Calculating Ksp for M2X3: Solubility and Equilibrium Calculation

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The solubility of M2X3 in water at 298K is 4.12 x 10^-4 M, leading to the dissociation equation M2X3 <--> 2M3+ + 3X2-. The molarity of M3+ is calculated as 8.24 x 10^-4 M, while the molarity of X2- is 1.236 x 10^-3 M. The solubility product constant (Ksp) is determined using the formula K_sp = [M3+]^2*[X2-]^3. The final calculated value for Ksp is 1.28 x 10^-15.
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The solubility of M2X3 (as M3+ and X2-) in water at 298K is 4.12 x 10-4 M. Calculate Ksp for M2X3.

M2X3 <--> 2M3+ + 3X2-

K_sp = [M3+]^2*[X2-]^3

Now Molarity of M3+ = (4.12 x 10-4) M2X3*(2 mol M3+/1 mol M2X3) = 8.24E-4 mol = Molarity

Molarity X2- = (4.12 x 10-4) M2X3*(3 mol X2-/1 mol M2X3) = 1.236E-3 mol = molarity

K_sp = [8.24E-4 M]^2*[1.236E-3]^3 = 1.28E-15

Thanks.
 
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