Finding the inverse of two functions

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To find the inverse of the function y = e^(-x^3), a logical first step is to take the natural logarithm of both sides, leading to x = -ln(y)^(1/3). For the function y = sin(1/x), it is noted that the function is not invertible due to its many-to-one nature, as multiple x-values can yield the same y-value. Specifically, the sine function has infinitely many solutions for y = 0, which complicates finding a unique inverse. In general, to find an inverse, one must solve for x in terms of y and ensure the function is one-to-one over the desired domain. Understanding these steps is essential for successfully determining the inverses of these functions.
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Homework Statement



How do I find the inverse of these functions step by step?

y= e^-x^3

y= sin(1/x)

I know the solutions but I don't know how to work with these two functions. Does anyone know the steps to finding the inverse of these?
 
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The goal is to solve for x in terms of y.

What can you do to both sides of y = e^(-x^3) that would be a logical first step?

For the second function, y = sin(1/x), is there a restriction on the domain? As it's written, this function is not invertible because it's many-to-one. For example, there are infinitely many x for which sin(1/x) = 0, namely x = 1/(n*pi) for any nonzero integer n.
 
Tebow15 said:

Homework Statement



How do I find the inverse of these functions step by step?

y= e^-x^3

y= sin(1/x)

I know the solutions but I don't know how to work with these two functions. Does anyone know the steps to finding the inverse of these?
How do you find the inverse of any function, in general?
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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