Finding A and L in Parametric Equation X(t)

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Homework Statement


The equation X(t)=A+tL is the parametric equation of a line through the point P:(2,-3,1). The parameter t represents distance from point P, directed so that the I component of L is positive. We know that the line is orthogonal to the plane with the equation 4x-6y+5z=6. Then solve for A and L in vector component form.


Homework Equations



Standard Vector Calculus equations.

The Attempt at a Solution



My problem here is simply understanding what the problem is saying. The t term is throwing me off. Hopefully some of you could shed some light on this.
 
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t is a number - like x in the 2d straight line equation y=m*x+b. L is analogous to the slope m. So as t runs from -infinity to infinity X(t) runs through a curve of points. That curve is a straight line.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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