Calculating Tangential Acceleration for Rotating Objects

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To calculate tangential acceleration for a rotating object, one must first determine angular acceleration using the formula α = Δω/Δt, where Δω is the change in angular velocity and Δt is the time interval. For the CD with a diameter of 12 cm, the tangential acceleration can be calculated at 2 rev/s and 3 rev/s by applying the formula a_t = r * α, where r is the radius. In the case of the fishing reel, the linear speed of the fishing line can be found using the formula v = r * ω, converting revolutions per second to radians per second as needed. The discussion emphasizes the importance of showing work and understanding the relationship between angular and tangential acceleration. Clear calculations and conversions are essential for accurate results.
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Can anyone help me with these 2 ?

1.) A cd with a diameter of 12 cm, speeds up from 0 to 4 rev/s in 3s. What is the tangential acceleration of a point on the outer rim of the disk at the moment when angular speed is a.) 2 rev/s b.) 3 rev/s

2.) A fisherman reels in a fish and turns the spool on the reel at a rate of 3 revolutions per second. If the radius of the reel is 3.7 cm, what is the linear speed of the fishing line as it is reeled in ?
 
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remember to get frequency its 1/t, so convert it the rev/s to Hz. I hope I'm correct?
 
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I don't know where to start .. can anyone Help ?
 
A formula for tangental acceleration is;

\alpha = \frac{a_{t}}{r}

where \alpha is angular acceleration and a_{t} is tangental acceleration.

-Hoot
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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