Calculate wind load using fluid impulse and momentum.

AI Thread Summary
The discussion focuses on calculating wind load using fluid mechanics principles, specifically impulse and momentum. It explores the feasibility of treating air as an incompressible fluid for wind load calculations, noting that compressibility can be neglected at velocities below 0.3 Mach. The concept of stagnation pressure is introduced as a method to determine force on surfaces from air streams, particularly when wind speed approaches zero against a structure. The conversation also considers the implications of angled surfaces and reflections on wind load calculations. The primary application discussed is estimating wind loads on large microwave antenna dishes on communications towers.
FrankJ777
Messages
140
Reaction score
6
I recently took a crash course that included some topics in fluid mechanics. I learned that you can use the concept of impulse and momentum the calculate the force of fluid, for instance a jet of water on a turbine blade. The equations used are:

ƩFx = ρQ(Vx1-Vx2)
ƩFy = ρQ(Vy1-Vy2)

I realize that as a gas air is compressible, but I was wondering if I could calculate wind loading on a wall using the same concept, but maybe with a factor of compressibility factored in. If I treat air as an incompressible fluid, will I get a wind load that is reasonably close to the actual wind load?

Thanks
 
Physics news on Phys.org
Compressibility can be neglected if the velocity of the gas is less than 0.3 Mach (~100 m/s)

To calculate the force on a flat surface from the impingement of an air stream, the stagnation pressure can be used. Stagnation Pressure = (1/2)rho*velocity^2
 
Would using the stagnation pressure approach only apply where the wind speed goes to zero, like up against a large vertical building? What if the face of the structure isn't normal to the wind, but at some angle that allows it to reflect off at a different direction. Then could one, use the momentum/impulse concepts.

By the way, my interest is estimating the wind loads on large microwave antenna dishes attached to communications towers. The face of the dishes are generally round and covered with a tarp, so i think they should represent uncomplicated structures.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top