Final Velocity of Falling Paint Can

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The discussion centers on calculating the final velocity of a falling paint can dropped from scaffolding. The painter nudges the can while ascending, and it falls a distance of H1, taking time T to reach the ground. The correct approach involves using the first equation to find the initial velocity (Viy) and then applying the second equation to determine the final velocity (Vy). The calculated final velocity should be positive, reflecting speed, despite the downward direction of the fall. The key takeaway is to ensure proper sign usage in calculations, as the final answer should represent speed rather than velocity.
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Homework Statement



A painter is standing on scaffolding that is raised at constant speed. As he travels upward, he accidentally nudges a paint can off the scaffolding and it falls a distance [H1] to the ground. You are watching, and measure with your stopwatch that it takes a time of [T] for the can to reach the ground. Ignore air resistance. What is the speed of the can just before it hits the ground (final velocity)?

Homework Equations



y = Yi + ViyT + 1/2 (AyT^2)

Vy = Viy + AyT

Vy^2 = Viy^2 + 2A(Y-Yi)

The Attempt at a Solution



Ive done this problem with each of the given equations and none seem to work. I was given sample values for H1 = 15 meters and T = 3.25
The answer is suppose to be 20.5 m/s but I've plugged in these numbers a hundred times and gotten several different answers.
Can someone please tell me what equation to use and how to arrive at 20.5 m/s for final velocity? Thanks
 
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You need to use your first equation for y to find Viy. Then use the second equation to find Vy. Keep all of the signs straight.
 
The scaffolding is going up, thus Viy is nonzero. You should be able to figure Viy as you're given T (and H1).

EDIT: I'm too slow.
 
Dick said:
You need to use your first equation for y to find Viy. Then use the second equation to find Vy. Keep all of the signs straight.

and

Päällikkö said:
The scaffolding is going up, thus Viy is nonzero. You should be able to figure Viy as you're given T (and H1).

EDIT: I'm too slow.

Thank you so much for this insight. I am going to try it right now

First equation
-15 = 0 + Viy(3.25) +(1/2)(-9.8)(3.25)^2

Viy = 5881/520

Second equation
(5881/520) + (-9.8)(3.25) = Vy = -20.5

Whohoo! the number is correct but it looks like I messed up somewhere with the signs because it should be positive. Hrm... any ideas?
 
The paint can IS going down when it hits, right? Wouldn't that be a negative velocity in your coordinates? Besides, the question asks for 'speed'.
 
Last edited:
Dick said:
The paint can IS going down when it hits, right? Wouldn't that be a negative velocity in your coordinates? Besides, the question asks for 'speed'.

:!) :smile: :cry:

Thanks!
 
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