What Is the Minimum Radius Needed to Paint on a Cube to Contain Light?

AI Thread Summary
To prevent light from escaping a glass cube with a side length of 16.0 cm, a circle must be painted on each face. The minimum radius of the circle is determined by the principles of total internal reflection, which dictate how light behaves at the interface of different media. The calculations involve the geometry of the cube and the angles of incidence and reflection. Without specific calculations provided, it's essential to apply the relevant formulas from optics to find the exact radius needed. Understanding these principles is crucial for effectively containing light within the cube.
firyace
Messages
8
Reaction score
0
Lets say you got a glass cube and a small light source embedded at the exact center of the glass cube.
Now if you want to paint a circle on each face of the cube so that the light is prevented from leaving the cube, what is the minimum radius of the circle that you need to paint?

Let say each of the sides of the cube is 16.0cm.

Thanks!
 
Physics news on Phys.org
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top