all, and maybe more, in the equation of yours above.

(This is what I meant by "manipulation, in its + sense, please understand!)

MY PDF violates this inequality, and agrees with QM, as explained in my just sent post.
 
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  • #61
Jesse, my replies will be spasmodic for a week or more. I will try to keep in touch because I think that we are getting to the meat of the differences between us.

XO, JenniT
 
  • #62
JenniT said:
Could you just use your formula; or the evident formula that I used in the worked example.

Why not do Pac++ and Pcb++?

Here's my answer: Sac/2, Scb/2. The QM results, I believe?
And how did you calculate these answers?? I just want a yes or no answer to the question of whether you use the formulas Pab++ = P3 + P4 and Pac++ = P2 + P4 and Pcb++ = P3 + P7, I won't discuss any further issues if you continue to be evasive on this simple question. It's obvious that if you do use these formulas, you will not get the QM predictions of Pab++=Sab/2, Pac++=Sac/2, and Pcb++=Scb/2 (if you think you will, you have made a math error somewhere)

edit: and speaking of math errors, your derivation in the PDF for Pab++=P3+P4=Sab/2 doesn't work. I'm fine up to the step where P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6, but how do figure that this would be equal to (2Sab + 2Pab++)/6? That's clearly wrong if you substitute some actual angles, like the earlier example of a=240,b=120 and c=0. In this case we have:

Sab=sin^2 ((a-b)/2) = sin^2 (60) = 0.75
Cac=cos^2 ((a-c)/2) = cos^2 (120) = 0.25
Sbc = sin^2 ((b-c)/2) = sin^2 (60) = 0.75
Sac = sin^2 ((a-c)/2) = sin^2 (120) = 0.75
Cbc = cos^2 ((b-c)/2) = cos^2 (60) = 0.25

So, Pab++=P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6=(2*0.75 + 0.25*0.75 + 0.75*0.25)/6 = 1.875/6 = 0.3125

But if Pab++ = 0.3125 using your formulas with the specified angles, then clearly it is not true that Pab++=Sab/2 according to your formulas, since Sab/2 = 0.75/2 = 0.375 (and this would be the answer predicted by QM, so if Pab++=P3+P4 and we use the values of P3 and P4 in your table, we get an answer which differs from QM here). Nor are either of these equal to (2Sab + 2Pab++)/6, this would be equal to (2*0.75 + 2*0.3125)/6 = (1.5 + 0.625)/6 = 2.125/6 = 0.3541666... So, you must have goofed in the step where you equated (2Sab + Cac.Sbc + Sac.Cbc)/6 to (2Sab + 2Pab++)/6.

edit #2: Perhaps the reason for this erroneous substitution of Cac.Sbc + Sac.Cbc = 2Pab++ is that you were using 2Pab++=2P3 + 2P4 combined with the original definitions of P3 and P4 in your original post on this thread? But that will not do, because the definitions of P3 and P4 in your original post are incompatible with the definitions of P3 and P4 in the PDF table. For example, in the original post you define P3 = Cac.Sbc/2, which for the angles a=240, b=120 and c=0 is equal to 0.25*0.75/2 = 0.09375...whereas in the PDF table you define P3 = [Sab.Cac + Sab.Sbc + Cac.Sbc]/6, which for the same angles is equal to [0.75*0.25 + 0.75*0.75 + 0.25*0.75]/6 = 0.15625. So you have to pick one or the other, you can't use both definitions for P3.
 
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  • #63
JesseM said:
I would not be OK with this, I think you are using this forum as a platform for advertising a crackpot theory that you are already totally confident is right, rather than just exploring the issue in an open-minded way that acknowledges the strong likelihood that it is you who have made an error somewhere in your analysis, and making a sincere effort to listen to critiques in order to identify likely errors.

Indeed, I fully agree with this. Remember that there was "permission to post your 8 numbers" for pedagogical reasons, but there seems not to be much pedagogy happening.

So, to be clear: NO, JenniT, you are NOT allowed to open yet another thread on this same subject.
 
  • #64
I've been following this thread and haven't wanted to post in it so as not to disrupt it's thematic flow (such as it was), however since JenniT has said that she will be off the internet for several days, then I hope it's ok. Nothing Earth'shaking, but some progress in my understanding -- I think.

I hadn't until recently understood the significance of DrChinese's Local Realistic (LR) dataset requirement wrt evaluating proposed LR models of entanglement. Comments in this and other recent threads have helped to clarify my thinking on this subject -- which has led me to a better understanding of why explicitly local hidden variable models of entanglement can't possibly reproduce the range of the qm statistical predictions.

Wrt what constitutes an LR model, it might be phrased that it's the explicit representation of locality (which entails an explicit representation of the local hidden variables that are relevant wrt the production of the local facts of individual measurements, which in turn imposes a constraint on the range of the predictions that any such model of entanglement can produce) that defines a model as LR, and not only whether the model satisfies Bell's inequality (BI).

However, insofar as Bell's LR model is the archetypal LR model1 of entanglement, a necessary condition for a model to be considered LR is that it must satisfy BI.

Hence, any proposed LR model that violates BI is, by definition, not an LR model. On the other hand, it's been definitively shown that any proposed LR model that satisfies BI can't possibly reproduce the qm predictions (or, as has also been definitively demonstrated2, be in agreement with experimental results).

So, there doesn't seem to be any point in considering any proposed LR model of entanglement.

Exactly what BI is implying or has to do with the deep reality underlying instrumental results is another question, the answer to which is, imho ... nothing. BIs are statements about the constraints on the relationship between joint polarizer settings and joint detection attributes (where individual detection attributes are limited to values of 0 and 1) given certain formal, LR, requirements.

-----------------------------------------

1Bell's ansatz is the archetypal LR model of entanglement because it encodes both an explicit expression of locality and an explicit expression of the hidden variables which produce the local experimental facts.

2There's some disagreement about this, but the experimental loophole considerations have, imho, turned out to be strawman or superfluous considerations wrt the correct interpretation of the physical meaning of Bell's theorem.
 
  • #65
JenniT said:
OK; thank you; your post came in as I was posting my last.

Q: Do you not see that all the sums that you could possibly require are included in -- or easily derived from -- the base-data in the PDF.

Q: I left many more sums for the reader to complete. Do you want to see any of them?

NB: I ABSOLUTELY REJECT:

P(a+, b+) = P3 + P4 and P(a+, c+) = P2 + P4 and P(c+, b+) = P3 + P7

IF IT IMPLIES: P3 + P4 = P3 + P4 + (POSITIVE NUMBER)!
(XXX)

Q: Seriously: In case I misinterpret: Is equation (XXX) what you want me to accept?

Of course not.
That is NOT what the Bell inequalities imply.

What the Bell inequalities imply is the following:

IF YOU ASSUME that all of the emitted the pairs have PREDESTINED responses to 3 possible measurements on both sides independent of which of these three measurements is actually going to be performed (this is the LOCAL REALISM ASSUMPTION), THEN there exist 8 numbers P1...P8 such that
P(a+,b+) = P3 + P4
P(a+,c+) = P2 + P4
and P(c+,b+) = P3 + P7

The 8 numbers P1...P8 come from the 8 different possibilities to predestine responses.

IF that is the case, then it is simple arithmetic to show that:

P(a+,c+) + P(c+,b+) = (P2 + P4) + (P3 + P7) = P3 + P4 + P2 + P7
= P(a+,b+) + P2 + P7.

And from this follows that IT WILL BE IMPOSSIBLE to find 8 such numbers and to obtain that P(a+,b+) is larger than P(a+,c+) + P(c+,b+), no matter what funny theory GENERATES these numbers. You cannot have that P3 + P4 is LARGER than P3 + P4 + positive number.

Now, quantum mechanics DOES NOT assume that the pairs are predestined, so in quantum mechanics there is no such a priori existence for 8 such numbers.
AND it turns out that for specific experiments with pairs of electrons, we can find 3 measurements on both sides such that the QM predictions for P(a+,c+), P(c+,b+) and P(a+,b+) are such that P(a+,b+) is larger than the sum of P(a+,c+) and P(c+,b+).

Note that in QM, P(a+,b+) must not be equal to some P3 + P4. It is only if you claim that you have an EQUIVALENT LOCAL REALISTIC THEORY which predestines the pairs that these numbers P1...P8 have a meaning, and then you run in the impossibility that you should have that these numbers satisfy that P3 + P4 > P3 + P4 + positive number (namely P2 + P7).

Now, YOU CLAIMED that you could provide us with 8 such numbers. Clearly you haven't. (and clearly it is impossible). You asked if you could show them. For sake of pedagogy, you were allowed to "show" us those impossible numbers (I told you so).

Your numbers do NOT reproduce the QM predictions. They do so for 2 out of 3 (you can ALWAYS do it for 2 out of 3) and they fail (of course) for the 3rd prediction, because if they wouldn't, they'd satisfy impossible conditions.

Now, you have been talking A LOT here, not learning a lot.

PS: I believe in my theory; and QM; and I will answer every question.

Up to now, you haven't.

You mentioned a game, which had me confused. I had hoped that the PDF showed my response to ANY game played with EPRB?

Your PDF doesn't show anything, except for a specific calculation of 8 numbers, 8 numbers which DO NOT correspond to the predictions of QM.
 
  • #66
vanesch said:
Of course not.
That is NOT what the Bell inequalities imply.

What the Bell inequalities imply is the following:

IF YOU ASSUME that all of the emitted the pairs have PREDESTINED responses to 3 possible measurements on both sides independent of which of these three measurements is actually going to be performed (this is the LOCAL REALISM ASSUMPTION), THEN there exist 8 numbers P1...P8 such that
P(a+,b+) = P3 + P4
P(a+,c+) = P2 + P4
and P(c+,b+) = P3 + P7

The 8 numbers P1...P8 come from the 8 different possibilities to predestine responses.

IF that is the case, then it is simple arithmetic to show that:

P(a+,c+) + P(c+,b+) = (P2 + P4) + (P3 + P7) = P3 + P4 + P2 + P7
= P(a+,b+) + P2 + P7.

And from this follows that IT WILL BE IMPOSSIBLE to find 8 such numbers and to obtain that P(a+,b+) is larger than P(a+,c+) + P(c+,b+), no matter what funny theory GENERATES these numbers. You cannot have that P3 + P4 is LARGER than P3 + P4 + positive number.

Now, quantum mechanics DOES NOT assume that the pairs are predestined, so in quantum mechanics there is no such a priori existence for 8 such numbers.
AND it turns out that for specific experiments with pairs of electrons, we can find 3 measurements on both sides such that the QM predictions for P(a+,c+), P(c+,b+) and P(a+,b+) are such that P(a+,b+) is larger than the sum of P(a+,c+) and P(c+,b+).

Note that in QM, P(a+,b+) must not be equal to some P3 + P4. It is only if you claim that you have an EQUIVALENT LOCAL REALISTIC THEORY which predestines the pairs that these numbers P1...P8 have a meaning, and then you run in the impossibility that you should have that these numbers satisfy that P3 + P4 > P3 + P4 + positive number (namely P2 + P7).

Now, YOU CLAIMED that you could provide us with 8 such numbers. Clearly you haven't. (and clearly it is impossible). You asked if you could show them. For sake of pedagogy, you were allowed to "show" us those impossible numbers (I told you so).

Your numbers do NOT reproduce the QM predictions. They do so for 2 out of 3 (you can ALWAYS do it for 2 out of 3) and they fail (of course) for the 3rd prediction, because if they wouldn't, they'd satisfy impossible conditions.

Now, you have been talking A LOT here, not learning a lot.
Up to now, you haven't.
Your PDF doesn't show anything, except for a specific calculation of 8 numbers, 8 numbers which DO NOT correspond to the predictions of QM.
I hope this addresses the issues above:

Let us take: ab = 90, ac = bc = 45.

From the PDF, I derive in the given worked example:

Pab++ = Sab/2 = 0.25.

In similar manner, I derive (and will add as an addendum when I get back)

Pac++ = Sac/2 = 0.0732

Sbc++ = Sbc/2 = 0.0732

I thought that these were the QM predictions?

PS: I'm learning a great deal, and am sorry if I'm trying your patience. But can you see here why I must ask another question?

So please: Let me have the next specific question that now arises from you, re the above. For it seems to me that the problem must be somewhere else.

PS: If you doubt my calculations; well, when I put them into an Appendix you will see the same method as in the PDF example, and the same answers that I have given above.

Q: I might ask: Why do you say that the PDF numbers are wrong? I thought that QM had no such predictions for the table?

I've asked to see them, but so far have not.

Thank you.
 
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  • #67
JesseM said:
And how did you calculate these answers?? I just want a yes or no answer to the question of whether you use the formulas Pab++ = P3 + P4 and Pac++ = P2 + P4 and Pcb++ = P3 + P7, I won't discuss any further issues if you continue to be evasive on this simple question. It's obvious that if you do use these formulas, you will not get the QM predictions of Pab++=Sab/2, Pac++=Sac/2, and Pcb++=Scb/2 (if you think you will, you have made a math error somewhere)

The Pab++ example can be checked right now. It is the worked example in the PDF.

A math error there will be repeated in an addendum that I'll add when I get back; giving the other workings, and those values I have already given to you.

JesseM said:
edit: and speaking of math errors, your derivation in the PDF for Pab++=P3+P4=Sab/2 doesn't work. I'm fine up to the step where P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6, but how do figure that this would be equal to (2Sab + 2Pab++)/6? That's clearly wrong if you substitute some actual angles, like the earlier example of a=240,b=120 and c=0. In this case we have:

Sab=sin^2 ((a-b)/2) = sin^2 (60) = 0.75
Cac=cos^2 ((a-c)/2) = cos^2 (120) = 0.25
Sbc = sin^2 ((b-c)/2) = sin^2 (60) = 0.75
Sac = sin^2 ((a-c)/2) = sin^2 (120) = 0.75
Cbc = cos^2 ((b-c)/2) = cos^2 (60) = 0.25

So, Pab++=P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6=(2*0.75 + 0.25*0.75 + 0.75*0.25)/6 = 1.875/6 = 0.3125

But if Pab++ = 0.3125 using your formulas with the specified angles, then clearly it is not true that Pab++=Sab/2 according to your formulas, since Sab/2 = 0.75/2 = 0.375 (and this would be the answer predicted by QM, so if Pab++=P3+P4 and we use the values of P3 and P4 in your table, we get an answer which differs from QM here). Nor are either of these equal to (2Sab + 2Pab++)/6, this would be equal to (2*0.75 + 2*0.3125)/6 = (1.5 + 0.625)/6 = 2.125/6 = 0.3541666... So, you must have goofed in the step where you equated (2Sab + Cac.Sbc + Sac.Cbc)/6 to (2Sab + 2Pab++)/6
.

This is rushed, but are you looking at the right table. The PDF has the correct result. The 3 earlier labels, as explained, had one angle not specifically specified. A problem resolved when the 3 were amalgamated to give the PDF.

The PDF amalgamates the 3 earlier tables; all angles are there specific.

JesseM said:
edit #2: Perhaps the reason for this erroneous substitution of Cac.Sbc + Sac.Cbc = 2Pab++ is that you were using 2Pab++=2P3 + 2P4 combined with the original definitions of P3 and P4 in your original post on this thread? But that will not do, because the definitions of P3 and P4 in your original post are incompatible with the definitions of P3 and P4 in the PDF table. For example, in the original post you define P3 = Cac.Sbc/2, which for the angles a=240, b=120 and c=0 is equal to 0.25*0.75/2 = 0.09375...whereas in the PDF table you define P3 = [Sab.Cac + Sab.Sbc + Cac.Sbc]/6, which for the same angles is equal to [0.75*0.25 + 0.75*0.75 + 0.25*0.75]/6 = 0.15625. So you have to pick one or the other, you can't use both definitions for P3.


Just off the cuff, [for now] as above, the 3 earlier tables were required by my model to produce the PDF. The PDF is the model; the others were steps in the model building because I could not handle my "angle" problem any other way.

The substitutions that you query are given in post #33.

There you will see: Pab++ = P3 + P4 = (Cac.Sbc + Sac.Cbc)/2.

And all the other such.

That is where the queried substitution comes from.

Excuse rush.
 
  • #68
I must interject here. Either the mentors and science advisors are capable of explaining clearly and succincltly why prospective LR theories are pointless, or they aren't capable of doing that. There's nothing to be learned by this nitpicking -- imho.

Refer back to DrC's post. (#2?, iirc)

If the proposed LR model doesn't produce an LR dataset (and therefore satisfy BI), then it isn't an LR model. Period.

And if it does produce an LR dataset then it can't agree with qm (and, so far and presumably, with experimental results). Period.

There's nothing else to consider. LR models of entanglement are impossible. Period.

What does this tell us of the underlying reality? Nothing. Period.
 
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  • #69
JenniT said:
I hope this addresses the issues above:

Let us take: ab = 90, ac = bc = 45.

From the PDF, I derive in the given worked example:

Pab++ = Sab/2 = 0.25.

In similar manner, I derive (and will add as an addendum when I get back)

Pac++ = Sac/2 = 0.732

Sbc++ = Sbc/2 = 0.732

I thought that these were the QM predictions?

Clearly, it can't. (there's a typo for Pac++ and Pbc++ where the values are 0.0732, but I guess this is a typo).

I didn't check your pdf in detail, but in your pdf, you (correctly) define:

Pab++ = P3 + P4

You work this out to something (I didn't check the goniometric algebra), but it equals P3 + P4.

You didn't work out the rest, but if it is done correctly, you should also have:

Pcb++ = P3 + P7

and

Pac++ = P2 + P4.

It is a pity that you didn't work it out.

Now, I can assume that the numerical value of P3 + P7 doesn't change between when you write it as P3 + P7, and when you work out the goniometric algebra :wink:
(otherwise you made a mistake in your algebra, right ?)

Now, give me please the NUMERICAL VALUES for a vertically, c 45 degrees towards the window, and b horizontal towards the window (so 90 degrees), for all 8 values P1, ... P8 and then for your calculation of Pab++ , Pac++ and Pcb++.

Because it should be obvious that if all your values P1...P8 are positive numbers, and if Pab++ = P3 + P4 and so on as you claim (correctly), that you CANNOT obtain numerically Pab++ = 0.25 and Pac++ = Pcb++ = 0.073...

So in order to show you this, you should work out, for the given angles, the numbers P1 up to P8, and then Pab++ = P3 + P4 and also according to your algebra Sab/2 and Pcb++ and Pac++.
 
  • #70
ThomasT said:
I must interject here. Either the mentors and science advisors are capable of explaining clearly and succincltly why prospective LR theories are pointless, or they aren't capable of doing that. There's nothing to be learned by this nitpicking -- imho.

Well this thread is the result of a request by JenniT that he/she COULD generate 8 numbers P1...P8 such that it corresponded to the quantum predictions. This is clearly impossible, but up to now JenniT has been claiming otherwise.

His/her first attempt gave:

QM: 0.25, 0.073, 0.073 (for spin-1/2 particles and axes 0 degrees, 45 degrees and 90 degrees) and JenniT produced a first set of 8 numbers such that the numbers that came out were 0.125, 0.073 and 0.073, and there was a lot of hot air about a claim that these WERE the right results because of "an average that had to be taken over two different angles" without ever having cleared this up.

Now we seem to have ANOTHER proposal by JenniT where he/she claims this time to HAVE produced 8 numbers such that the predictions come out to be:

0.25, 0.073 and 0.073

after some algebra.

As this is algebraically impossible, we ask him to give us the 8 numerical values, and show how they comply with the above calculation.


There's nothing else to consider. LR models of entanglement are impossible. Period.

You're right, but we're dealing with somebody who claims he knows how to make one.
 
  • #71
JenniT said:
The Pab++ example can be checked right now. It is the worked example in the PDF.
Yes, I checked it, and it was wrong.
JenniT said:
This is rushed, but are you looking at the right table. The PDF has the correct result.
Yes, I was looking just at the PDF. There you write that

Pab++=P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6=(2Sab + 2Pab++)/6=Sab/2

But with the specific examples I gave of a=240,b=120,c=0 it is trivial to see that they are not equal:

(2Sab + Cac.Sbc + Sac.Cbc)/6=0.3125

Sab/2=0.375

So these are not equal to one another, and if we use Pab++=0.3125 neither of these is equal to (2Sab + 2Pab++)/6=0.3541666... If we use Pab++=0.375 then it is true that (2Sab + 2Pab++)/6 = Pab++, but neither of these is consistent with the earlier equation in the PDF saying that Pab++=P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6.
JenniT said:
The substitutions that you query are given in post #33.

There you will see: Pab++ = P3 + P4 = (Cac.Sbc + Sac.Cbc)/2.
In post #33 you continue to use the incomprehensible language of "bi-angles", but in any case it's clear that the equation Pab++ = P3 + P4 = (Cac.Sbc + Sac.Cbc)/2 from post #33 is inconsistent with the PDF's equation of Pab++=P3+P4=(2Sab + Cac.Sbc + Sac.Cbc)/6, because with a=240,b=120,c=0 we have:

(Cac.Sbc + Sac.Cbc)/2 = (0.25*0.75 + 0.75*0.25)/2 = 0.1875

whereas

(2Sab + Cac.Sbc + Sac.Cbc)/6=(2*0.75 + 0.25*0.75 + 0.75*0.25)/6 = 1.875/6 = 0.3125

and neither of these are equal to

Sab/2 = 0.375

Please check this numerical example yourself before responding, you'll see that what I say is correct.
 
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  • #72
ThomasT said:
Refer back to DrC's post. (#2?, iirc)

If the proposed LR model doesn't produce an LR dataset (and therefore satisfy BI), then it isn't an LR model. Period.

And if it does produce an LR dataset then it can't agree with qm (and, so far and presumably, with experimental results). Period.

There's nothing else to consider. LR models of entanglement are impossible. Period.

What does this tell us of the underlying reality? Nothing. Period.
Thomas, you seem to be arguing as if "local realist" is defined to mean you must have a dataset of predetermined values, but this isn't true. As I said in post #20 to Avodyne:
JesseM said:
Not all Bell inequalities assume that the hidden variables totally determine what the response to any given angle will be, see the CHSH inequality for example where the angles a,a' used on one side may be different from the angles b,b' on the other in which case there'd be no combination of settings where knowledge of the result on one side gives you total certainty about the result on the other. I like to think of the definition of local realism this way:

1. The complete set of physical facts about any region of spacetime can be broken down into a set of local facts about the value of variables at each point in that regions (like the value of the electric and magnetic field vectors at each point in classical electromagnetism)

2. The local facts about any given point P in spacetime are only causally influenced by facts about points in the past light cone of P, meaning if you already know the complete information about all points in some spacelike cross-section of the past light cone, additional knowledge about points at a spacelike separation from P cannot alter your prediction about what happens at P itself (your prediction may be a probabilistic one if the laws of physics are non-deterministic).

From this it follows that if two experimenters making measurements at a spacelike separation are guaranteed to get the same result when they choose the same angle, despite the fact that they pick which angle to use at random, then the results for each possible angle must have already predetermined by facts in their past light cone (like facts about the hidden variables associated with each particle) at some time T after the particles had been emitted but before they picked their angles. But this is just a derived consequence of the notion of local realism above, not a definition of local realism.
Do you agree that no theory with characteristics 1 and 2 above (regardless of whether it involves datasets of predetermined results, and regardless of whether the local variables are hidden or measurable as in classical electromagnetism which does satisfy 1 and 2) could reproduce the statistics predicted by QM?
 
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  • #73
JesseM said:
Thomas, you seem to be arguing as if "local realist" is defined to mean you must have a dataset of predetermined values, but this isn't true.
I agree, see my post #64 in this thread. However, the LR dataset (ie., agreement with BI) is a necessary condition that any proposed LR model has to satisfy.

That's the beauty of DrC's LR dataset requirement and the math of Bell's theorem. It cuts through, ie. obviates, what you're going through here. I just didn't appreciate or understand it before because I was lost in the trees so to speak. If Jennit's model of entanglement agrees with qm and violates Bell's inequality, then, via the definition of an LR model a la Bell's archetype and your 1 and 2 (which entails that an LR model will satisfy Bell's inequality), it can't be an LR model of entanglement. The same holds for Christian's Clifford algebra C-space model, or Unnikrishnan's static phase relation (iirc) model or any other model that reproduces qm results and violates Bell's inequality.

JesseM said:
Do you agree that no theory with characteristics 1 and 2 above (regardless of whether it involves datasets of predetermined results, and regardless of whether the local variables are hidden or measurable as in classical electromagnetism which does satisfy 1 and 2) could reproduce the statistics predicted by QM?
Yes. The point is that a necessary condition for a theory to be called LR is that it has to produce datasets that don't agree with the qm predicted datasets -- ie., that it satisfies Bell's inequality.

And now I think I should probably delete my second, rather terse, post in this thread. I just had to savor the irony (recalling the countless interchanges that we've had on this subject). Or should I leave it? Your call.
 
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  • #74
ThomasT said:
Yes. The point is that a necessary condition for a theory to be called LR is that it has to produce datasets that don't agree with the qm predicted datasets -- ie., that it satisfies Bell's inequality.
OK good, I just wanted to make sure you understood that although satisfying Bell's inequality is a necessary consequence of the basic definition of LR, it isn't part of the definition itself (otherwise Bell would have no need for a "proof" that local realism implies the inequality is satisfied!) So I would disagree with your earlier statement "What does this tell us of the underlying reality? Nothing. Period." It tells us that QM is incompatible with any theory satisfying point 1) and 2) from my post to Avodyne, I would say that's a strong negative result ruling out a broad class of theories about the "underlying reality", although perhaps you just meant that it doesn't give us a positive answer to what the underlying reality actually is.
ThomasT said:
And now I think I should probably delete my second, rather terse, post in this thread. I just had to savor the irony (recalling the countless interchanges that we've had on this subject). Or should I leave it? Your call.
I don't think there's a need to delete it, perhaps the resulting discussion could clarify some things for people reading the thread.
 
  • #75
JesseM said:
OK good, I just wanted to make sure you understood that although satisfying Bell's inequality is a necessary consequence of the basic definition of LR, it isn't part of the definition itself (otherwise Bell would have no need for a "proof" that local realism implies the inequality is satisfied!)
Yes, I get this -- it just took a while.
JesseM said:
So I would disagree with your earlier statement "What does this tell us of the underlying reality? Nothing. Period." It tells us that QM is incompatible with any theory satisfying point 1) and 2) from my post to Avodyne, I would say that's a strong negative result ruling out a broad class of theories about the "underlying reality", although perhaps you just meant that it doesn't give us a positive answer to what the underlying reality actually is.
I mean that it doesn't tell us whether what's happening in the underlying reality is due to exclusively local interactions and transmissions or not. So, it doesn't contradict the general assumptions of locality and the existence of local hidden variables. It just tells us that explicitly LR formulations of entanglement must produce a reduced range of statistical predictions, and are therefore ruled out.

Why this is so is what Hess, Michielsen, and De Raedt are talking about in their recent paper on the subject.
 
  • #76
ThomasT said:
I mean that it doesn't tell us whether what's happening in the underlying reality is due to exclusively local interactions and transmissions or not.
How do you figure? Wouldn't any theory about the underlying reality which involves "exclusively local interactions and transmissions" satisfy 1) and 2) in my description of local realism?
ThomasT said:
So, it doesn't contradict the general assumptions of locality and the existence of local hidden variables.
I don't understand why you would distinguish "the general assumptions of locality and the existence of local hidden variables" from "local realism" as described by 1) and 2). Are you imagining there could be a local theory involving local hidden variables which violated either 1) or 2) (or both)? If so which would it violate?
 
  • #77
Sorry for jumping in,
but (on a psycological level) why "die hard local realists" (c) Dr. Chinese
never consider just using MWI to obtain the result they want?
 
  • #78
vanesch said:
Clearly, it can't. (there's a typo for Pac++ and Pbc++ where the values are 0.0732, but I guess this is a typo).

I didn't check your pdf in detail, but in your pdf, you (correctly) define:

Pab++ = P3 + P4

You work this out to something (I didn't check the goniometric algebra), but it equals P3 + P4.

You didn't work out the rest, but if it is done correctly, you should also have:

Pcb++ = P3 + P7

and

Pac++ = P2 + P4.

It is a pity that you didn't work it out.

Now, I can assume that the numerical value of P3 + P7 doesn't change between when you write it as P3 + P7, and when you work out the goniometric algebra :wink:
(otherwise you made a mistake in your algebra, right ?)

Now, give me please the NUMERICAL VALUES for a vertically, c 45 degrees towards the window, and b horizontal towards the window (so 90 degrees), for all 8 values P1, ... P8 and then for your calculation of Pab++ , Pac++ and Pcb++.

Because it should be obvious that if all your values P1...P8 are positive numbers, and if Pab++ = P3 + P4 and so on as you claim (correctly), that you CANNOT obtain numerically Pab++ = 0.25 and Pac++ = Pcb++ = 0.073...

So in order to show you this, you should work out, for the given angles, the numbers P1 up to P8, and then Pab++ = P3 + P4 and also according to your algebra Sab/2 and Pcb++ and Pac++.



Thanks for your patience and blunder-identification (which I've corrected via an edit). Time-pressure is the excuse; trying to hold up my end of this thread.

That blunder is the message for now:

I've made a big mistake in trying to do my bit here and keep my end of the thread moving while snowed-under with other critical commitments: because I am lapping up the teaching and I'm keen to get to the end.

I even delayed my departure, that's how I'm here, to get some further calcs and answers out.

So: Thanks again; I shall return; your specific questions addressed; quick calcs and answers to follow later -- now to be happily reviewed more carefully first.

The hope for us all, if I may add some hope, is that the arguments will be resolved via maths, not words. That I am happy with; that I learn best from. XO
 
  • #79
JesseM said:
How do you figure? Wouldn't any theory about the underlying reality which involves "exclusively local interactions and transmissions" satisfy 1) and 2) in my description of local realism?
Yes, but that doesn't imply that the constraints on statistical predictions associated with the formal LR requirements are due to an underlying nonlocality. I mean, you can interpret it that way, but I don't think you have to. Isn't it at least possible that the effective determiner of BI violations has to do with some more mundane conflict between the LR formalism and the experimental design and preparation of Bell tests than with the existence of nonlocal signals or the nonexistence of local hidden variables?

JesseM said:
I don't understand why you would distinguish "the general assumptions of locality and the existence of local hidden variables" from "local realism" as described by 1) and 2).
As DrC's signature quotes from Korzybski, "The map is not the territory." (Did I get that right?)

JesseM said:
Are you imagining there could be a local theory involving local hidden variables which violated either 1) or 2) (or both)?
No. I'm just holding out for a more parsimonious explanation for BI violation (that I fully understand) than that it's due to nonlocality. Who knows, maybe I'll eventually think that Bell's theorem proves nonlocality, but right now that doesn't seem likely.

Edit: Apologies to JenniT for somewhat off topic posts. I thought you were going to be away for a while and I wanted to express and clarify my thinking on this. Anyway, I'll post no more in this thread so that you might continue your presentation and argument.
 
  • #80
ThomasT said:
Yes, but that doesn't imply that the constraints on statistical predictions associated with the formal LR requirements are due to an underlying nonlocality.
I didn't use the word "nonlocality", I just said that a theory of the type described by 1) and 2) was ruled out. As you know from previous discussions there are certain "loopholes", for example I was implicitly assuming in 1) that there is a unique set of physical facts about each point in spacetime and so a unique result to any specific measurement, if you drop this and imagine multiple parallel versions of a measurement occurring in the same region of spacetime as in the MWI, then you may be able to explain the quantum statistics without violating locality. Similarly if you imagine the experimenter's choice of what detector setting to use on each trial is not actually uncorrelated with the local variables associated with the particle immediately after emission, so that you have a sort of retrocausal effect where the particle "anticipates" what the future detector setting will be, then one might argue that this would be compatible with locality as well (though some might argue that retrocausal influences don't count as "local").
ThomasT said:
As DrC's signature quotes from Korzybski, "The map is not the territory." (Did I get that right?)
I don't see how that statement is applicable here. Would you describe statements 1) and 2) about the nature of physics as "map" or "territory"? Whichever you'd choose, I don't see why you'd say that "the general assumptions of locality and the existence of local hidden variables" was any different. And logically, if you agree that "the general assumptions of locality and the existence of local hidden variables" (or 'exclusively local interactions and transmissions") would be false if 1) and 2) were false, then if QM is incompatible with 1) and 2) that shows it's also incompatible with "the general assumptions of locality and the existence of local hidden variables" regardless of what you call "map" and what you call "territory".
 
  • #81
JesseM said:
1. The complete set of physical facts about any region of spacetime can be broken down into a set of local facts about the value of variables at each point in that regions (like the value of the electric and magnetic field vectors at each point in classical electromagnetism)

2. The local facts about any given point P in spacetime are only causally influenced by facts about points in the past light cone of P, meaning if you already know the complete information about all points in some spacelike cross-section of the past light cone, additional knowledge about points at a spacelike separation from P cannot alter your prediction about what happens at P itself (your prediction may be a probabilistic one if the laws of physics are non-deterministic).

JesseM said:
I don't understand why you would distinguish "the general assumptions of locality and the existence of local hidden variables" from "local realism" as described by 1) and 2).
My current thinking is that 1) is obviated by the experimental design of Bell tests. Accurately predicting entanglement correlations simply doesn't require breaking things down into sets of local facts. It's because of the inclusion of a local hidden variable lambda in the formulation that the range of statistical predictions is reduced.

2) entails a formalism that contradicts both parameter and outcome dependence. But outcome dependence doesn't contradict locality, thus facilitating a more parsimonious explanation for why BIs are violated than the existence of underlying nonlocal transmissions.
 
  • #82
JesseM said:
... I just said that a theory of the type described by 1) and 2) was ruled out.
And we're in agreement on that, which represents progress in my understanding. Maybe we should just leave it at that for the time being and I'll stay out of the thread.
 
  • #83
ThomasT said:
My current thinking is that 1) is obviated by the experimental design of Bell tests.
Purely by the design of the tests, or by the resulting statistics? If you just think that the design itself is enough to obviate 1) you are misunderstanding something, you could certainly do the same sort of tests in a universe where classical electromagnetism was exactly correct and 1) and 2) would both be correct there, you just wouldn't get any statistics that violated Bell inequalities in this case. Keep in mind that 1) doesn't forbid you from talking about "facts" that involve an extended region of spacetime, it just says that these facts must be possible to deduce as a function of all the local facts in that region. For example, in classical electromagnetism we can talk about the magnetic flux through an extended 2D surface of arbitrary size, this is not itself a local quantity, but the total flux is simply a function of all the local magnetic vectors at each point on the surface, that's the sort of thing I meant when I said in 1) that all physical facts "can be broken down into a set of local facts". Similarly in certain Bell inequalities one considers the expectation values for the product of the two results (each one represented as either +1 or -1), obviously this product is not itself a local fact, but it's a trivial function of the two local facts about the result each experimenter got.
ThomasT said:
2) entails a formalism that contradicts both parameter and outcome dependence. But outcome dependence doesn't contradict locality, thus facilitating a more parsimonious explanation for why BIs are violated than the existence of underlying nonlocal transmissions.
Not sure what you mean by "parameter and outcome dependence", can you be more specific? Again, 1) and 2) are definitely true of classical electromagnetism, if you think they aren't (for any conceivable experiment in a universe where classical electromagnetism was exactly true) then you are misunderstanding something (do you think any possible experiment in such a universe would display parameter and/or outcome dependence?)
 
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  • #84
I'm back. And happy to be so.

Apologies for my absence; me recognizing my part in this tread. And many thanks to all participants.

Absences will continue sporadically. But there's no need for me to signal them: In that I am committed to answer every question here, you can rest assured that I have not quit ... until I say so.

If a final post sinks my model, then you can expect me to acknowledge that, and move happily on.

I have no problem correcting my wrong beliefs and moving on to new (and better) ones.

I trust the above is a satisfactory part-reply to TomT. Note that my maths is elementary, and supports what I would have thought to be a reasonable LR position for you. More re DrC's position soon, that might interest you.

To Avodyne, OK, and fair enough. But I hope to go beyond semantics and hand-waving.

To Dmitry67, thanks for your post! I'm very happy to spar with physicists who have neither knuckle-dusters, nor FTL, not NL, in their gloves. If I survive this warm-up bout, I might be ready for this one: What's wrong with this One World Interpretation of MWI? Until then, thanks again.

More soon, with a focus on technical issues raised by DrC, JesseM, vanesch.

XO-s and thanks again to all,

JenniT
 
  • #85
DrChinese said:
The criticism is the same for all such: it isn't realistic! ("So any inference to a third side will be misleading. ")

If it is, simply provide a dataset for us to look at. 0, 120, 240 degrees is always a good combo to supply. We will see if the QM predictions hold.

DrChinese said:
I will repeat my main objection again: it's not realistic if you do not provide values for measurements which cannot be performed. That is the definition of "realistic".

The "confusion" issue is: to the extent anyone agrees with you, we are simply talking about the usual approach to Bell or a closely related equivalent variation. To the extent you assert you have provided a LR counter-example, we keep explaining that actually you have violated the requirement of L locality or R realism despite your words. You cannot just wave your hands and say you have accomplished this without pointing us to some new revelation. I see nothing novel in your approach at all, and it seems to follow your arguments presented in other threads.

Where's the beef? :smile: It would really be nice if you would show us something new to discuss rather than just say "I'm right unless you show me where am I wrong".

I have tidied up the presentation, in the attached PDF, in the hope of minimising confusion: and would welcome your comments on it; plus:

Do most of the Tables give results for experiments that cannot be performed? (I think that they do.)

Can you point to any hand-waving in the PDF please? (I am keen to delete any such.)

Could we discuss a protocol for studying your 0, 120, 240 example; along the lines of Figure 1 in the PDF, and related commentary thereunder? (I would be happy to derive the subsequent results.)

PS: For JesseM and vanesch: I am working on replies to your welcome technical queries; please don't despair.

And thank you, as always, DrC.
 

Attachments

  • #86
JenniT said:
I have tidied up the presentation, in the attached PDF, in the hope of minimising confusion: and would welcome your comments on it; plus:

Do most of the Tables give results for experiments that cannot be performed? (I think that they do.)

Can you point to any hand-waving in the PDF please? (I am keen to delete any such.)

Could we discuss a protocol for studying your 0, 120, 240 example; along the lines of Figure 1 in the PDF, and related commentary thereunder? (I would be happy to derive the subsequent results.)

PS: For JesseM and vanesch: I am working on replies to your welcome technical queries; please don't despair.

And thank you, as always, DrC.

Re the above post by me:

A. I suggest that we refer to the PDF (attached to the above post) as PDF2.

B. CORRECTIONS to PDF2:

1. Equation (A3a); the last term should read [Sbc + P(bc++|a)]/3.

2. In the second line of the Headings to Tables A1.a, A2.b, A3.c: delete the 2.
 
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  • #87
vanesch said:
I highlighted what we need: Pac++, Pab++ and Pcb++=Pbc--

Pac++ is what is measured on monday, and equals 0.073... in agreement with your numbers
Pab++ is what is measured on tuesday, and equals 0.25. Your number gives 0.125
Pcb++=Pbc-- is what is measured on thursday, and equals 0.073 in agreement with your numbers.

You will NEVER be able to get Pab++ equal to 0.25 (you actually have 0.125), simply because it can't be larger than (Pac++) + (Pbc--) which equals 0.146...
Note that indeed, your number (0.125) is, as it can't be otherwise, smaller than 0.146.
Simply because this 0.146 is made up of your 4 positive numbers P2 + P3 + P4 + P7 as you give it yourself, and Pab++ is equal to only P3+P4 (your 0.125). You ADD to your 0.125 still your P2 and P7 to obtain 0.146, so it has to be smaller (as indeed it is).

Now, QM predicts not 0.125, but rather 0.25. It is bigger. So it can't come from numbers P1...P8 in this way.

There's nothing more to say about this.
JenniT said:
Please refer to PDF2, attached at this post

In PDF2 (see above), I have clarified the notation by including the conditioning space in every Probability function. That conditioning, now explicit, was implicit (as you will see) in the example that you cite. The RO was given as c, and the output statement was explicit in referring Pab to = the average over the bi-angle. [2Pab corrected to Pab.]

That is, as also in PDF2: Pab(++|c) = P3 + P4 = (Cac.Sbc + Sac.Cbc)/2.

So we now examine your relations with the implicit conditioning space now explicit (as in PDF2, Table A3.c):

A: P(ac++|c) is what is measured on Monday, and equals 0.073 in agreement with my numbers.

B: P(ab++|c) [SIC] is what is measured on Tuesday, and equals 0.25. [I agree with 0.25. BUT you say that my number gives 0.125: Your statement is incorrect -- as shown below.]

C: P(cb++|c) =P(bc--|c) is what is measured on Thursday, and equals 0.073 in agreement with my numbers.

So our disagreement is at B only ... and, I believe, readily turned to agreement:

Please note that what is measured on Tuesday is P(ab++|ab) or P(ab++|a) or P(ab++|b)! With my model, you have three choices as to how you define it. And from PDF2, all equal Sab/2 = 0.25. In full agreement with YOUR calculation.

The one choice that you cannot make (with my model) is this: That on Tuesday we measured P(ab++|c).

Reason: Orientation c was nowhere evident in Tuesday's test.

Tuesday's test used orientation a, orientation b, and angle ab; the model can work with any of these. BUT orientation c CANNOT appear in the conditioning space for Tuesday's test.

With this correction, which I trust you understand and accept, there is nothing more to say beyond this: We agree with the QM numbers that apply to the subject tests.

In that I said that my model correctly delivered all the QM results, this agreement was to be expected.

So let me now see if we can reach agreement re bi-angles: According to the model, Tuesdays bi-angles are 0 and 90, and the experimenters chose to measure over the 90 value: No problem whatsoever for the model. But note: One bi-angle value yields (S0)/2 = 0. The other bi-angle value yields (S45)/2 = 0.25. The average of these results is 0.125.

That is the origin of that 0.125 number; which is not the number applicable to the actual measurement made on Tuesday. The model gives BOTH numbers, and both correctly: The measured result is 0.25 (in full agreement with QM), and the average over the bi-angle 0.125.

Where we still differ is in the numbers that you invoke re the (supposedly) related Bell-inequality. But as PDF2 states: In agreement with QM (so in agreement between you and me, I'm sure), my model will disagree on numbers to do with BT.

So I will now move to reply to the post where you gave such numbers and, from memory, related them to an impossibility that is unrelated to my model. [The model does not fail when it comes to BT-based impossibilities. Rather, it shows that they cannot be rationally constructed from within. This is shown in PDF2, equation (?). Yes, equation(?), foot of page 4.]

I seek to show you that the L*R model again agrees with QM; here re the futility of any attempt to construct BT from within L*R.

In closing: I very much appreciate your attention to detail, and your engagement with the model. At the end of the day, I expect us both to agree on all the QM numbers. AND on QM's position that BT cannot be constructed from within QM.

I go on to say that BT cannot be constructed from within L*R ("advanced local realism"). So I see that that is where our discussion will head; e.g., is L*R truly L + R. In that MWI beats BT too, as I (preliminarily) understand it, it might boil down to us uniting L*R and MWI -- who knows --

With many thanks, as always; more soon.
 
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  • #88
You still seem to be talking about "bi-angles" in your pdf, and the diagram shows an experimental setup where, if "a" is an orientation pointing vertically, then there are two possible choices for the direction of "b" and two possible choices for the direction of "c". Please understand that this is not the experimental setup envisioned by Bell or the one that's used in actual Bell test experiments. In a Bell test experiment, the experimenters have pre-agreed on only three possible orientations for the Stern-Gerlach devices or polarizers--imagine that there's a clock face on the wall in front of the SG device used by one of the experimenters, and that experimenter must arrange his device so that the North end of the North-South axis of his device is either pointing in the same direction as 12 o'clock, 2 o'clock, or 4 o'clock, no other orientations are permitted (meanwhile the other experimenter is only allowed to pick orientations which would match up with the same readings in a mirror image of the first experimenter's clock). It is in this specific experiment that Bell said it would be impossible for a local realist theory to violate the Bell inequality, not the alternate setup you seem to be imagining where if "a" points at 12 o'clock "b" could either point at 2 o'clock or 12-2 = 8 o'clock. So, I hope you will take this into consideration and avoid all reference to "bi-angles" in any future response to me.
 
  • #89
JesseM said:
You still seem to be talking about "bi-angles" in your pdf, and the diagram shows an experimental setup where, if "a" is an orientation pointing vertically, then there are two possible choices for the direction of "b" and two possible choices for the direction of "c". Please understand that this is not the experimental setup envisioned by Bell or the one that's used in actual Bell test experiments. In a Bell test experiment, the experimenters have pre-agreed on only three possible orientations for the Stern-Gerlach devices or polarizers--imagine that there's a clock face on the wall in front of the SG device used by one of the experimenters, and that experimenter must arrange his device so that the North end of the North-South axis of his device is either pointing in the same direction as 12 o'clock, 2 o'clock, or 4 o'clock, no other orientations are permitted (meanwhile the other experimenter is only allowed to pick orientations which would match up with the same readings in a mirror image of the first experimenter's clock). It is in this specific experiment that Bell said it would be impossible for a local realist theory to violate the Bell inequality, not the alternate setup you seem to be imagining where if "a" points at 12 o'clock "b" could either point at 2 o'clock or 12-2 = 8 o'clock. So, I hope you will take this into consideration and avoid all reference to "bi-angles" in any future response to me.

OK; fair enough. But please see my most recent reply to vanesch re the conditioning spaces (of the probability functions), that must be applied to any real experiment carried out over 3 orientations. Also, equations (A0a) - (A0c), exemplifying the derivation of the QM results, make no mention of those angles. Do you see a problem with this equation set?

1. Without reference to any angles, other than those specifically tested (as requested), Table 2 in PDF2 provides all the testable probabilities; all in accord with QM. Do we agree on that? Does this Table, with supporting equations, answer some of your earlier questions re what it is that Table 1 delivers.

2. Note that the alternative "test-arrangements" were given in PDF2 as a way of illustrating what it is that L*R does. Do you believe that the allowance of these additional tests would somehow be the way that L*R breaches BT? (They are not.) Remember that Alice and Bob can move on to any RO, and L*R will still deliver the correct outcome distributions; see Table 2.

3. Moreover, from those correct distributions, L*R delivers precise values for any test set-up. As shown in PDF2, equation (?), there is no basis for a BI in L*R, anymore than there is such a basis within QM.

Many thanks.
 
  • #90
JenniT said:
OK; fair enough. But please see my most recent reply to vanesch re the conditioning spaces (of the probability functions), that must be applied to any real experiment carried out over 3 orientations.
Since I don't understand the meaning of your "reference orientation" I don't understand what type of "conditioning space" you are using, as in your response to vanesch you say "The RO was given as c" and then condition all your probabilities on c. Normally a probability like Pab(++) would be conditioned on the fact that Alice chose angle "a", Bob chose angle "b", while the specific values of "a", "b" and "c" would be assumed as part of the conditions of the experiment. Indeed that seems to be what you do in Table 2 of the pdf when you write conditional probabilities like P(ab++|ab), but elsewhere in the pdf (and in your response to vanesch) you condition on other things besides the choice of two detector settings on a given trial, I don't understand the reason for that.
JenniT said:
Also, equations (A0a) - (A0c), exemplifying the derivation of the QM results, make no mention of those angles. Do you see a problem with this equation set?
Where are equations (A0a) - (A0c)? If they're in the PDF, what page?
JenniT said:
1. Without reference to any angles, other than those specifically tested (as requested), Table 2 in PDF2 provides all the testable probabilities; all in accord with QM. Do we agree on that? Does this Table, with supporting equations, answer some of your earlier questions re what it is that Table 1 delivers.
No, I already showed the math for getting Table 2 from the probabilities in Table 1 doesn't work in [post=3159151]post 71[/post] which I hope you will review and respond to. If P(ab++|ab)=P3+P4, then according to Table 1 this will be:

[Sab.Cac + Sab.Sbc + Cac.Sbc]/6 + [Sab.Sac + Sab.Cbc + Sac.Cbc]/6 =
[Sab*(Cac + Sac) + Sab*(Sbc + Cbc) + Cac.Sbc + Sac.Cbc]/6 =
[2Sab + Cac.Sbc + Sac.Cbc]/6

And as I showed in post #71, for the angles a=240,b=120,c=0, this would be equal to 0.3125. But Table 2 claims that P(ab++|ab)=Sab/2, and for these angles Sab/2=0.375. So, the equations in Table 1 are inconsistent with Table 2, assuming you accept equations such as P(ab++|ab)=P3+P4.
JenniT said:
2. Note that the alternative "test-arrangements" were given in PDF2 as a way of illustrating what it is that L*R does. Do you believe that the allowance of these additional tests would somehow be the way that L*R breaches BT? (They are not.)
Your question makes no sense to me. The BT deal with a specific type of experiment, how would could the "allowance of additional tests" involving a totally different type of experiment be a way of breaching a theorem which doesn't address the second type of experiment at all? This is kind of like asking whether the "allowance" of an experiment on the breeding habits of Bengal tigers would "be the way that L*R breaches BT".
 
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  • #91
JesseM said:
Since I don't understand the meaning of your "reference orientation" I don't understand what type of "conditioning space" you are using, as in your response to vanesch you say "The RO was given as c" and then condition all your probabilities on c. Normally a probability like Pab(++) would be conditioned on the fact that Alice chose angle "a", Bob chose angle "b", while the specific values of "a", "b" and "c" would be assumed as part of the conditions of the experiment. Indeed that seems to be what you do in Table 2 of the pdf when you write conditional probabilities like P(ab++|ab), but elsewhere in the pdf (and in your response to vanesch) you condition on other things besides the choice of two detector settings on a given trial, I don't understand the reason for that.

A reference orientation is any pre-agreed orientation of a detector in a Bell-test experiment, the experimenters (Alice and Bob) having here pre-agreed to three such orientations. (Thank you.)

The conditioning space in P(X|C) is C; as usual. And, as usual, the boundary conditions on the experiment are implied. So, as I believe is customary, only special conditions are included specifically. Since P(ab++|ab) differs from P(ab++|c), the model includes both. P(ab++|ab) is the probability of ab++ when correlated across the angle ab. P(ab++|c) arises from the use of frames of reference in the model, as in my reply to vanesch. I'll address this when I revise; in that I will be removing the Bell-test objection that you raise with regard to multiple tests.

I honestly expected no resistance to ADDITIONAL tests, over all 3 reference orientations. And thought it (for present purposes), better, less novel, than introducing the local-realistic basis for L*R. Will fix.

JesseM said:
Where are equations (A0a) - (A0c)? If they're in the PDF, what page?

PDF2, Page 7.

JesseM said:
No, I already showed the math for getting Table 2 from the probabilities in Table 1 doesn't work in [post=3159151]post 71[/post] which I hope you will review and respond to. If P(ab++|ab)=P3+P4, then according to Table 1 this will be:

[Sab.Cac + Sab.Sbc + Cac.Sbc]/6 + [Sab.Sac + Sab.Cbc + Sac.Cbc]/6 =
[Sab*(Cac + Sac) + Sab*(Sbc + Cbc) + Cac.Sbc + Sac.Cbc]/6 =
[2Sab + Cac.Sbc + Sac.Cbc]/6

And as I showed in post #71, for the angles a=240,b=120,c=0, this would be equal to 0.3125. But Table 2 claims that P(ab++|ab)=Sab/2, and for these angles Sab/2=0.375. So, the equations in Table 1 are inconsistent with Table 2, assuming you accept equations such as P(ab++|ab)=P3+P4.

PDF2 was written to correct the hurried mess that was the first PDF, with its short-cuts; including short-cutting the conditioning space on any P; noting that all P are conditional to me, in that some conditions are inevitably implied or explicit. So, with apologies, PDF2 now spells out every calculation. Which will bring you to those darned angles.

JesseM said:
Your question makes no sense to me. The BT deal with a specific type of experiment, how would could the "allowance of additional tests" involving a totally different type of experiment be a way of breaching a theorem which doesn't address the second type of experiment at all? This is kind of like asking whether the "allowance" of an experiment on the breeding habits of Bengal tigers would "be the way that L*R breaches BT".

I thought that, when the L*R tests are conducted over every Bell-test detector setting (as they are; see Tables A1-A3), all we would have (and agree upon) is a more complete set of Bell-tests. I did not expect an objection to MORE tests; any component of which is a component of a Bell-test.

As for tigers: I thought that I was breeding Bell-tests.

So, for me, the question remains: Given that Table 2, PDF2, will remain unchanged, and since it applies to any Bell-test that you might nominate, how will a Bell Inequality be constructed?

To take a common example: How will P(ab++|ab) be yoked to P(ac++|ac) and P(bc++|bc)? The model being as one with QM in this respect?

It seems to me that these considerations will eventually move us to enquire: Is the model truly local and realistic?

That is: Local and realistic in line with Einstein's ideas and expectations? Me believing that he was not happy with the EPR elements of reality (too naive, imho), me understanding that he makes no mention of them in his work?
 
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  • #92
JenniT said:
A reference orientation is any pre-agreed orientation of a detector in a Bell-test experiment, the experimenters (Alice and Bob) having here pre-agreed to three such orientations. (Thank you.)

The conditioning space in P(X|C) is C; as usual. And, as usual, the boundary conditions on the experiment are implied. So, as I believe is customary, only special conditions are included specifically.
Yes, that's how conditional probability normally works, you don't include conditions which are present in all trials (like facts about the experimental setup which don't change), you only include conditions which can vary from one trial to another. But then I don't understand why you write:
JenniT said:
Since P(ab++|ab) differs from P(ab++|c), the model includes both.
P(ab++|ab) means we are looking at only the subset of trials where Alice chose angle "a" and Bob chose angle "b", correct? But then what does P(ab++|c) mean? If c is supposed to be the "reference orientation", you just said the "reference orientation" was "pre-agreed", so it shouldn't change from one trial to another. Does c here not represent the choice of which orientation to call the "reference orientation" but rather the actual detector setting chosen by Alice or Bob on a trial? If so, who chose c, Alice or Bob? Or both? You really need to explain your notation more when it departs from the standard notation.
JenniT said:
P(ab++|ab) is the probability of ab++ when correlated across the angle ab.
"correlated across angle ab" is an odd way of phrasing it, do you mean the same thing as I meant, i.e. the probability they both get result "+" in the subset of trials where Alice chose to set her SG device at the orientation "a" and Bob chose to set his SG device at the orientation "b"?
JenniT said:
P(ab++|c) arises from the use of frames of reference in the model, as in my reply to vanesch.
There is no need to consider multiple "frames of reference", we can just use a single physical standard for labeling the three possible orientations, as I said in this comment:
In a Bell test experiment, the experimenters have pre-agreed on only three possible orientations for the Stern-Gerlach devices or polarizers--imagine that there's a clock face on the wall in front of the SG device used by one of the experimenters, and that experimenter must arrange his device so that the North end of the North-South axis of his device is either pointing in the same direction as 12 o'clock, 2 o'clock, or 4 o'clock, no other orientations are permitted (meanwhile the other experimenter is only allowed to pick orientations which would match up with the same readings in a mirror image of the first experimenter's clock)
JenniT said:
I'll address this when I revise; in that I will be removing the Bell-test objection that you raise with regard to multiple tests.

I honestly expected no resistance to ADDITIONAL tests, over all 3 reference orientations.
I have no idea what you mean by "over all 3 reference orientations", is this something to do with your bizarre notions about "bi-angles" and multiple "coordinate systems"? You seem to want to play a weird shell game where you try to "win" by using different labels for the same physical orientations on different trials, but surely you understand that a mere re-labeling is not going to change the actual results of any physical experiment. Why not accept the standard practice in physics of using a single scheme for labeling angles of physical objects, rather than developing some completely weird and idiosyncratic labeling scheme that makes everything far more complicated for no apparent reason?
JenniT said:
JesseM said:
Where are equations (A0a) - (A0c)? If they're in the PDF, what page?
Page 7; it's safe; no tigers lurking.
OK, as noted above I don't know what terms like P(ab++|a) even mean, and if it's something to do with changing how you label angles from one trial to another, I don't really want to know. Unless you are making the totally crackpot argument that proving Bell wrong requires this sort of relabeling (in which case I really have no interest in trying to reason with you), please just adopt the standard practice of picking a single way to label angles and sticking with it through all trials. Note that I already asked you to do this in two separate posts...in post #25 I said:
Look, if you want to talk about angles there's no need for some convoluted notion of defining them relative to one another and picking one as a "reference angle", just do what is always done when talking about angles in physics, and define them relative to some fixed coordinate system! You could have a long straight rod stretching from one experimenter to the other whose position never changes and which is taken to define the x-axis of your coordinate system, and then the angle of the polarizer could just be defined as the angle relative to the rod, and then if you started the polarizer out parallel to the rod you could just see how many degrees you have to rotate it counterclockwise before it reaches the desired orientation, and call that the "angle" of the desired orientation. In this case every orientation would have a well defined angle, like a=70, b=30 and c=10, and then a difference between two angles like ac could just be defined as one minus the other, so ac=a-c while ca=c-a and so forth. In this case it's clear that ac=ab+bc is true since (a-c)=(a-b)+(b-c), while ac=ab-bc is false since (a-c)=(a-b)-(b-c)=a-2b+c which doesn't work. Given my example angles above you can see that ac=70-10=60, ab=70-30=40, and bc=30-10=20, so clearly ac=ab+bc does work since 60=40+20, but ac=ab-bc doesn't since 60 is not equal to 40-20.

I really hope your entire argument doesn't reduce to an incoherent notation for labeling angles...if not, then please just phrase your argument in terms of the standard type of coordinate-based angular notation I describe above.
And in post #29 I said:
I would like you to use the standard type of notation for angles, where individual angles are defined relative to some fixed coordinate angles and differences between two angles are defined in some fixed way, like ab=a-b. If you think the terminology of "bi-angles" still makes sense in this context, then please explain clearly what you mean, hopefully using a numerical example where we have definite angles for a,b,c and can thus calculate any angles like ab and ac.

...

Your notion of "focusing" on 2 angles or "reference angles" are similarly incomprehensible to me, I'm just talking about angles in the standard way that physicists always talk about angles, defining them relative to some fixed coordinate system, see post #25. As I requested there, I would like you to start using this sort of standard definition of angles as well, if your argument really revolves around saying there is something fundamentally flawed about defining angles relative to a fixed coordinate system and that we must use your incomprehensible alternative definitions, then your argument really is hopelessly crackpot and I am not interested in continuing.
Will you agree to this, and not refer me to any arguments or equations involving changing definitions of which orientation is at an angle of 0 and what the angles of the other two orientations are?
JenniT said:
PDF2 was written to correct the hurried mess that was the first PDF, with its short-cuts; including short-cutting the conditioning space on any P; noting that all P are conditional to me, in that some conditions are inevitably implied or explicit. So, with apologies, PDF2 now spells out every calculation. Which will bring you to those darned angles.
PDF2 involves a lot of incomprehensible notation and terminology such as "bi-angles" and "P(ab++|c)". In your reply to me, assuming we are using a fixed coordinate system where the angles assigned to each orientation are a=240,b=120,c=0, can you please show what values you would calculate for P3, P4 and P(ab++|ab) given these angles?
JenniT said:
I thought that, when the L*R tests are conducted over every Bell-test detector setting (as they are; see Tables A1-A3), all we would have (and agree upon) is a more complete set of Bell-tests. I did not expect an objection to MORE tests; any component of which is a component of a Bell-test.
This is all totally incomprehensible to me, as I did not object to "more tests", I objected to the notion (which seemed implicit in your "bi-angles" terminology and in Fig. 1) that in a single series of trials the physical meaning of a given label like "b" might be different on some trials than others (on some it might mean the SG device was aligned with 2 o'clock, on some it might mean it was aligned with 10 o'clock...again, that's what Fig. 1 seems to show). Bell inequalities are only meant to apply to a series of trials where the experimenters were picking between a set of three physical orientations which are labeled in a consistent way, of course you could first do a series of trials #1 where the orientations were a=240,b=120,c=0 and a series of trials #2 where the orientations were a=30,b=20,c=0, but each series would have a separate Bell inequality it would be expected to satisfy under local realism, Bell wouldn't say that local realism demands that when you combine the data from both series that the combined dataset must still satisfy a Bell inequality.
JenniT said:
So, for me, the question remains: Given that Table 2, PDF2, will remain unchanged, and since it applies to any Bell-test that you might nominate, how will a Bell Inequality be constructed?
Table 2 simply gives the standard QM probabilities, what I don't believe is that you can derive Table 2 from any table like Table 1 that gives specific values for P1-P8 and is thus compatible with local realism. If you disagree, please address my specific example of a=240,b=120,c=0, and tell me what values you would get for P3 and P4 given these angles. From Table 1 it seems you should get P3=0.9375/6=0.15625 and P4=0.15625, so that if P(ab++|ab)=P3+P4 this would imply P(ab++|ab)=0.15625 + 0.15625 = 0.3125, but Table 2 says that P(ab++|ab)=Sab/2 which for these angles is equal to 0.375.
JenniT said:
To take a common example: How will P(ab++|ab) be yoked to P(ac++|ac) and P(bc++|bc)? The model being as one with QM in this respect?
Um, the whole point of the argument is that none of us believe you can come up with a local realist model that gives probabilities for P1-P8 which is "as one with QM". Do you really not understand the really really basic point that all Bell inequalities are supposed to be claims about what must be true under local realism, not about what is predicted by the QM probabilities?
JenniT said:
It seems to me that these considerations will eventually move us to enquire: Is the model truly local and realistic?

That is: Local and realistic in line with Einstein's ideas and expectations? Me believing that he was not happy with the EPR elements of reality (too naive, imho), me understanding that he makes no mention of them in his work?
I have my doubts that you understand either "the EPR elements of reality" or the standard notion of "local realism"--perhaps you could explain what aspects you find "naive" so we could see if you are addressing what these ideas actually mean or just some strawman version.
 
  • #93
JesseM said:
I have my doubts that you understand either "the EPR elements of reality" or the standard notion of "local realism"--perhaps you could explain what aspects you find "naive" so we could see if you are addressing what these ideas actually mean or just some strawman version.

Excuse me for chopping up you last post here. All points will be answered. I just want to separate out some non-mathematical issues first.

I call "naive" any local realism that does not allow that a measurement may perturb the measured system. My view makes me wary of the way some interpret the EPR paper; i.e., when they conclude that if particle 1 is measured to be spin-UP, then particle 2 is spin-UP prior to its measurement. (In my view, a measurement of one reveals an equivalence class for the other -- which is quite a different statement -- and one which I trust will not side-track us here from moving to a focus on my maths.)

By "locality", I follow Einstein (1949): " ... the real factual situation of the system S2 is independent of what is done with system S1, which is spatially separated from the former."

With "realism", I follow Clauser and Shimony (1978): "Realism is a philosophical view, according to which external reality is assumed to exist and have definite properties, whether or not they are observed by someone." This means that I talk about trajectories and total angular momenta before they are measured.

Does this remove your concern in this area?
 
  • #94
JenniT said:
Excuse me for chopping up you last post here. All points will be answered. I just want to separate out some non-mathematical issues first.

I call "naive" any local realism that does not allow that a measurement may perturb the measured system. My view makes me wary of the way some interpret the EPR paper; i.e., when they conclude that if particle 1 is measured to be spin-UP, then particle 2 is spin-UP prior to its measurement. (In my view, a measurement of one reveals an equivalence class for the other -- which is quite a different statement -- and one which I trust will not side-track us here from moving to a focus on my maths.)
I agree with you, there's no need to take this "naive" view that measurements are simply revealing properties of the particle that were exactly the same before measurement. I haven't looked at the EPR paper lately so I can't say for sure that they avoid this naive view, but from my reading of Bell's own work I'm confident that his version of local realism did not take such a naive view. In post #20 I gave my summary of how I understand "local realism", which I think matches Bell's conception:

1. The complete set of physical facts about any region of spacetime can be broken down into a set of local facts about the value of variables at each point in that regions (like the value of the electric and magnetic field vectors at each point in classical electromagnetism)

2. The local facts about any given point P in spacetime are only causally influenced by facts about points in the past light cone of P, meaning if you already know the complete information about all points in some spacelike cross-section of the past light cone, additional knowledge about points at a spacelike separation from P cannot alter your prediction about what happens at P itself (your prediction may be a probabilistic one if the laws of physics are non-deterministic).

Then in post #83 I offered the following clarification to ThomasT about the meaning of 1):
Keep in mind that 1) doesn't forbid you from talking about "facts" that involve an extended region of spacetime, it just says that these facts must be possible to deduce as a function of all the local facts in that region. For example, in classical electromagnetism we can talk about the magnetic flux through an extended 2D surface of arbitrary size, this is not itself a local quantity, but the total flux is simply a function of all the local magnetic vectors at each point on the surface, that's the sort of thing I meant when I said in 1) that all physical facts "can be broken down into a set of local facts". Similarly in certain Bell inequalities one considers the expectation values for the product of the two results (each one represented as either +1 or -1), obviously this product is not itself a local fact, but it's a trivial function of the two local facts about the result each experimenter got.
The "local facts" referred to in 1) might or might not be facts about the values of measurable quantities like position and spin, there is no requirement that they correspond in any such direct way to measurable quantities (and if they do, there is certainly no requirement that the value of this quantity at a point on the particle's worldline immediately before measurement is the same as its value at a point immediately after measurement). All that's required in my clarification to ThomasT is that a fact about a measurement performed in some finite region of spacetime, like "we measured the particle and got result spin-up", would be in principle deducible from the complete set of all local facts about points in spacetime within that finite region, there should be no "irreducibly nonlocal" facts in the universe which cannot even in principle be deduced from the complete set of local facts.
JenniT said:
By "locality", I follow Einstein (1949): " ... the real factual situation of the system S2 is independent of what is done with system S1, which is spatially separated from the former."
And would you agree that the "real factual situation" cannot be "irreducibly nonlocal" as I defined it above? That whatever the "real factual situation" about some well-defined region of spacetime, it must ultimately boil down to a collection of real factual situations about each point in spacetime within that region?

Also, Einstein's statement requires some clarification, it's not just that they are "spatially separated" in the ordinary sense of being at different positions in space, but that we are talking about two regions of spacetime with a spacelike separation, so that we are not talking about the factual situation about one system in a region of spacetime that's in the past light cone of the region of spacetime of the other system. After all, if S1 was in the past light cone of S2 then facts about S1 could have a causal influence on facts about S2, so they wouldn't necessarily be statistically "independent". That's why I defined point 2) in terms of light cones above.
JenniT said:
With "realism", I follow Clauser and Shimony (1978): "Realism is a philosophical view, according to which external reality is assumed to exist and have definite properties, whether or not they are observed by someone." This means that I talk about trajectories and total angular momenta before they are measured.
As long as you agree with the above point that this external reality can in principle be boiled down to a collection of local facts about each point in spacetime, and the other point that there must be a spacelike separation between two sets of local facts for them to be considered truly independent, then I think your definition shouldn't be any different from mine above. But please tell me if you have any objections to (or questions about) my definition of local realism (which I'm pretty sure matches up with Bell's notion), if you think there's any way in which it differs from your own.
 
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  • #95
JesseM said:
I agree with you, there's no need to take this "naive" view that measurements are simply revealing properties of the particle that were exactly the same before measurement. I haven't looked at the EPR paper lately so I can't say for sure that they avoid this naive view, but from my reading of Bell's own work I'm confident that his version of local realism did not take such a naive view. In post #20 I gave my summary of how I understand "local realism", which I think matches Bell's conception:

1. The complete set of physical facts about any region of spacetime can be broken down into a set of local facts about the value of variables at each point in that regions (like the value of the electric and magnetic field vectors at each point in classical electromagnetism)

2. The local facts about any given point P in spacetime are only causally influenced by facts about points in the past light cone of P, meaning if you already know the complete information about all points in some spacelike cross-section of the past light cone, additional knowledge about points at a spacelike separation from P cannot alter your prediction about what happens at P itself (your prediction may be a probabilistic one if the laws of physics are non-deterministic).

Then in post #83 I offered the following clarification to ThomasT about the meaning of 1):

The "local facts" referred to in 1) might or might not be facts about the values of measurable quantities like position and spin, there is no requirement that they correspond in any such direct way to measurable quantities (and if they do, there is certainly no requirement that the value of this quantity at a point on the particle's worldline immediately before measurement is the same as its value at a point immediately after measurement). All that's required in my clarification to ThomasT is that a fact about a measurement performed in some finite region of spacetime, like "we measured the particle and got result spin-up", would be in principle deducible from the complete set of all local facts about points in spacetime within that finite region, there should be no "irreducibly nonlocal" facts in the universe which cannot even in principle be deduced from the complete set of local facts.

And would you agree that the "real factual situation" cannot be "irreducibly nonlocal" as I defined it above? That whatever the "real factual situation" about some well-defined region of spacetime, it must ultimately boil down to a collection of real factual situations about each point in spacetime within that region?

Also, Einstein's statement requires some clarification, it's not just that they are "spatially separated" in the ordinary sense of being at different positions in space, but that we are talking about two regions of spacetime with a spacelike separation, so that we are not talking about the factual situation about one system in a region of spacetime that's in the past light cone of the region of spacetime of the other system. After all, if S1 was in the past light cone of S2 then facts about S1 could have a causal influence on facts about S2, so they wouldn't necessarily be statistically "independent". That's why I defined point 2) in terms of light cones above.

As long as you agree with the above point that this external reality can in principle be boiled down to a collection of local facts about each point in spacetime, and the other point that there must be a spacelike separation between two sets of local facts for them to be considered truly independent, then I think your definition shouldn't be any different from mine above. But please tell me if you have any objections to (or questions about) my definition of local realism (which I'm pretty sure matches up with Bell's notion), if you think there's any way in which it differs from your own.

Jesse, this is fantastic stuff for me, and I want to do all that I can to keep it coming -- hopefully to the point of a full consensus between us. And I continue to marvel at your "fluency" (efficiency) across various threads. (I need to lift my game in that area.)

But here's my problem: I neatly began to "itemize" your prior post, to begin developing the clearest possible answers (having nothing to hide, and keen to learn). Then BANG, another set of "itemizations" required, and I haven't finished with the first post!

NOW, that's my problem, so please do not change your style. Keep pumping the info and questions out; and chase me up on any point not clear or missed.

I just want to be clear why I will sometimes appear to be guarded in my answers; why I may appear to be over-cautious in some replies: I want to reassure you that my ideas are grounded in a great deal of good sense, so that that you will move ahead with more facts and probing questions.

I will cover them all, as the thread progresses. And, for me, seeing the consequences that might be (improperly) associated with some of my early answers, I can clarify such points as I go.

SO, to the point, on your latest post:

I cannot immediately see where we disagree; or might disagree.

I certainly accept that added "space-like" requirement without question. And if I'd found an old paper of mine (as I now have), I would simply have cut and pasted this (re photons, hence the nu):

"That is, following Einstein: The real factual situation of a system v [nu] is independent of what is done to system v' that is space-like separated from it," (Einstein 1949).

My immediate question relates to this: there should be no "irreducibly nonlocal" facts in the universe which cannot even in principle be deduced from the complete set of local facts.

It is not an impediment to any analysis of my model, but it seems to me that it could be worded more clearly? Could you put it another way? Some clarifying punctuation, maybe?

Many thanks, as always; and henceforth to be understood.
 
  • #96
THIS IS THE LAST POST BY JenniT

This will be my last post at PF.

As some of you know, from private communications, I am the tentative alter ego of a keen PF supporter.

That supporter, my boyfriend, struggles with his writing. So I represent his attempt to develop a suitable "social-networking" style of expression and correspondence

That same boyfriend (it's our 4th anniversary on April 9) has proposed that we live together. And I've accepted.

We've been allocating duties, jobs, etc, via coin-tosses (and no funny-business ...) ever since, with these results:

Here's where I won: He moves into my flat next Saturday. I am to have lots of babies. I am to find affordable land in a happy valley by the sea to continue our research into developing heirloom fruit and vegetables that grow like weeds. I am to sort out his research in this area.

Here's where he lost: He is to be the bread-winner. He is to make lots of babies, starting next Saturday. (Yes, truly; we start then!) He, poor boy, is to sort out my messy interests in physics.

In closing: I would like to sincerely thank every PF participant that has contributed to my knowledge and experience and learning here; especially those who might have thought that we were squabbling; or me too cheeky ... sometimes. I apologize for such shortcomings, though I do believe that I learn best when it's fun.

I thank Greg for creating PF, and for his efficient administration. (I have advised him of my departure.)

I thank DrC and ThomasT for their informative inputs, and for their mutual goings-on; me seemingly at odds with them both.

I thank vanesch for sharing his knowledge, and the way he brings mathematics into his answers.

I especially thank JesseM for his patience, diligence and all-round competence and knowledge. He has helped me very much! "One day with a great teacher beats a thousand days studying solo."

I have learned a great deal at PF, and will watch from afar, now and then, with great interest.

Ciao, for now,

XOXOXOXOX

JenniT
 
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  • #97
This is the first post by Gordon Watson.

Symbolically turning over a new leaf, as a reminder to myself, I would like to assure readers of this thread re two things:

1. All questions will be answered in due course.

2. I will certainly acknowledge that penultimate post, should there be such, that sinks the model definitively.

With best regards,

Gordon Watson
 
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  • #98
JesseM said:
The "local facts" referred to in 1) might or might not be facts about the values of measurable quantities like position and spin, there is no requirement that they correspond in any such direct way to measurable quantities (and if they do, there is certainly no requirement that the value of this quantity at a point on the particle's worldline immediately before measurement is the same as its value at a point immediately after measurement). All that's required in my clarification to ThomasT is that a fact about a measurement performed in some finite region of spacetime, like "we measured the particle and got result spin-up", would be in principle deducible from the complete set of all local facts about points in spacetime within that finite region, there should be no "irreducibly nonlocal" facts in the universe which cannot even in principle be deduced from the complete set of local facts.

JesseM said:
And would you agree that the "real factual situation" cannot be "irreducibly nonlocal" as I defined it above? That whatever the "real factual situation" about some well-defined region of spacetime, it must ultimately boil down to a collection of real factual situations about each point in spacetime within that region?

JesseM said:
so, Einstein's statement requires some clarification, it's not just that they are "spatially separated" in the ordinary sense of being at different positions in space, but that we are talking about two regions of spacetime with a spacelike separation, so that we are not talking about the factual situation about one system in a region of spacetime that's in the past light cone of the region of spacetime of the other system. After all, if S1 was in the past light cone of S2 then facts about S1 could have a causal influence on facts about S2, so they wouldn't necessarily be statistically "independent". That's why I defined point 2) in terms of light cones above.

Wrt my current understanding, Bell codifies your 1) via his 'continuous λ', and codifies your 2) via his locality condition.

Regarding 1):

The inclusion of a λ variable is necessary for the realism part of a Local Realistic (LR) model to be clearly evident in the model. That is, if it isn't explicitly realistic in that it includes explicit reference to a local hidden variable (λ), then by what criterion might the model be said to be realistic? I think the answer is that there is no other way to do it than by inclusion of λ. Without λ, then a proposed LR model lacks R. (Unless Gordon Watson is proposing some sort of non-Bell-like R, and can demonstrate why it should be considered R.) And it has therefore failed the first test in determining whether it's an LR model of entanglement.

The reason I said in an earlier post that 1) is not necessary wrt effective modelling of entanglement (whether everything is actually evolving according to local causality or not -- and of course we have no way of ascertaining that) is that we know that λ is irrelevant wrt determining coincidental photon flux. λ determines individual photon flux. A continuous λ allows us to trace the production of a relationship between λa and λb back to the emission process and codifies the assumption that this relationship had a local, common cause (eg., wrt Aspect, two photons are entangled, via conservation of angular momentum, via their emission by the same atom during the same atomic transition).

One hypothesis is that the inclusion of λ in a model of entanglement skews the range of statistical results that will be predicted by such a model independent of whether the evolution of the underlying reality excludes nonlocal transmissions.

But if no λ, then the model isn't LR. And if it includes R, then either L is encoded via R or an additional locality condition is required. Sort of a Catch-22 for LR diehards if the above hypothesis is correct -- since it's untestable.Regarding 2):

The inclusion of a λ variable still doesn't codify the causal independence of S1 and S2. For that we need some sort of locality condition. Bell's reduces to an expression of both causal and simple statistical independence. Hence, we have no way of knowing whether BIs are effectively experimentally violated via one or the other.Regarding Gordon Watson's (GW) proposed LR model:

What I would like to see is a clear exposition and explanation of GW's LR ansatz. If, at that stage, it's ascertained to be nonrealistic, then whether it reproduces qm results is moot, because it wouldn't be an LR model.

That is, I still don't understand exactly how GW's LR model is encoding realism and locality (ie., how it is making your, JesseM's, 1 and 2 explicit).

I also don't understand how realism and locality could be encoded (made clearly explicit) in any way other than the way Bell did it. In more or less recent threads this is what my fiddling with some way to specify the relationship between λa and λb without skewing the range of predictions had to do with.

So, unless GW is able to answer these questions, or demonstrate why a non-Bell-like LR formulation should be considered an LR formulation, then I'm compelled to take Bell's formulation as the archetypal LR model of entanglement -- thus, via Bell's demonstration, ruling out any and all LR models of entanglement.
[Note: The above considerations should make it clear why I think that Bell's theorem doesn't rule out the possibility that nature, including Bell tests and other realizations of quantum entanglement, is evolving locally. The fact that a viable model can be made which causally (via FTL or AAD) relates events in S1 and S2 is meaningless wrt what is actually happening at level(s) underlying instrumental results. Bottom line, we have no way of knowing, and assumptions/inferences of nonlocality aren't reasonable given the current situation in physics.]
 
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  • #99
JesseM said:
Um, the whole point of the argument is that none of us believe you can come up with a local realist model that gives probabilities for P1-P8 which is "as one with QM".

There seems to be a major misunderstanding here. Not about my understanding of current beliefs, but about the next bit, which I'll rephrase as a question:

Q: Does GW really believe that he can come up with a local realist model that gives probabilities for P1-P8 which is "as one with QM"?

A: Yes; as has been shown in PDF2 (Table 1, Table 2, and notes thereto). So, in fact, GW believes that he has (beyond can) already come up with a local realist model that gives probabilities for P1-P8 which is "as one with QM"?

Let me explain: Table 1 is NOT based on QM; it is based solely on local realism of the L*R variety. So it must be interpreted in that context. Table 1 cannot be based on current understandings in QM, because the conditioning space (CS) includes three orientations (a, b, c).

[Aside (which is where my writing too often goes astray): Are you happy to have the space C in P(X|C) called the conditioning space; CS, for short?]

Further, any sum over Table 1 must be (initially, until the sum is reduced), a sum of of Ps with CSs abc. Thus SUM = P(X|abc) + P(Y|abc) + ... .

Since QM tests currently range over only two orientations, these summations cannot be QM results. They are L*R results. The QM results are delivered by reducing the CS to any two orientations.

PDF2: Table 2 gives every possible 2-orientation outcome. Appendix A has everyone worked out in full detail. All agree with QM.

To be clear here: The first Boundary Condition (B/C) on L*R is local realism. The second B/C is that all testable results must accord with QM. If one or both of these B/Cs is not met, the model fails.

PS:

QM can test over two orientations and one angle.

L*R can test over three orientations and two angles -- via a thought-experiment. For that is how L*R was developed.

I trust this might help to remove some of our "Table 1 and 2 and QM-outcome" differences?


JesseM said:
Do you really not understand the really really basic point that all Bell inequalities are supposed to be claims about what must be true under local realism, not about what is predicted by the QM probabilities?

I do understand this point. I am wondering where I appeared to not understand?

The predicted QM probabilities are simply a B/C on the L*R predictions. If they are not "as one", then the model fails.

But look at your second point: "all Bell inequalities are supposed to be claims about what must be true under local realism." Again, where do we differ? They are supposed to be.

They are "supposed to be, and are widely believed to be" claims about what must be true under local realism.

Hence my bringing L*R here to see where it fails. FOR L*R is a local realistic model about what MUST be true about local realism.

And, just as in QM, L*R says Bell's inequalities cannot be constructed from within this local realistic world-view.

Tentative conclusion by GW (which is under test here at PF now): All Bell inequalities are supposed to be claims about what must be true under local realism. BUT L*R is definitely derived from local realism, local realism in its most general form, and Bell inequalities cannot be formulated therein.

Implied conclusions:

1. All Bell inequalities are supposed to be claims about what must be true under local realism, but they are not.

2. All Bell inequalities may (perhaps) be true under a naive form of local realism.

I will be follow-up on these matters, using the PDF2 material and expanded clarifying notes. I know there are many more questions that need to be answered.
 
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  • #100
the P
thomast said:
<snip>

regarding gordon watson's (gw) proposed lr model:

What i would like to see is a clear exposition and explanation of gw's lr ansatz. If, at that stage, it's ascertained to be nonrealistic, then whether it reproduces qm results is moot, because it wouldn't be an lr model.

That is, i still don't understand exactly how gw's lr model is encoding realism and locality (ie., how it is making your, jessem's, 1 and 2 explicit).

<snip>
[Note to Admins: If this expansion on the model is not permissible here, under PF guidelines, I'd be happy to lodge an application for it to go under Independent Research.]

ThomasT,

Does this help? I think it properly gets us to the nitty-gritty, and what I write might help others understand the simplicity beneath L*R. Or locate the defect, which is our goal!

1. In L*R there are no abstract entities; we work with real elements of physical reality, and every relevant element of such must appear in the relevant equations. Such elements include trajectories and angular momenta before any test. In the discussion here, we can proceed by considering test outcomes only. The WHY for our maneuvers needs some discussion of HVs, total-momentum orientations and perturbed trajectories in 3-space, projected onto 2-space.

2. In L*R there are just two types of spin-half particles in the world: Those that would yield + and those that would yield when tested via an appropriate detector oriented a. Same for photons.

3. How come there are only two types? Well, in L*R, any test reveals an equivalence class (EC) to which that particle belongs.

4. So when we select a frame of reference (FoR), say a, we know that there are only two particle types that require consideration at that orientation: Those that will, or did, or could, yield +; those that will, or did, or could, yield at this orientation.

5. Since the pristine-particle orientations are pairwise correlated, but otherwise random, the P(a+|a) from one set of twins to the next is 1/2. BUT, as a consequence of the pair-wise correlations of twins at their creation, if one twin (by test) belongs to a specific EC, the other twin belongs to a related EC, depending on the particlar correlation existing at their creation. In PDF2, the correlations are OPPOSITE. So if one particle EC-qualifies a+, its twin will qualify a–.

6. So here, if you are ready to maintain the discipline enforced by FoRs, you are now ready to derive Tables A1-A3 in PDF2. NB: Your readiness implies that you understand this fact: As you fill up the cells in your blank Table, you are repeatedly answering a question like this:

If this pristine particle would yield a + outcome if tested at a, what is the probability that its pristine twin would yield a + outcome if it were tested at b? And so on. Does this next comment help? Imagine the pristine twins to be stable correlated gyroscopes. We are going to perturb each, independently, via a measurement interaction. We are allowing that the perturbed 3-space orientation-based trajectories of both particles do this: They pass through a on their way to b; or vice versa; or they start between a and b and go their own correlated ways accordingly. In thought-testing many pairs, across many orientations, I know of no evidence that negates this trajectory-centric-view.

7. For the frame of reference selected (and you will be going through a, b, c in turn), the first number to write is 1/2; the Probability, for the outcome you are analyzing, occurring at that orientation. For the next orientation (say b), in this FoR-a Table (A1), you will write Cab if the sign is the same at that for the a frame; or Sab if the signs are different. For these are the related Ps that apply over the relevant trajectories. (We are just using Malus' Law, generalized.)

8. You will do the same for c in the a-FoR Table (A1).

9. Table A1 is now complete. So next do A2, then A3. Table 1 is the average over these 3 Tables. Table 2 (the crucial desideratum) follows, as per detailed equations in Appendix A, if you get lost.

10. Tip: The process is so straight-forward and robotic that I usually derive the results afresh each time that they're required. To get a flying start, copy the tables from PDF2 and blank out the answers only.

HOMEWORK: Since we are only dealing with squared cosines and sines, there is no excuse for not doing this as a way to begin answering the excellent point (imho) that you raise:

Time yourself over the above exercise, please. For this will be helpful info. I'm guessing that it takes maybe two hours max; especially with PDF2 to bail you out.

Please see if you differ from any result given in PDF2. This, of course, does not validate the model completely. There could be two wrongs making a supposed right.

But it will at least show the simplicity involved in L*R. You will have derived every possible QM outcome, in full accord with the QM-approved result. (The method, of course, not yet approved.) You will have followed the discipline which I believe FoRs bring to bear on the subject: Remembering that FoRs provide different accounts of the same phenomena.

So, seems to me like a fair investment for (maybe) two hours work. :smile:

I might even send you a PF subscription, if you find the defect: :redface:

Or you buy a 5-year one when you don't? :smile:
 
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