Proving Natural Number e: Exponential Value Explained

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The discussion centers on the limit definition of the natural number e, expressed as (1 + 1/n)^n as n approaches infinity. A common misconception arises when substituting n with infinity, leading to the erroneous conclusion that the expression equals 1. The forum participants clarify that this substitution results in an indeterminate form, specifically 1^∞, which does not yield a definitive value. They emphasize that manipulating limits can lead to different results depending on the order of the limits taken, illustrating that limits do not always commute. Ultimately, the correct evaluation of the limit confirms that (1 + 1/n)^n approaches e, not 1, as n approaches infinity.
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For proving the natural number, e.
(1+1/n)^n As n approches infinite, (1+1/n)^n ----> e
However, wouldn't it become one as n becomes infinite?
(1+1/n)^n=(1+0)^n=1
Could anyone explain this to me please!
 
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If you just naively substitute ##n=\infty##, then you would get

(1+0)^\infty = 1^\infty

which is an indeterminate form. Surely, things like ##1^2## and ##1^{100}## equal ##1##. But if the exponent is infinity, then it's an indeterminate form.
 
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(1+\frac{1}{n})^n = 1 + n\frac{1}{n} +\frac{ n(n-1)}{2!} \frac{1}{n^2} + ... \frac{1}{n^n}

This does not ->1 as n becomes infinite.
 
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henrywang said:
For proving the natural number, e.
(1+1/n)^n As n approches infinite, (1+1/n)^n ----> e
However, wouldn't it become one as n becomes infinite?
(1+1/n)^n=(1+0)^n=1
Could anyone explain this to me please!

The manipulation here takes a limit involving one variable and turns it into what amounts to a pair of nested limits involving two variables. The original formula was:

<br /> \displaystyle\lim_{n\rightarrow +\infty} {(1+\frac{1}{n})^n}<br />

The attempted manipulation was to:

<br /> \displaystyle\lim_{{n_1}\rightarrow +\infty} {\displaystyle\lim_{{n_2}\rightarrow +\infty} {(1+\frac{1}{n_2})^{n_1}}}<br />

which is distinct from:

<br /> \displaystyle\lim_{{n_2}\rightarrow +\infty} {\displaystyle\lim_{{n_1}\rightarrow +\infty} {(1+\frac{1}{n_2})^{n_1}}}<br />

Those two nested limits give different results. The first one evaluates to 1. The second one does not exist at all. Limits do not always commute.

One way of seeing this is to imagine the formula {(1+\frac{1}{x})^y} as a function of two variables. It is defined everywhere in the first quadrant of the coordinate plane for x and y. You can imagine extending the definition to infinite x and infinite y by tracing a path going off into the distance and looking at the limit of the function values along that path. It then turns out that the limit you get depends on the path you take.

The prescription in the original formulation was for a path running exactly on the 45° line through the middle of the first quadrant.
 
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