Is the concept of a perpetual motion machine feasible in the realm of physics?

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The discussion centers on the feasibility of a perpetual motion machine within the frameworks of General Relativity (GR) and Special Relativity (SR). Participants argue that gravitational time dilation affects energy transfer in mechanical systems, specifically gears and levers, which cannot maintain perfect rigidity in a gravitational field. The Ehrenfest paradox is referenced to illustrate the limitations of rigid-body motion in GR. Ultimately, the consensus is that energy loss due to gravitational effects prevents the realization of a perpetual motion machine.

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  • Understanding of General Relativity (GR) and Special Relativity (SR)
  • Familiarity with gravitational time dilation concepts
  • Knowledge of mechanical systems, specifically gears and levers
  • Basic principles of energy conservation in physics
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  • Research the Ehrenfest paradox and its implications in GR
  • Study gravitational time dilation and its effects on energy transfer
  • Explore the mathematical foundations of rigid-body motion in GR
  • Investigate the principles of energy conservation in non-inertial reference frames
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Physicists, mechanical engineers, and students of relativity interested in the theoretical limitations of perpetual motion machines and the implications of gravitational effects on energy systems.

  • #61
There seems to be an assumption in this thread that the downcoming photons are adding energy to the system.They are not.Let me reiterate the points I made earlier:

The total energy of the system remains constant and there are no energy increases when the photons move down or energy decreases when the photons move up.

When photons are gaining energy by blue shifting the system is losing potential energy and when they are losing energy by red shifting the system is gaining potential energy.
 
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  • #62
yuiop said:
As I understand it, SR forbids a material with infinite tensile strength, but you seem to be forming your own conjecture/theorem that GR puts a much lower limit on the hypothetical tensile strength of any possible and maybe as yet undiscovered tensile.
The conjecture which puts a much lower limit on the tensile strength of a material is called the "weak energy condition". Basically it says that the energy density in every frame must be non negative everywhere. Tension in one frame reduces the energy density in other frames, so this places a finite limit on the tension.
 
  • #63
DaleSpam said:
Tone does make a difference to me. Feel free to be less influenced by style than I am in deciding which posts you choose to report or not.

I don't feel bad about reporting your previous thread, and although I didn't report this one I wouldn't have disagreed if someone else did.
If style or tone or tenor is actually the difference, how about giving me a straight answer to the following. Suppose I 'repackage' that closed thread and post it anew, thoroughly cleansed of any trigger words like 'free energy', 'perpetual motion' etc, or assertive statements claiming conservation laws might be under a cloud. Given your participation in this thread, would you move to block me again? Yes or no please, and with a reason.
 
  • #64
Dadface said:
There seems to be an assumption in this thread that the downcoming photons are adding energy to the system.They are not.Let me reiterate the points I made earlier:

The total energy of the system remains constant and there are no energy increases when the photons move down or energy decreases when the photons move up.

When photons are gaining energy by blue shifting the system is losing potential energy and when they are losing energy by red shifting the system is gaining potential energy.

I can see that, but I can't see the net zero gain of the whole system until the whole energy cycle is parsed according to its components. The downward photons are more energetic, and their number is not diminished. The loss of potential energy is not found in basic high-school physics bookkeeping until the potential energy is regained by the arrival of return red-shifted photons.
 
  • #65
Dadface said:
There seems to be an assumption in this thread that the downcoming photons are adding energy to the system.They are not.Let me reiterate the points I made earlier:

The total energy of the system remains constant and there are no energy increases when the photons move down or energy decreases when the photons move up.

When photons are gaining energy by blue shifting the system is losing potential energy and when they are losing energy by red shifting the system is gaining potential energy.

But why? Is it simply because the standard E = mgh doesn't apply because the rest mass of a photon is 0? So that E = mgh always uses rest mass and not relativistic mass?
 
  • #66
Q-reeus said:
how about giving me a straight answer to the following ... would you move to block me again? Yes or no please, and with a reason.
I can't give you a definite reaction to a hypothetical post. But hypothetically if there were nothing objectionable then even if I did the moderators would ignore me.
 
  • #67
DaleSpam said:
I can't give you a definite reaction to a hypothetical post. But hypothetically if there were nothing objectionable then even if I did the moderators would ignore me.
OK let's leave it at that for now then, and maybe see what transpires down the track a bit.
 
  • #68
danR said:
I can see that, but I can't see the net zero gain of the whole system until the whole energy cycle is parsed according to its components. The downward photons are more energetic, and their number is not diminished. The loss of potential energy is not found in basic high-school physics bookkeeping until the potential energy is regained by the arrival of return red-shifted photons.

High school students study energy changes and would know,for example,that when an object is falling freely there is a conversion of PE to KE.The part of the event where the object is falling is analogous to the part of the event described by guss where the photons are moving down.
 
  • #69
guss said:
But why? Is it simply because the standard E = mgh doesn't apply because the rest mass of a photon is 0? So that E = mgh always uses rest mass and not relativistic mass?

For a photon E=hf=mc^2 where m= the effective mass of the photon.
 
  • #70
Dadface said:
High school students study energy changes and would know,for example,that when an object is falling freely there is a conversion of PE to KE.The part of the event where the object is falling is analogous to the part of the event described by guss where the photons are moving down.

In Newtonian physics, the potential energy is hypothetically stored in the gravitational field, but in GR it is not necessarily that simple and as far as I know energy has to be more directly accounted for in GR. In some ways in Newtonian physics, potential energy is a bookeeping exercise to keep the energy balance straight. In GR any energy has a gravitational effect and we have to state where that energy is, AFAIK. As you can probably tell, I am really not sure of the absolute answers here, so maybe some of the more enlightened could shed some light on this.
 
  • #71
danR said:
I can see that, but I can't see the net zero gain of the whole system until the whole energy cycle is parsed according to its components. The downward photons are more energetic, and their number is not diminished. The loss of potential energy is not found in basic high-school physics bookkeeping until the potential energy is regained by the arrival of return red-shifted photons.

How to account for the energy depends on what bookeeping system one is using.

In the Newtonian bookeeping system,a falling physical object is loosing potential energy and gaining kinetic energy. For the photon, it's still loosing potential energy (more or less,it could be argued that we are using a variant of Newtonian theory here, because standard Newtonian theory gets a bit strained in dealing with light. But still, that's the standard Newtonian way of dealing with falling objects, you've got a kinetic energy, and a potential energy, and the sum is the total energy.

In GR, we need another bookeeping system. There are at least three that might apply, but I'm only familiar enough with one of them to tell you how it "keeps the books".

The three that could apply are the ADM system, which keeps tract of the ADM energy, the Bondi system, which keeps tract of the Bondi energy, and the Komar system, which keeps tract of the Komar energy. These are all different definitions of "Energy", but unfortunately energy isn't the simple thing it is in GR as it is in Newtonian physics. This may be confusing, but it is what it is, I can only try to mention it to people, and perhaps to point them at references (which are usually over their heads, though there are a few good popularizations out there like the sci.physics.faq on energy in GR). But I digress.

It's common to use the names Bondi, ADM, and Komar energy, but it's not particularly common to call it a "bookeeping system", that's more or less an analogy I'm making to make the idea understandable.

OK - I've wandered a bit, let's get back on track. How do we handle energy in the Komar sense? Well, we don't really have a direct concept of "potential energy", but what we do instead is very similar. We CAN express the energy in this system as in integral of the energy density (though interestingly enough the integral isn't often unique), and what we do is to say that energy deep in a gravity well, counts for less towards the total energy of the system.

This is rather similar to what we'd say if we had a concept of "potential energy", but we don't. Mainly because there isn't any sort of tensor field we can think of which could store said energy, and people have for the most part realized that non-tensor approaches towards "fields" aren't really physical.

The factor by which it counts less can be thought of as the local time dilation factor, as long as you use coordinates that respect the underlying symmetry of the problem. A coordinate-independent description is possible, but it tends to confuse people, alas, and we've already had a few complaints on the thread that it was getting too technical. So I'll avoid mentioning it unless there's some specific interest, people who need to know can probably take a good guess at this point (or maybe not, in which case they'll have to ask and the people who get confused with it will have to live with it, I guess).

So, there you have it. The blue shifted photon , in some local sense, has more energy than the redshifted photon. But when you add it's energy to "the books", for accountng purposes you you you say that it contributes less to the book value than it's local value. Another way of saying it is that the "book value" of energy is the energy it would have at infinity.

And that's how you account for energy in the Komar system. More or less, I've been deliberately rather informal for the purposes of trying to explain it in terms that most people will be able to understand. Probably the biggest and most dangerous oversimplification that I've made is to assume that you can account for energy in terms of adding up piecies (i.e. via some integral) at all. It's usually possible to do this, and it's familiar, but it's not necessarily a unique process in GR.

[add]The other thing I've oversimplified, because it doesn't really contribute to the problem at hand, is the notion of how pressure affects the bookeeping.

I wish I had a better understanding of the ADM and Bondi systems to provide a similar explanation - or perhaps even to say that a similar explanation doesn't exist - but at t his point, I don't.

I will point out that arguing over the energy as it's defined in Newtonian physics isn't going to get the thread anywhere. Not that it usually stops people from doing it. From my viewpoint,though, if you want to understand how GR deals with energy, you actually have to try to lean how it deals with it. It's NOT necessarily the same way that Newtonian theory does it, and you might have to make a few mental adjustments. If you don't really have the background for it, it might be better to wait until you do if you want really detailed information and understanding without any errors. If you don't or can't, you'll have to make do with popularizations such as posts like this and the sci.physics.faq, which may get you pointed more or less in the right direction, but might be missing a few points that later turn out to be important to your understanding.
 
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  • #72
Dadface said:
High school students study energy changes and would know,for example,that when an object is falling freely there is a conversion of PE to KE.The part of the event where the object is falling is analogous to the part of the event described by guss where the photons are moving down.

Sure, but the whole machine has to be deconstructed. That's the trick in this post. Otherwise everyone could say: 'violation of conservation; next question...'. There's the physics analogue of the 1=2 algebraic trick that hides an a/0.
 
  • #73
pervect said:
How to account for the energy depends on what bookeeping system one is using.
.
.
.
Probably the biggest and most dangerous oversimplification that I've made is to assume that you can account for energy in terms of adding up piecies (i.e. via some integral) at all. It's usually possible to do this, and it's familiar, but it's not necessarily a unique process in GR.

[add]The other thing I've oversimplified, because it doesn't really contribute to the problem at hand, is the notion of how pressure affects the bookeeping.

I wish I had a better understanding of the ADM and Bondi systems to provide a similar explanation - or perhaps even to say that a similar explanation doesn't exist - but at t his point, I don't.

I will point out that arguing over the energy as it's defined in Newtonian physics isn't going to get the thread anywhere. Not that it usually stops people from doing it. From my viewpoint,though, if you want to understand how GR deals with energy, you actually have to try to lean how it deals with it. It's NOT necessarily the same way that Newtonian theory does it, and you might have to make a few mental adjustments. If you don't really have the background for it, it might be better to wait until you do if you want really detailed information and understanding without any errors. If you don't or can't, you'll have to make do with popularizations such as posts like this and the sci.physics.faq, which may get you pointed more or less in the right direction, but might be missing a few points that later turn out to be important to your understanding.

I have no complaints about discussions getting 'too' technical, though I often point out the fact. But I have to come to some simple deconstruction of the machine's down and up energy path that makes to sense to me, though it may be off.
 
  • #74
danR said:
Otherwise everyone could say: 'violation of conservation; next question...'.
Everyone can say exactly that. That is the whole point of finding general conservation laws.
 
  • #75
DaleSpam said:
Everyone can say exactly that. That is the whole point of finding general conservation laws.

Richard Feynman would not have been satisfied with answering guss' problem so summarily, however.

He would might have said something like 'conservation of energy', yes, and then tear down the whole machine and say: 'There's your problem right there, lady...'

Edit: To give another example, the plane on the conveyor belt 'conundrum' is nothing more than a F=ma illustration all dressed up. But I went through misery answering this thing in Yahoo answers, and then along comes a guy with years in aviation, explaining that the plane will not take off, in exasperating detail, and wouldn't you know, he gets the 'best answer' award.

If I just said 'therefore a=F/m, so the plane will go forward, the wheels and belt have nothing to do with anything. But no, I had go ahead and explain the whole thing (as did others).

'love's labour lost'
 
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  • #76
danR said:
Richard Feynman would not have been satisfied with answering guss' problem so summarily, however.

He would might have said something like 'conservation of energy', yes, and then tear down the whole machine and say: 'There's your problem right there, lady...'
Which is what we did here.

In any case, Feynman is not on PF so you may have to settle for our inferior efforts instead. It is always possible to come up with a scenario so complicated that your audience cannot analyze it (even Feynman).

Since the conservation principles follow directly from the laws then the details of a given machine are irrelevant. As long as it follows the laws it must also follow the conservation principles. At some point you need to stop conjecturing more complicated machines and actually learn the derivation of the conservation law. But again, that is not what was done here.
 
  • #77
<<To start, light doesn't accelerate. c is fixed>>

Not correct. In Spoecial Relativity the speed of light is c, but not in general in General Relativity.

Pretty much every day I visit this board I see this mistake being made.
 
  • #78
ApplePion said:
<<To start, light doesn't accelerate. c is fixed>>

Not correct. In Spoecial Relativity the speed of light is c, but not in general in General Relativity.

Pretty much every day I visit this board I see this mistake being made.

Gosh, I really hope this "mistake" is made in every post in PF! :smile:
 
  • #79
DaleSpam said:
Which is what we did here.

In any case, Feynman is not on PF so you may have to settle for our inferior efforts instead. It is always possible to come up with a scenario so complicated that your audience cannot analyze it (even Feynman).

Since the conservation principles follow directly from the laws then the details of a given machine are irrelevant. As long as it follows the laws it must also follow the conservation principles. At some point you need to stop conjecturing more complicated machines and actually learn the derivation of the conservation law. But again, that is not what was done here.
I think this was a very straightforward problem. I wanted to dissect and understand exactly why the energy was being lost. Some people got very technical about it, and that's fine.

Also, I'm still a little confused. Wasn't the general consensus that the gears were losing energy due to time dilation? And now the consensus is that the light does not gain energy? So now we have a net energy loss in the system, which doesn't make sense. So one of those consensuses is wrong.
ApplePion said:
<<To start, light doesn't accelerate. c is fixed>>

Not correct. In Spoecial Relativity the speed of light is c, but not in general in General Relativity.

Pretty much every day I visit this board I see this mistake being made.
If you had read literally the two posts after the first post, you would have seen that this problem was already completely addressed.
 
  • #80
ApplePion said:
<<To start, light doesn't accelerate. c is fixed>>

Not correct. In Spoecial Relativity the speed of light is c, but not in general in General Relativity.
The speed of light is c in inertial coordinates in both SR and GR. The only difference between SR and GR on this point is that SR admits globally inertial coordinate systems while in GR they may be only local.
 
  • #81
Guss - re your #79, may I suggest you re-read #56 again. What applies to the spinning shaft there equally applies to your meshing gear setup. Both rotation speed and force are equally affected as measured *locally* in the gravitational potential. At any given height, power in the descending light beam will be exactly matched by ascending power in the meshing gears. Just a glorified 'conveyer belt' in effect. Both values are *equally* greater at the bottom, and lower at the top. The key is to appreciate power is related to the square of redshift (or blueshift depending on datum point chosen) as *locally* measured. And btw, prior argument to the effect that force impulses have to explained as 'photon exchange' is both missing the issue and just wrong. I'm no expert in solid state physics, but can say that solids are *not* held together by electromagnetic forces only - quantum interactions like Pauli exchange interactions are important. Hence covalent bonds, metallic bonds, as well as ionic bonds ,and in any real solid it is a mixture of these. As long as the gears hold together properly, all that matters is how gravity effects the local measure of things.
 
  • #82
guss said:
Wasn't the general consensus that the gears were losing energy due to time dilation? And now the consensus is that the light does not gain energy?
Consensus is over-rated. I never noticed the second consensus.
 
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  • #83
<<If you had read literally the two posts after the first post, you would have seen that this problem was already completely addressed.>>

I do not think it was. Perhaps you could enlighten me.
 
  • #84
<<The speed of light is c in inertial coordinates in both SR and GR. The only difference between SR and GR on this point is that SR admits globally inertial coordinate systems while in GR they may be only local.>>

This is another common mistake here.

It *would* be c is one *switched* to inertial coordinates, but when one is working in a system one has to use the coordinates of the actual system.

I live in Florida, and while it is possible that I *could* live in Alaska being that I am an American citizen, I do not actually live in Alaska.

One one considers a physics situation one descibes things in a chosen coordinate system. As I'm sure you know you cannot have inertial coordinates everywhere...and thus you do not have inertial coordinates everywhere.
 
  • #85
guss said:
And now the consensus is that the light does not gain energy?

The light gains energy, that is, gravitational energy is converted to electromagnetic energy (classically speaking).
Put otherwise (GR speaking), since the time dilation is increasing, the apparent frequency of the light is increasing too.
 
  • #86
I like Serena said:
The light gains energy, that is, gravitational energy is converted to electromagnetic energy (classically speaking).
Put otherwise (GR speaking), since the time dilation is increasing, the apparent frequency of the light is increasing too.

Well put, in this way the system energy as a whole (light plus gravitational field or) is conserved.
 
  • #87
ApplePion said:
<<The speed of light is c in inertial coordinates in both SR and GR. The only difference between SR and GR on this point is that SR admits globally inertial coordinate systems while in GR they may be only local.>>

This is another common mistake here.

There is nothing mistaken in the Dalespam quote the way it is expressed IMO, maybe you have misinterpreted it.

ApplePion said:
It *would* be c is one *switched* to inertial coordinates, but when one is working in a system one has to use the coordinates of the actual system.
Wich are very close to local inertial coordinates for any measure of c that you may want to perform. C is always measured locally.
ApplePion said:
One one considers a physics situation one descibes things in a chosen coordinate system. As I'm sure you know you cannot have inertial coordinates everywhere...and thus you do not have inertial coordinates everywhere.
This phrasing is confusing, if you mean there is no global inertial coordinates in GR, that is just what Dalespam said. If you mean that you can't have inertial coordinates set up at every point of spacetime, you would be denying normal coordinates and the Equivalence Principle.
 
  • #88
danR said:
Edit: To give another example, the plane on the conveyor belt 'conundrum' is nothing more than a F=ma illustration all dressed up. But I went through misery answering this thing in Yahoo answers, and then along comes a guy with years in aviation, explaining that the plane will not take off, in exasperating detail, and wouldn't you know, he gets the 'best answer' award.

If I just said 'therefore a=F/m, so the plane will go forward, the wheels and belt have nothing to do with anything. But no, I had go ahead and explain the whole thing (as did others).

'love's labour lost'
Would have been easier to have just posted a link to this youtube video of a plane taking off from a conveyor belt. No one was more surprised than the pilot when the plane took off. LOL
 
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  • #89
Going back to the very first post and considering the chain of cogwheels (which as someone said is like a conveyor belt in principle) how fast will the bottom cog be turning according to a local observer at the bottom, if the the top cog is turning at X rpm according to the top observer?

Assume all the cogs are exactly the same size and almost 100% efficiency and the gravitational redshift factor is F.
 
  • #90
yuiop said:
Going back to the very first post and considering the chain of cogwheels (which as someone said is like a conveyor belt in principle) how fast will the bottom cog be turning according to a local observer at the bottom, if the the top cog is turning at X rpm according to the top observer?

Assume all the cogs are exactly the same size and almost 100% efficiency and the gravitational redshift factor is F.
XF (where F is defined as >1) yuiop - we've had a bit of recent practice with that sort of thing on another thread, right?!:smile:
 

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