What Is the Derivative of This Gravitational Potential Energy Function?

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The discussion focuses on finding the derivative of the gravitational potential energy function U with respect to 'r'. The function is expressed as U = (-GMeMs)/(r) - (GMmMs)/(R-r), where G is the gravitational constant, Me is Earth's mass, Ms is the spacecraft's mass, and R is the distance between the Earth and the moon. The equation is rewritten for clarity, emphasizing the application of the chain rule for differentiation. The first term's derivative involves multiplying by the exponent and adjusting it, while the second term requires accounting for the derivative of the inner function, which is -1. This approach simplifies the differentiation process for the given gravitational potential energy function.
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Can someone please tell me the derivative of the following with respect to little 'r' where G is the gravitational constant (6.67x10^-11), Me is mass of Earth (5.98X10^24kg), Ms is mass of a spacecraft that has a mass of 1000kg and R which is the distance between the Earth and the moon (384400 x 10^3m). Thanks.

U = (-GMeMs)/(r) - (GMmMs)/(R-r)
 
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dvvz2006 said:
Can someone please tell me the derivative of the following with respect to little 'r' where G is the gravitational constant (6.67x10^-11), Me is mass of Earth (5.98X10^24kg), Ms is mass of a spacecraft that has a mass of 1000kg and R which is the distance between the Earth and the moon (384400 x 10^3m). Thanks.
U = (-GMeMs)/(r) - (GMmMs)/(R-r)

re-write your equation U = (-GMeMs)/(r) - (GMmMs)/(R-r) as:
U = (-GMeMs)(r^-1) - (GMmMs)[(R-r)^-1]
Then it is simply using the chain rule. For the first term: Multiply by the exponent, subtract the exponent by 1 to get the new exponent. Everything else is constant so no need to touch it.

For the 2nd term same thing, except do not forget u also must take the derivative of what is on the inside. Which is -1.
 
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