What is the speed of the second ball after the collision?

Thread starter Luvs_Mariah_C
Start date Feb 9, 2004
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Ball Collision Speed

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In an elastic collision involving two equal mass billiard balls, the first ball traveling at 4.0 m/s comes to a complete stop after the collision. The second ball, initially at rest, will then move with the same speed as the first ball before the collision, which is 4.0 m/s. The relevant equation to use for this scenario is the conservation of momentum, specifically p_initial = p_final. This principle states that the total momentum before the collision equals the total momentum after the collision. Understanding this concept is crucial for calculating the speed of the second ball independently.

Feb 9, 2004

Luvs_Mariah_C

A billiard ball traveling at 4.0 m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at rest. The first ball is at rest after the collision. What is the speed of the second ball after the collision?

What equation should i use? Please post.

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Feb 9, 2004

Integral

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See this thread

Feb 9, 2004

Luvs_Mariah_C

Thanks...but

That shows me the anser, I'm looking for the equation to find the answer myself. Thank you anyways.

Feb 9, 2004

Integral

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Look again.

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