Locus of Q in Coordinate Geometry: Find the Answer

AI Thread Summary
The discussion revolves around finding the locus of point Q, which moves such that the length of the tangent from Q to the given circle equals its distance from the origin. Initial attempts to solve the problem involved complex methods, including calculating the tangent's gradient and using perpendicular distances. However, it was later revealed that the locus of Q simplifies to the linear equation 4x + 8y + 9 = 0. Participants suggest starting with a visual representation of the circle, plotting point Q, and analyzing the distances to clarify the problem. Ultimately, the solution emphasizes that the locus is indeed linear, contrary to initial assumptions of a more complicated curve.
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The points Q moves such that the length of the tangent from Q to the circle
x^2+y^2+4x+8y+9=0 is equal to the distance of Q from the origin ). Determine the locus of Q.

I am basically clueless about this question...but I will try to provide as many work I have done on this question.

I assume that we are required to find the locus of point Q. I reckon that locus of Q is a curve, since the word tangent is only suitable for curves. Hence, I will have to find the gradient of the tangent of the curve in order to solve for the tangent equation, then finding the perpendicular distance of the tangent to the circle, and equate it to the distance from Q to the origin.

But I found that the above methods seems overcomplicated and not likely to be the solution. I check the answer, but to my surprise, the locus of Q is a linear equation 4x+8y+9=0. Is the answer wrong? And how should I approach this question?
 
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Best way is to start with a picture. Work out the centre and radius of the circle, sketch it on a set of axes. Plot an arbitrary point Q. Draw the tangent from Q to the circle. Join Q to the origin. Work out the distances required and equate them.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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